1. SQL in Action Amit Bhawnani & Nimesh Shah

2. Basic Structure SQL is based on set and relational operations with certain modifications and enhancements A typical SQL query has the form: select A 1, A 2,..., A n from r 1, r 2,..., r m where P – A i s represent attributes – r i s represent relations – P is a predicate. This query is equivalent to the relational algebra expression.  A1, A2,..., An (  P (r 1 x r 2 x... x r m )) The result of an SQL query is a relation.

3. SELECT What are the names and prices of all the products we carry? Select product name, retail price from the products table SELECT ProductName, RetailPrice FROM Products

4. DISTINCT Which states do our customers come from ? Select the distinct state values from the customers table Select DISTINCT custState FROM Customers Tip: Use only when necessary

5. SELECT ALL Display all the information on our employees SELECT * FROM employees Tip: explicitly specify columns instead of querying with *

6. ORDER BY Display a list of vendor names in ZIP Code order. SELECT VendName, VendZipCode FROM Vendors ORDER BY VendZipCode

7. ORDER BY Display the names of our employees, including their phone number and ID number, and list them by last name and first name. SELECT EmpLastName, EmpFirstName,EmpPhoneNumber, EmployeeID FROM Employees ORDER BY EmpLastName, EmpFirstName

8. Concatenation Expression Give me a list of employee full names and their dates of birth. Select EmpFirstname || ‘ ‘ || EmpLastName as EmployeeName, DOB AS DateOfBirth FROM Employees

9. Mathematical Expression What is the inventory value of each product? SELECT ProductName, RetailPrice * QuantityOnHand AS InventoryValue FROM Products

10. Aggregate Functions - SUM What is the total amount we pay in salaries to ALL our employees? SELECT SUM(Salary) AS TotalSalaryAmount FROM Employees

11. Aggregate Functions - MIN What is the lowest price we charge for a product? SELECT MIN(Price) AS LowestProductPrice FROM Products

12. FILTER What are the names of our customers who live in the state of washington (WA)? SELECT CustFirstName, CustLastName FROM Customers WHERE CustState = 'WA'

13. COUNT How many of our customers live in the state of washington (WA)? SELECT count(*) as NumberOfCustomers FROM Customers WHERE CustState = 'WA'

14. FILTER - Inequality Display a list of vendor names and phone numbers for all our vendors,with the exception of those here in Bellevue. SELECT VendName, VendPhone FROM Vendors WHERE VendCity <> 'Bellevue'

15. Filter - Less Than and Greater Than Are there any orders where the ship date was accidentally posted earlier than the order date? SELECT OrderNumber FROM Orders WHERE ShipDate < OrderDate

16. LIKE Show me an alphabetical list of products with names that begin with ‘Dog’ SELECT ProductName FROM Products WHERE ProductName LIKE 'Dog%‘ ORDER BY ProductName

17. Multiple Filters Display customers with the last name 'Patterson’ and the customer should belong to the state CA or the zip code should end in 9. SELECT CustFirstName, CustLastName, CustState, CustZipCode FROM Customers WHERE CustLastName = 'Patterson‘ AND (CustState = 'CA‘ OR CustZipCode LIKE '%9‘)

18. BETWEEN Display the list of Orders that were placed in September 2007 Select * from Orders WHERE OrderDate BETWEEN '2007-09-01' AND '2007-09-30‘

19. IS NULL Which vendors do we work with that don’t have a Web site select vendorID,VendName from vendors where VendWebPage is null

20. IN Give me the names of all vendors based in Ballard, Bellevue, and Redmond select vendorID,VendName from vendors where VendCity in ( 'Ballard', 'Bellevue', 'Redmond' )

21. TOP Display the name and retail price of the 10 most expensive products Select top 10 productName,RetailPrice from products order by retailPrice desc

22. GROUP BY Display the numbers of customers from each city in descending order of the number of customers. SELECT CustCity, Count(*) as CustPerCity FROM Customers GROUP BY Customers.CustCity ORDER by CustPerCity desc

23. GROUP BY Display product number and total sales for each product SELECT productNumber, SUM(QuotedPrice*QuantityOrdered) as total_price FROM Order_Details GROUP BY productNumber ORDER BY total_price desc

24. HAVING Display for the productnumber for all the products where the total sales for the product is greater than 100000 SELECT productNumber, SUM(QuotedPrice*QuantityOrdered) as total_price FROM Order_Details GROUP BY productNumber HAVING sum(QuotedPrice*QuantityOrdered) > 100000 order by total_price desc Tip: Having clause is used to filter rows after all the rows are selected. Do not try to use HAVING instead of WHERE

25. INNER Join Display all product names and their category descriptions. SELECT Categories.CategoryDescription, Products.ProductName FROM Categories INNER JOIN Products ON Categories.CategoryID = Products.CategoryID

26. More then two tables List of customer names who have ever ordered a helmet. SELECT DISTINCT Customers.CustFirstName, Customers.CustLastName FROM Customers INNER JOIN Orders ON Customers.CustomerID = Orders.CustomerID INNER JOIN Order_Details ON Orders.OrderNumber = Order_Details.OrderNumber INNER JOIN Products ON Products.ProductNumber = Order_Details.ProductNumber WHERE Products.ProductName LIKE '%Helmet%'

27. Left Outer Join What products have never been ordered ? SELECT Products.ProductNumber, Products.ProductName FROM Products LEFT OUTER JOIN Order_Details ON Products.ProductNumber = Order_Details.ProductNumber WHERE Order_Details.OrderNumber IS NULL

28. LEFT OUTER JOIN List product number, Product name and the quantity ordered for each product. Also include the products that have not been ordered. Order in descending order of products sold. SELECT Products.ProductNumber, Products.ProductName, b.cnt FROM Products LEFT OUTER JOIN ( select productNumber,sum(quantityOrdered) as cnt from Order_Details group by productNumber ) as b ON Products.ProductNumber = b.ProductNumber

29. Subqueries as Filters (IN) Find all the customers who have placed an order on 2008-02-28 select customerId,custFirstName,CustLastName from customers where customerid in (select customerid from orders where OrderDate = '2008-02-28')

30. Correlated subquery Find all the customers that have placed over 40 orders select customerId,CustFirstName,CustLastName from Customers c where 40 < (select count(*) from orders o where o.customerId = c.customerId)

31. EXISTS List of all employees who generated a sale on the 2007-09-09 select EmpFirstName,EmpLastName from employees where exists (select 1 from Orders where Orders.EmployeeId = employees.EmployeeId and OrderDate = '2007-09-09')

32. NOT EXISTS List of all employees who did not make any sales on the 2007-09-09 select EmpFirstName,EmpLastName from employees where not exists (select 1 from Orders where Orders.EmployeeId = employees.EmployeeId and OrderDate = '2007-09-09')

33. Subqueries as Column Expressions Display a list of customers and the last date on which they placed an order SELECT Customers.CustFirstName, Customers.CustLastName, (SELECT MAX(OrderDate) FROM Orders WHERE Orders.CustomerID = Customers.CustomerID) AS LastOrderDate FROM Customers

34. Subqueries as Column Expressions List vendors and a count of the products they sell to us Select VendName,(select count(productNumber) from product_vendors where vendorId = vendors.vendorid) from vendors

35. EXCEPT Find all the customers who have placed an order on 2007-09-13 but NOT on 2007-09-22 select customerId,custFirstName,CustLastName from customers where customerid in ( select customerid from orders where OrderDate = '2007-09-13‘ except select customerid from orders where OrderDate = '2007-09-22‘ )

36. UNION Give a list of customer full and vendor full names that belong to the state of texas. SELECT CustFirstName + ' ' + CustLastName as CustName from customers where custState = 'TX‘ union select VendName from vendors where VendState = 'TX' Tip: try to use UNION ALL in place of UNION.

37. Update Increase the retail price of all products by 10 percent. UPDATE Products SET Price = Price + (0.1 * Price)

38. Update – with filters Modify products by increasing the retail price by 4 percent for products that are clothing UPDATE Products SET RetailPrice = RetailPrice * 1.04 WHERE CategoryID = (SELECT CategoryID FROM Categories WHERE CategoryDescription = 'Clothing')

39. Delete Delete all order details for orders placed before January 1, 2008 DELETE FROM Order_Details WHERE OrderNumber IN (SELECT OrderNumber FROM Orders WHERE OrderDate < '2008-01-01')

40. Delete Delete vendors who do not provide any products DELETE FROM Vendors WHERE VendorID NOT IN (SELECT VendorID FROM Product_Vendors)

41. Insert Insert into the employees table in the columns first name,last name, street address, city, state, ZIP Code, area code, and phone number the values Susan, Metters, 16547 NE 132nd St, Woodinville,WA, 98072, 425, and 555-7825 INSERT INTO Employees (EmpFirstName, EmpLastName, EmpStreetAddress, EmpCity, EmpState,EmpZipCode, EmpAreaCode, EmpPhoneNumber) VALUES ('Susan', 'Metters','16547 NE 132nd St', 'Woodinville', 'WA','98072', 425, '555-7825')

42. Insert data by using SELECT Copy to the Employees table the relevant columns in the Customers table for customer David Smith. INSERT INTO Employees (EmpFirstName, EmpLastName, EmpStreetAddress, EmpCity, EmpState, EmpZipCode, EmpAreaCode, EmpPhoneNumber) SELECT Customers.CustFirstName,Customers.CustLastName, Customers.CustStreetAddress, Customers.CustCity, Customers.CustState, Customers.CustZipCode, Customers.CustAreaCode, Customers.CustPhoneNumber FROM Customers WHERE Customers.CustFirstName = 'David' AND Customers.CustLastName = 'Smith'

43. Create table Create a dept table with dept_id (PK), description, insert_date Modify the employees table and associate the department id with the employees create table department ( dept_id integer primary key, description varchar(50) not null, addition_date datetime default getdate() ) Alter table employees add dept_id integer foreign key references department(dept_id)