Presentation is loading. Please wait.

Presentation is loading. Please wait.

Electric Field Concepts. Rules for constructing filed lines A convenient way to visualize the electric field due to any charge distribution is to draw.

Similar presentations


Presentation on theme: "Electric Field Concepts. Rules for constructing filed lines A convenient way to visualize the electric field due to any charge distribution is to draw."— Presentation transcript:

1 Electric Field Concepts

2 Rules for constructing filed lines A convenient way to visualize the electric field due to any charge distribution is to draw a field line diagram. At any point the field line has the same direction as the electric field vector Field lines begin at positive charge and end at negative charge The number of field lines shown diverging from or converging into a point is proportional to the magnitude of the charge. Field lines are spherically symmetric near a point charge If the system has a net charge, the field lines are spherically symmetric at great distances Field lines never cross each other.

3 ELECTRIC POTENTIAL (The Volt) To develop the concept of electric potential and show its relationship to electric field intensity. In moving the object from point a to b, the work can be expressed by: d L is differential length vector along some portion of the path between a and b

4 The work done by the field in moving the charge from a to b is If an external force moves the charge against the field, the work done is negative: ELECTRIC POTENTIAL (cont’d)

5 We can defined the electric potential difference, V ab as the work done by an external source to move a charge from point a to point b as: Where, ELECTRIC POTENTIAL (cont’d) ‘a’ is the initial point while ‘b’ is the final point If is negative, there is a loss in potential energy in moving Q from ‘a’ to ‘b’; this implies that the work is being done by the field. However. If is positive, there is a gain in potential energy in the movement, an external agent performs the work is independent of the path taken is measured in joules per coulomb, commonly referred to as volts (V)

6 Consider the potential difference between two points in space resulting from the field of a point charge located at origin, where the electric field intensity is radially directed, then move from point a to b to have: ELECTRIC POTENTIAL (cont’d)

7 Thus, The absolute potential at some finite radius from a point charge fixed at the origin: ELECTRIC POTENTIAL (cont’d)

8 If the collection of charges becomes a continuous distribution, we could find: Where, Line charge Surface charge Volume charge ELECTRIC POTENTIAL (cont’d)

9 Or generally, The principle of superposition, where applied to electric field also applies to potential difference. ELECTRIC POTENTIAL (cont’d)

10 Based on figure, if a closed path is chosen, the integral will return zero potential: Three different paths to calculate work moving from the origin to point P against an electric field. ELECTRIC POTENTIAL (cont’d)

11 EXAMPLE 10 Two point charges -4 μC and 5 μC are located at (2,1-,3) and (0,4,-2) respectively. Find the potential at (1,0,1). Let and So, Where, SOLUTION - EXAMPLE 10 Therefore,

12 The electrostatic potential contours from a point charge form equipotential surfaces surrounding the point charge. The surfaces are always orthogonal to the field lines. The electric field can be determined by finding the maximum rate and direction of spatial change of the potential field. ELECTRIC POTENTIAL (cont’d)

13 Therefore, The negative sign indicates that the field is pointing in the direction of decreasing potential. By applying to the potential field: ELECTRIC POTENTIAL (cont’d)

14 Three ways to calculate E:  If sufficient symmetry, employ Gauss’s Law.  Use the Coulomb’s Law approach.  Use the gradient equation. IMPORTANT !!

15 Consider a disk of charge ρ S, find the potential at point (0,0,h) on the z-axis and then find E at that point. EXAMPLE 11 Find that, and With then, SOLUTION TO EXAMPLE 11

16 Let and leads to Integral then, How to calculate the integral? SOLUTION TO EXAMPLE 11 (Cont’d) To find E, need to know how V is changing with position. In this case E varies along the z-axis, so simply replace h with z in the answer for V, then proceed with the gradient equation.

17 Conductors and Insulators A conductor is a substance that allows current to flow through it :- they transfer charge across them. In metals, the current is composed of moving electrons. Electrolytic solutions also conduct current but by the movement of flow of ions. Insulators have few mobile electrons or ions and the flow of current is inhibited- They keep tight tabs on their electrons. As fields are increased, dielectric breakdown of insulators occurs and the current is discharged as a surge. The dielectric strength is the maximum field an insulator can support.

18 Resistance is a measure of resistance to flow of electricity. It is defined by Ohm’s Law as follows: (ohm’s Law) Therefore, resistance is in the units of volts per ampere. One volt per ampere is called an ohm (Ω). The reciprocal of resistance is conductance Resistance and Ohm’s Law

19 The amount of charge that accumulates as a function of potential difference is called the capacitance. The unit is the farad (F) or coulomb per volt. Capacitance

20 Two methods for determining capacitance:  Q Method Assume a charge +Q on plate ‘ a’ and a charge –Q on plate ‘ b’. Solve for E using the appropriate method (Coulomb’s Law, Gauss’s Law, boundary conditions) Solve for the potential difference V ab between the plates (The assumed Q will divide out) Capacitance (Cont’d)

21  V Method Assume V ab between the plates. Find E, then D using Laplace’s equation. Find ρ S, and then Q at each plate using conductor dielectric boundary condition (D N = ρ S ) C = Q/ V ab (the assumed V ab will divide out) Capacitance (Cont’d)

22 Use Q method to find the capacitance for the parallel plate capacitor as shown. Example 12

23 Place charge +Q on the inner surface of the top plate, and –Q charge on the upper surface of the bottom plate, where the charge density, Use conductor dielectric boundary, to obtain: from Solution to Example 12

24 We could find the electric field intensity, E The potential difference across the plates is: Solution to Example 12

25 Finally, to get the capacitance: Solution to Example 12

26 Bioelectrical impedance analysis (BIA) is a commonly used method for estimating body composition. Since the advent of the first commercially available devices in the mid-1980s the method has become popular owing to its ease of use, portability of the equipment and its relatively low cost compared to some of the other methods of body composition analysis. It is familiar in the consumer market as a simple instrument for estimating body fat. BIA actually determines the electrical impedance, or opposition to the flow of an electric current, of body tissues, which can be used to calculate an estimate of total body water (TBW).electrical impedancetotal body water TBW can be used to estimate fat-free body mass and, by difference with body weight, body fat.body fat Bioelectrical Impedance Analysis

27 When constant electric current is applied between two electrodes through a biological medium and the corresponding voltage is measured between the two source poles, the resultant impedance or bioimpedance is determined by Ohm’s law. The recorded voltage is the sum of the potential difference contributions due to the electrical conductivity properties of the tissue medium. The exchange of electrons from source to sink occurs from electrons of the metal electrode (such as platinum or silver-silver chloride) to ions of the tissue medium. The electrode is the site of charge carrier exchange between electrons and ions and thus serves as a transducer of electrical energy. Impedance measurements most commonly use a two- electrode (bipolar) of four-electrode (tetrapolar) arrangement. Bioelectrical Impedance Theory

28 The Maxwell equation most relevant to bioimpedance is Eq. (1) Eq. (2) where H - magnetic field strength [A/m], D - electric flux density [coulomb/m2], J - current density [A/m2], E - electric field strength [V/m], - permittivity of vacuum [farad (F)/m], and P - electric polarization dipole moment pr. volume [coulomb/m2]. If the magnetic component is ignored, Equation 1 is reduced to: Eq. (3) Equations 1-3 are extremely robust and also valid under nonhomogeneous, nonlinear, and anisotropic conditions. They relate the time and space derivatives at a point to the current density at that point. Bioelectrical Impedance Theory

29 Impedance and permittivity in their simplest forms are based on a basic capacitor model. Basic equation of bioimpedance is then (time vectors) Bioelectrical Impedance Theory Typical body segment resistance values

30 SUMMARY (1) The force exerted on a charge Q1 on charge Q2 in a medium of permittivity ε is given by Coulomb’s Law: Where is a vector from charge Q1 to Q2 Electric field intensity E 1 is related to force F 12 by:

31 The Coulomb’s Law can be rewritten as: For a continuous charge distribution: For a point charge at origin: SUMMARY (2)

32 For an infinite length line charge ρ L on the z axis For an infinite extent sheet of charge ρ S Electric flux density, D related to field intensity by: Where ε r is the relative permittivity in a linear, isotropic and homogeneous material. SUMMARY (3)

33 Electric flux passing through a surface is given by: Gauss’s Law states that the net electric flux through any closed surface is equal to the total charge enclosed by that surface: Point form of Gauss’s Law is SUMMARY (4)

34 The electric potential difference V ab between a pair of points a and b in an electric field is given by: Where V a and V b are the electrostatics potentials at a and b respectively. For a distribution of charge in the vicinity of the origin, where a zero reference voltage is taken at infinite radius: SUMMARY (5)

35 E is related to V by the gradient equation: Which for Cartesian coordinates is: The conditions for the fields at the boundary between a pair of dielectrics is given by: and SUMMARY (6)

36 Where E T1 and E T2 are the electric field components tangential to the boundary, a 21 is a unit vector from medium 2 to 1 and ρ S is the surface charge at the boundary. If no surface charge is present, the components of D normal to the boundary are equal: At the boundary between a conductor and a dielectric, the conditions are: and SUMMARY (7)

37 Poisson’s equation is: Where the Laplacian of V in Cartesian coordinates is given by: In a charge free medium, Poisson’s equation reduces to Laplace’s equation SUMMARY (8)

38 Capacitance is a measure of charge storage capability and is given by: For coaxial cable: For two concentric spheres: So, SUMMARY (9)


Download ppt "Electric Field Concepts. Rules for constructing filed lines A convenient way to visualize the electric field due to any charge distribution is to draw."

Similar presentations


Ads by Google