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Published byJustin Beasley Modified over 9 years ago
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Dilutions
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Solve problems involving the dilution of solutions. Include: dilution of stock solutions, mixing common solutions with different volumes and concentrations Additional KEY Terms
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Labs buy highly concentrated solutions to save storage space - stock solutions. To dilute a solution means to add more solvent to small volume of stock without adding more solute. Moles of solute remains unchanged. moles s = moles d
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moles d moles s
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M = moles Where: C 1 is the initial concentration (stock) V 1 is the initial volume of solution (stock) C 2 is the concentration after dilution V 2 is the volume after dilution moles s = moles d C 1 V 1 = C 2 V 2 L
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If 500.0 mL of water is added to 300.0 mL of a 0.100 mol/L solution of NaCl, what is the new concentration? V 2 = 300.0 + 500.0 = 800.0 mL = C1C1 V1V1 C2C2 V2V2 = (0.100)C2C2 (0.800) (0.300)0.0375 M
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What is the concentration of the stock solution if 50.0 mL of the stock is diluted to make 220.0 mL of a 0.400 M solution? = C1C1 V1V1 C2C2 V2V2 = (0.400) C1C1 (0.0500) (0.220) 1.76 mol/L
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How much water must be added to 25.0 mL of a 1.00 M stock solution of NaOH to make a 0.100 M solution? = C1C1 V1V1 C2C2 V2V2 = (1.00) V2V2 (0.100) (0.0250) 0.250 L 0.250 L – 0.0250 L = 0.225 L
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To prepare a diluted solution: 1.Determine the volume of stock solution needed. 2.Add half of the volume of water to the beaker. 3.Add the stock solution. 4.Add remaining water to the total volume and mix.
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Mixing two or more solutions having the same solute, but different concentrations: = (C 1 V 1 + C 2 V 2 + …) C Final (V 1 + V 2 + …) = C Final Total volume Total moles
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450.0 mL of a 0.150 M NaCl solution is mixed with 125 mL of a 0.220 M NaCl solution. = 0.165 M = (C 1 V 1 + C 2 V 2 ) C Final (V 1 + V 2 ) = (0.150)(0.450) + (0.220)(0.125) CFCF (0.450 + 0.125)
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A diluted solution has the same number of moles of solute as the given stock, but a new volume. Since the moles of solute remains the same, the dilution equation is C 1 V 1 = C 2 V 2 Mix two or more solutions containing the same solute - use the equation
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CAN YOU / HAVE YOU? Solve problems involving the dilution of solutions. Include: dilution of stock solutions, mixing common solutions with different volumes and concentrations Additional KEY Terms
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