1. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Main AR Standards

2. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu AR STANDARDS for ch. 10-11

3. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Table of Contents Chapter 11 Gases Section 1 Gases and Pressure

4. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Objectives Define pressure, give units of pressure, and describe how pressure is measured. State the standard conditions of temperature and pressure and convert units of pressure. Use Dalton’s law of partial pressures to calculate partial pressures and total pressures. Section 1 Gases and Pressure Chapter 11

5. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Why Chemistry Matters Videoclip Intro. 4:47 Click below to watch the video http://my.hrw.com/content/hmof/science/high_school_sci/na/gr 9-12/hmd_chem_9780547708089_/dlo/whyitmatters/#p/9

6. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Pressure and Force Pressure (P) is the force per unit area on a surface. Gas pressure is caused by collisions of the gas molecules with each other and with surfaces with which they come into contact. The pressure exerted by a gas depends on volume, temperature, and the number of molecules present. The greater the number of collisions of gas molecules, the higher the pressure will be. Section 1 Gases and Pressure Chapter 11

7. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Visual Concepts Pressure - wait for video to play - while in play mode Chapter 11

8. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Visual Concepts Click below to watch the Visual Concept. Visual Concept Equation for Pressure Chapter 11 http://my.hrw.com/sh/hc6_003036809x/s tudent/ch11/sec01/vc01/hc611_01_v01fs.htm

9. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Pressure and Force The SI unit for force is the newton, (N), the force that will increase the speed of a one-kilogram mass by one meter per second each second that the force is applied. example: consider a person with a mass of 51 kg. At Earth’s surface, gravity has an acceleration of 9.8 m/s 2. The force the person exerts on the ground is therefore 51 kg  9.8 m/s 2 = 500 kg m/s 2 = 500 N Chapter 11 Section 1 Gases and Pressure

10. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Pressure and Force Chapter 11 Section 1 Gases and Pressure Pressure is force per unit area, so the pressure of a 500 N person on an area of the floor that is 325 cm 2 is: 500 N ÷ 325 cm 2 = 1.5 N/cm 2 The greater the force on a given area, the greater the pressure. The smaller the area is on which a given force acts, the greater the pressure.

11. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Relationship Between Pressure, Force, and Area Chapter 11 Section 1 Gases and Pressure

12. 13.1 Fluid Pressure Atmospheric pressure is the sum of the individual pressures of the various gases: 78% nitrogen, 21% oxygen, and 1% other approximately. Why do your ears pop when you change altitude such as climbing a large mountain in a car ? Density is lower and atmospheric pressure lower at higher altitudes. The outside pressure changes more quickly than your ear can adjust which creates a pressure difference in pressure. When unbalanced pressures equalize, popping sensation within a small tube in your ear occurs.

13. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Pressure and Force, continued Measuring Pressure A barometer is a device used to measure atmospheric pressure. The first barometer was introduced by Evangelista Torricelli in the early 1600s. Torricelli noticed that water pumps could raise water only to a maximum height of about 34 feet. He wondered why this was so, and thought the height must depend somehow on the weight of water compared with the weight of air. Chapter 11 Section 1 Gases and Pressure

14. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Chapter 11 Section 1 Gases and Pressure Torricelli reasoned that if the maximum height of a water column depended on its weight, then mercury, which is about 14 times as dense as water, could be raised only about 1/14 as high as water. He tested this idea by sealing a long glass tube at one end and filling it with mercury. Inverting the tube into a dish of mercury, the mercury rose to a height of about 30 in. (760 mm), which is about 1/14 of 34 feet. Pressure and Force, continued Measuring Pressure, continued

15. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Visual Concepts Click below to watch the Visual Concept. Visual Concept Chapter 11 Barometer http://my.hrw.com/sh/hc6_003036809x/student/ ch11/sec01/vc02/hc611_01_v02fs.htm

16. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Manometer A manometer measures pressure of an enclosed gas sample.

17. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Optional Links and Video about barometers & manometers Click on this to learn more about barometers and manometers. (This is an optional video and links that are not required for basic concepts.) Must be in play mode. http://www.kentchemistry.com/links/GasLaws/manBar.htm

18. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu The common unit of pressure is millimeters of mercury, symbolized mm Hg. A pressure of 1 mm Hg is also called 1 torr in honor of Torricelli for his invention of the barometer. Chapter 11 Section 1 Gases and Pressure Pressure and Force, continued Measuring Pressure, continued Pressures can also be measured in units of atmospheres. Because the average atmospheric pressure at sea level at 0°C is 760 mm Hg, one atmosphere of pressure (atm) is defined as being exactly equivalent to 760 mm Hg.

19. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu In SI, pressure is expressed in pascals. One pascal (Pa) is defined as the pressure exerted by a force of one newton (1 N) acting on an area of one square meter. The unit is named for Blaise Pascal, a French mathematician and philosopher who studied pressure during the seventeenth century. One pascal is a very small unit of pressure, so in many cases, it is more convenient to express pressure in kilopascals (kPa). 1 atm is equal to 101.325 kPa. Chapter 11 Section 1 Gases and Pressure Pressure and Force, continued Measuring Pressure, continued

20. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Units of Pressure Chapter 11 Section 1 Gases and Pressure

21. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Pressure and Force, continued Sample Problem A The average atmospheric pressure in Denver, Colorado is 0.830 atm. Express this pressure in a. millimeters of mercury (mm Hg) and b. kilopascals (kPa) Chapter 11 Section 1 Gases and Pressure

22. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Pressure and Force, continued Sample Problem A Solution Given: atmospheric pressure = 0.830 atm Unknown: a. pressure in mm Hg b. pressure in kPa Solution: conversion factor a. b. Chapter 11 Section 1 Gases and Pressure

23. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Sample Problem A Solution, continued conversion factor a. b. Pressure and Force, continued Chapter 11 Section 1 Gases and Pressure

24. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Practice Problems pg. 365 Complete problem #1-2 Practice problems pg. 365 in your notes. You must show work for credit. ANSWERS ALONE ARE NOT POINTS

25. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu ANSWERS Practice Problems pg. 365 Complete problem #1-2 Practice problems pg. 365 in your notes. ANSWERS ALONE ARE NOT POINTS

26. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Dalton’s Law of Partial Pressures Chapter 11 Section 1 Gases and Pressure The pressure of each gas in a mixture is called the partial pressure of that gas. John Dalton, the English chemist who proposed the atomic theory, discovered that the pressure exerted by each gas in a mixture is independent of that exerted by other gases present. Dalton’s law of partial pressures states that the total pressure of a gas mixture is the sum of the partial pressures of the component gases.

27. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Visual Concepts Click below to watch the Visual Concept. Visual Concept Dalton’s Law of Partial Pressures Chapter 11 http://my.hrw.com/sh/hc6_003036809x/stud ent/ch11/sec01/vc04/hc611_01_v04fs.htm

28. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Visual Concepts Click below to watch the Visual Concept. Visual Concept Chapter 11 Equation for Dalton’s Law of Partial Pressures http://my.hrw.com/sh/hc6_003036809x/stude nt/ch11/sec01/vc05/hc611_01_v05fs.htm

29. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Dalton’s Law of Partial Pressures, continued Gases Collected by Water Displacement Gases produced in the laboratory are often collected over water. The gas produced by the reaction displaces the water in the reaction bottle. A gas collected by water displacement is not pure but is always mixed with water vapor. Water molecules at the liquid surface evaporate and mix with the gas molecules. Water vapor, like other gases, exerts a pressure known as vapor pressure. Dalton’s law of partial pressures can be applied to calculate the pressures of gases collected in this way. Chapter 11 Section 1 Gases and Pressure

30. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Particle Model for a Gas Collected Over Water Chapter 11 Section 1 Gases and Pressure

31. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu If you raise the bottle until the water levels inside and outside the bottle are the same, the total pressure outside and inside the bottle will be the same. Reading the atmospheric pressure from a barometer and looking up the value of at the temperature of the experiment in a table, you can calculate P gas. To determine the pressure of a gas inside a collection bottle, you would use the following equation, which is an instance of Dalton’s law of partial pressures. P atm = P gas + Chapter 11 Section 1 Gases and Pressure Dalton’s Law of Partial Pressures, continued Gases Collected by Water Displacement, continued

32. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Dalton’s Law of Partial Pressures, continued Sample Problem B Oxygen gas from the decomposition of potassium chlorate, KClO 3, was collected by water displacement. The barometric pressure and the temperature during the experiment were 731.0 torr and 20.0°C. respectively. What was the partial pressure of the oxygen collected? Chapter 11 Section 1 Gases and Pressure

33. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Dalton’s Law of Partial Pressures, continued Sample Problem B Solution Given:P T = P atm = 731.0 torr = 17.5 torr (vapor pressure of water at 20.0°C, from table A-8 in your book) P atm = Unknown: in torr Solution: start with the equation: rearrange algebraically to: Chapter 11 Section 1 Gases and Pressure

34. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Sample Problem B Solution, continued substitute the given values of P atm and into the equation: Dalton’s Law of Partial Pressures, continued Chapter 11 Section 1 Gases and Pressure

35. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu Section Review Problems pg. 367 Answer section review problems pg. 367 #1, 3-5 in your notes. MUST show your work. Attach notebook paper if needed. Staple NOW to packet AND LABEL.

36. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu ANSWERS Section Review Problems pg. 367 Answer section review problems pg. 367 #1, 3-5 in your notes. Show your work.

37. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu PhET Simulation 11.1 Balloons and Buoyancy - See Lab with these concepts as well that I have using PhET.

38. © Copyright Pearson Prentice Hall Slide of 25 End Show HIGHLIGHTS OF 11.1

39. © Copyright Pearson Prentice Hall Slide of 25 End Show SECTION PROBLEMS Explore these interactive demonstrations to learn how to use equations to solve science problems. Section 1: Gases and Pressure Atmospheric Pressure Conversion See how it's done Try it yourselfAtmospheric Pressure Conversion PARTIAL PressurePARTIAL Pressure See how it's done Try it yourself

40. © Copyright Pearson Prentice Hall Slide of 25 End Show Online Self-Check Quiz Complete the online Quiz and record answers. Ask if you have any questions about your answers. click here for online Quiz 11.1 (8 questions) You must be in the “Play mode” for the slideshow for hyperlink to work.

41. © Copyright Pearson Prentice Hall Slide of 28 End Show VIDEOS FOR ADDITIONAL INSTRUCTION Additional Videos for Chapter 11: Gases Section 11.1: Gas and Pressure Dalton's Law Pressure Barometer Atmospheric Pressure

42. Copyright © by Holt, Rinehart and Winston. All rights reserved. ResourcesChapter menu End of Chapter 11.1 Show