1. The atom orbiting electrons Nucleus (protons and neutrons)

2. Nuclide notation Li 3 7 Proton number (Z) = number of protons Nucleon number (A) = number of protons and neutrons Neutron number (N) = A - Z

3. Isotopes Li 3 7 It is possible for the nuclei of the same element to have different numbers of neutrons in the nucleus (but it must have the same number of protons) Li 3 6

4. Isotopes Li 3 7 For example, Lithium atoms occur in two forms, Lithium-6 and Lithium-7 Li 3 6 4 neutrons 3 neutrons

5. Isotopes of Hydrogen H 1 1 The three isotopes of Hydrogen even have their own names! H 1 2 H 1 3 Hi! I’m hydrogen They call me deuterium Hola! Mi nombre es tritium y yo soy de Madrid!

6. How do we know the structure of the atom?

7. The famous Geiger-Marsden Alpha scattering experiment In 1909, Geiger and Marsden were studying how alpha particles are scattered by a thin gold foil. Alpha source Thin gold foil

8. Geiger-Marsden As expected, most alpha particles were detected at very small scattering angles Alpha particles Thin gold foil Small-angle scattering

9. Geiger-Marsden To their great surprise, they found that some alpha particles (1 in 20 000) had very large scattering angles Alpha particles Thin gold foil Small-angle scattering Large-angle scattering

10. Explaining Geiger and Marsdens’ results The results suggested that the positive (repulsive) charge must be concentrated at the centre of the atom. Most alpha particles do not pass close to this so pass undisturbed, only alpha particles passing very close to this small nucleus get repelled backwards (the nucleus must also be very massive for this to happen). nucleus

11. Rutherford did the calculations! Rutherford (their supervisor) calculated theoretically the number of alpha particles that should be scattered at different angles. He found agreement with the experimental results if he assumed the atomic nucleus was confined to a diameter of about 10 -15 meters

12. Rutherford did the calculations! Atomic nucleus had a diameter of about 10 -15 m That’s 100,000 times smaller than the size of an atom (about 10 -10 meters).

13. Stadium as atom If the nucleus of an atom was a ping-pong ball, the atom would be the size of a football stadium (and mostly full of nothing)! Nucleus (ping- pong ball

14. Forces in the Nucleus

15. Coulomb Force in Nucleus Repulsive force between protons + +

16. The Strong Force The nucleons (protons and neutrons) in the nucleus are bound together by the strong nuclear force

17. Strong Force Acts over short distances (10 -15 m) Acts only between adjacent particles in the nucleus Carried by “gluons”

18. Why is a nucleus unstable? Because of the relative numbers of p and n Ex. Uranium 235 Hi! I’m uranium-235 and I’m unstable. I really need to lose some particles from my nucleus to become more stable.

19. The unstable nucleus emits a particle to become stable Thus, the atom (nucleus) has decayed. Weeeeeeeeeeeeee!

20. Decay of an Unstable Nucleus 1. Random – It’s going to happen, but when?! 2. Spontaneous – Not affected by temperature, pressure etc. Weeeeeeeeeeeeee!

21. Becquerels (Bq) The amount of radioactivity given out by a substance is measured in Becquerels. One Becquerel is one particle emitted per second.

22. How to detect particles? Photographic film Fluorescence Geiger-Müller tube (GM tube) connected to a counter (counts the # of particles) –Use filters to distinguish alpha, beta, and gamma particles

23. Three main types of particles can be ejected from an unstable nucleus.

24. Alpha particles α Hi!

25. Alpha particles 2 protons and 2 neutrons joined together –Helium nucleus Stopped by paper or a few cm of air Highly ionising Deflected by electric and strong magnetic fields He 2 4 2+ α 2 4

26. Alpha Decay U 92 235 Th 90 231 + Atomic number goes down by 2 Atomic mass goes down by 4 He 2 4 2+

27. Alpha Decay U 92 235 Th 90 231 + Atomic number goes down by 2 Atomic mass goes down by 4 α 2 4

28. Beta particles β Yo!

29. Beta particles Fast moving electrons or positrons Stopped by about 3 mm of aluminium Weakly ionising Deflected by electric and magnetic fields e 0 β 0 e +1 0 β 0 Beta Negative  electronBeta Positive  Positron

30. In the nucleus a neutron [or proton] changes into an electron [positron] (the beta particle which is ejected) and a proton [neutron] (which stays in the nucleus) and an antineutrino [neutrino] –During beta decay the mass number stays the same but the proton number goes up [or down] by 1. e + ע e Beta decay e + ע e 0 Ca 20 46 Sc + 21 46 0 0 antineutrino +1 0 K 19 40 Ar + 18 40 0 0 neutrino

31. In the nucleus a neutron [or proton] changes into an electron [positron] (the beta particle which is ejected) and a proton [neutron] (which stays in the nucleus) and an antineutrino [neutrino] –During beta decay the mass number stays the same but the proton number goes up [or down] by 1. β + עeβ + עe Beta decay β + ע e 0 Ca 20 46 Sc + 21 46 0 0 antineutrino +1 0 K 19 40 Ar + 18 40 0 0 neutrino

32. Gamma rays Hola!

33. Gamma rays High frequency electromagnetic radiation Stopped by several cm of lead Very weakly ionising NOT affected by electric or magnetic fields

34. Gamma rays Usually associated with alpha decay Excited nucleus relaxes by releasing a gamma ray. U 92 235 Th * 90 231 + α Th 90 231 +

35. Biological Effects of Localized Radiation Exposure Short Term –Low dosage – skin reddening –High dosage – skin or tissue necrosis Long Term – through direct or indirect actions –Damages or mutates DNA and other cells (specific concern: somatic cells) –Potential cancer causing

36. Best Practice: Prevention! Limit Radiation Concentration (in labs) Limit Exposure Time Increase Distance Use Appropriate Shielding Materials

37. ½ - life The decay of a single nuclei is totally random However, with large numbers of atoms a pattern does occur

38. ½ - life This is the time it takes half the nuclei to decay half-life (t ½ ) Number of nuclei undecayed time

39. ½ - life This is the time it takes half the nuclei to decay half-life (t ½ ) Number of nuclei undecayed time

40. ½ - life This is the time it takes half the nuclei to decay half-life (t ½ ) Number of nuclei undecayed time A graph of the count rate against time will be the same shape

41. Different ½ - lives Different isotopes have different half-lives The ½-life could be a few milliseconds or 5000 million years! half-life (t ½ ) Number of nuclei undecayed time

42. Decay Constant (λ) The probability that an atom will decay –Remember that the decay of a single nuclei is totally random Activity = the decay constant times the number of atoms –Equation  A = λ N

43. Determining ½ - lives For short half-lives –Use a GM-tube to measure initial activity, and then measure the time it takes for that activity to decrease by a half. –That time is the half-life! For long half-lives –Use a GM-tube to measure the initial Activity –Measure the mass of the sample Calculate the # of atoms using molar mass and Avogadro’s number –Calculate λ [decay constant] from A 0 = λ N 0 –Calculate half-life  t 1/2 = ln(2) / λ

44. Nuclear Reactions

45. Unified mass unit (u) Defined as 1/12 of the mass of an atom of Carbon-12 u = 1.6605402 x 10 -27 kg

46. Energy mass equivalence E = mc 2 E = 1.6605402 x 10 -27 x (2.9979 x 10 8 ) 2 E = 1.4923946316 x 10 -10 J Remembering 1 eV = 1.602177 x 10 -19 J 1 u = 931.5 MeV The electron-Volt is a convenient unit of energy for nuclear physics

47. Mass defect For helium, the mass of the nucleus = 4.00156 u But, the mass of two protons and two nuetrons = 4.0320 u!!!! Where is the missing mass?

48. Mass defect The missing mass (mass defect) has been stored as energy in the nucleus. It is called the binding energy of the nucleus. It can be found from E = mc 2

49. Mass defect calculation Find the mass defect of the nucleus of gold, 196.97 - Au

50. Mass defect calculation The mass of this isotope is 196.97u Since it has 79 electrons its nuclear mass is 196.97u – 79x0.000549u = 196.924u

51. Mass defect calculation The mass of this isotope is 196.97u Since it has 79 electrons its nuclear mass is 196.97u – 79x0.000549u = 196.924u This nucleus has 79 protons and 118 neutrons, individually these have a mass of 79x1.0007276u + 118x1.008665u = 198.080u

52. Mass defect calculation The mass of this isotope is 196.97u Since it has 79 electrons its nuclear mass is 196.97u – 79x0.000549u = 196.924u This nucleus has 79 protons and 118 neutrons, individually these have a mass of 79x1.0007276u + 118x1.008665u = 198.080u The difference in mass (mass defect) is therefore 1.156u

53. Mass defect calculation The difference in mass (mass defect) is therefore 1.156u This “missing mass” is stored as energy in the nucleus (binding energy). 1u is equivalent to 931.5 MeV

54. Nuclear Reactions Similar calculation as mass defect – the products have less mass that the reactants, and the lost mass is converted into KE of the products Transmutation - the conversion of the nucleus of one isotope or element into another Artificial (induced) transmutation – the energy required for transmutation is provided by “artificial” means

55. EX. Artificial Transmutation – bombard a nitrogen atom with a high E alpha particle N 7 14 + O 8 17 + p 1 1 He 2 4 2+ N 7 14 + O 8 17 + p 1 1 α 2 4

56. Binding energy The work (energy) required to completely separate the nucleons of the nucleus.

57. Binding energy per nucleon The BE / nucleon number - the work (energy) required to completely remove 1 nucleon from a nucleus It is a measure of how stable the nucleus is.

58. The binding energy curve

59. Let’s do some reading!

60. Nuclear Fission

61. Uranium Uranium 235 has a large unstable nucleus.

62. Capture A lone neutron hitting the nucleus can be captured by the nucleus, forming Uranium 236.

63. Fission and free neutrons Uranium 236 is very unstable and splits (nuclear fission) into two smaller nuclei (called daughter nuclei) and three neutrons (with lots of kinetic energy)

64. Fission These free neutrons can strike more uranium nuclei, causing them to split.

65. Chain Reaction If there is enough uranium (critical mass) a chain reaction occurs. Huge amounts of energy are released very quickly.

66. Chain Reaction If there is enough uranium (critical mass) a chain reaction occurs. Huge amounts of energy are released very quickly.

67. Bang! This can result in a nuclear explosion! (movie is of a 23 ktonne nuke detonated underwater.) http://www.youtube.com/watch?v=b2WQvtGnBQw

69. Nuclear fusion – Star power!

70. http://hyperphysics.phy- astr.gsu.edu/hbase/nucene/fusion.html#c1http://hyperphysics.phy- astr.gsu.edu/hbase/nucene/fusion.html#c1 http://hyperphysics.phy- astr.gsu.edu/hbase/astro/astfus.html#c1http://hyperphysics.phy- astr.gsu.edu/hbase/astro/astfus.html#c1 Check out the 2 links above to better understand all the types of nuclear reactions that occur in stars.

71. The binding energy curve