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CHAPTER 7.5

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Indirect measurement is any method that uses formulas, similar figures, and/or proportions to measure an object. The following example shows one indirect measurement technique. Whenever dimensions are given in both feet and inches, you must convert them to either feet or inches before doing any calculations. Helpful Hint

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Tyler wants to find the height of a telephone pole. He measured the pole’s shadow and his own shadow and then made a diagram. What is the height h of the pole?

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Step 1 Convert the measurements to inches. AB = 7 ft 8 in. = (7 12) in. + 8 in. = 92 in. BC = 5 ft 9 in. = (5 12) in. + 9 in. = 69 in. FG = 38 ft 4 in. = (38 12) in. + 4 in. = 460 in. Step 2 Find h. 92h = 69 460 h = 345 The height h of the pole is 345 inches, or 28 feet 9 inches.

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A student who is 5 ft 6 in. tall measured shadows to find the height LM of a flagpole. What is LM?

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Step 1 Convert the measurements to inches. GH = 5 ft 6 in. = (5 12) in. + 6 in. = 66 in. JH = 5 ft = (5 12) in. = 60 in. NM = 14 ft 2 in. = (14 12) in. + 2 in. = 170 in. Step 2 Find h. 60(h) = 66 170 h = 187 The height of the flagpole is 187 in., or 15 ft. 7 in.

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A scale drawing represents an object as smaller than or larger than its actual size. The drawing’s scale is the ratio of any length in the drawing to the corresponding actual length. For example, on a map with a scale of 1 cm : 1500 m, one centimeter on the map represents 1500 m in actual distance. A proportion may compare measurements that have different units. Remember!

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Lady Liberty holds a tablet in her left hand. The tablet is 7.19 m long and 4.14 m wide. If you made a scale drawing using the scale 1 cm:0.75 m, what would be the dimensions to the nearest tenth? Set up proportions to find the length l and width w of the scale drawing. w 5.5 cm 9.6 cm 5.5 cm

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Given that ∆LMN ~∆QRT, find the perimeter P and area A of ∆QRS. The similarity ratio of ∆LMN to ∆QRS is By the Proportional Perimeters and Areas Theorem, the ratio of the triangles’ perimeters is also, and the ratio of the triangles’ areas is

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Perimeter Area 13P = 36(9.1) P = 25.2 13 2 A = (9.1) 2 (60) A = 29.4 cm 2 The perimeter of ∆QRS is 25.2 cm, and the area is 29.4 cm 2.

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∆ABC ~ ∆DEF, BC = 4 mm, and EF = 12 mm. If P = 42 mm and A = 96 mm 2 for ∆DEF, find the perimeter and area of ∆ABC. Perimeter Area 12P = 42(4) P = 14 mm 12 2 A = (4) 2 (96) The perimeter of ∆ABC is 14 mm, and the area is 10.7 mm 2.

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WORKSHEET P491 #’S 10-11 P492 #’S 18-19

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