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Ch2: Graphs y axis x axis y - $$ in thousands x Yrs Quadrant II (-, +)

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Presentation on theme: "Ch2: Graphs y axis x axis y - $$ in thousands x Yrs Quadrant II (-, +)"— Presentation transcript:

1 Ch2: Graphs y axis x axis y - $$ in thousands x Yrs Quadrant II (-, +)
Origin (0, 0) (6,0) 2 4 6 y intercept x intercept (5,-2) (-6,-3) (0,-3) Quadrant III (-, -) Quadrant IV (+, -) When distinct points are plotted as above the graph is called a scatter plot – ‘points that are scattered about’ Graphs represent trends in data. For example: x – number of years in business y – thousands of dollars of profit Equation : y = ½ x – 3 A point in the x/y coordinate plane is described by an ordered pair of coordinates (x, y)

2 2.1 Distance & Midpoint y x M Origin (0, 0) -6 -2 2 4 6
Things to know: Find distance or midpoint given 2 points Given midpoint and 1 point, find the other point Given distance and 1 point, find the other point Origin (0, 0) 2 4 6 A point in the x/y coordinate plane is described by an ordered pair of coordinates (x, y) (5,-2) (-6,-3) The Distance Formula To find the distance between 2 points (x1, y1) and (x2, y2) d =  (x2 – x1)2 + (y2 – y1)2 The Midpoint Formula To find the coordinates of the midpoint (M) of a segment given segment endpoints of (x1, y1) and (x2, y2) x1 + x2, y1 + y2 M

3 2.2 & 2.3 Linear Equations The graph of a linear equation is a line.
A linear function is of the form y = ax + b, where a and b are constants. y = 3x + 2 y = 3x + 5x y = -2x –3 y = (2/3)x -1 y = 4 6x + 3y = 12 y x x y=3x x y=2/3x –1 All of these equations are linear. Three of them are graphed above.

4 X and Y intercepts -3 6 y Equation: y = ½ x – 3 (6,0) x y intercept x
(0,-3) The y intercept happens where y is something & x = 0: (0, ____) Let x = 0 and solve for y: y = ½ (0) – 3 = -3 The x intercept happens where x is something & y = 0: (____, 0) Let y = 0 and solve for x: 0 = ½ x – 3 => 3 = ½ x => x = 6 -3 6

5 Slope Slope is the ratio of RISE (How High) y2 – y1 y (Change in y)
RUN (How Far) x2 – x x (Change in x) = Slope = 5 – 2 = 3 1 - 0 Slope = 1 – (-1) = 2 3 – y = mx + b m = slope b = y intercept y x Things to know: Find slope from graph Find a point using slope Find slope using 2 points Understand slope between 2 points is always the same on the same line x y=3x x y=2/3x –1

6 The Possibilities for a Line’s Slope (m)
Positive Slope x y m > 0 Line rises from left to right. Negative Slope x y m < 0 Line falls from left to right. Zero Slope x y m = 0 Line is horizontal. m is undefined Undefined Slope x y Line is vertical. Example: y = ½ x + 2 Example: y = -½ x + 1 Example: y = 2 Example: x = 3 Question: If 2 lines are parallel do you know anything about their slopes? Things to know: Identify the type of slope given a graph. Given a slope, understand what the graph would look like and draw it. Find the equation of a horizontal or vertical line given a graph. Graph a horizontal or vertical line given an equation Estimate the point of the y-intercept or x-intercept from a graph.

7 Linear Equation Forms (2 Vars)
Standard Form Ax + By = C A, B, C are real numbers. A & B are not both 0. Example: 6x y = 12 Things to know: Graph using x/y chart Know this makes a line graph. Slope Intercept Form y = mx + b m is the slope b is the y intercept Example: y = - ½ x - 2 Things to know: Find Slope & y-intercept Graph using slope & y-intercept Point Slope Form y – y1 = m(x – x1) Example: Write the linear equation through point P(-1, 4) with slope 3 y – y1 = m(x – x1) y – 4 = 3(x - - 1) y – 4 = 3(x + 1) Things to know: Change from point slope to/from other forms. Find the x or y-intercept of any linear equation

8 Parallel and Perpendicular Lines & Slopes
Things to know: Identify parallel/non-parallel lines. Vertical lines are parallel Non-vertical lines are parallel if and only if they have the same slope y = ¾ x + 2 y = ¾ x -8 Same Slope Things to know: Identify (non) perpendicular lines. Find the equation of a line parallel or perpendicular to another line through a point or through a y-intercept. PERPENDICULAR Any horizontal line and vertical line are perpendicular If the slopes of 2 lines have a product of –1 and/or are negative reciprocals of each other then the lines are perpendicular. y = ¾ x + 2 y = - 4/3 x - 5 Negative reciprocal slopes 3 • -4 = = -1 Product is -1

9 Practice Problems Find the slope of a line passing through (-1, 2) and (3, 8) Graph the line passing through (1, 2) with slope of - ½ Is the point (2, -1) on the line specified by: y = -2(x-1) + 3 ? Parallel, Perpendicular or Neither? 3y = 9x + 3 and 6y + 2x = 6 Find the equation of a line parallel to y = 4x + 2 through the point (-1,5) Find the equation of a line perpendicular to y = - ¾ x –8 through point (2, 7) Find a line parallel to x = 7; Find a line perpendicular to x = 7 Find a line parallel to y = 2; Find a line perpendicular to y = 2 8. Graph (using an x/y chart – plotting points) and find intercepts of any equation such as: y = 2x + 5 or y = x2 – 4

10 Symmetry in Graphing Y-Axis Symmetry  even functions f (-x) = f (x)
For every point (x,y), the point (-x, y) is also on the graph. Test for symmetry: Replace x by –x in equation. Check for equivalent equation. Origin Symmetry  odd functions f (-x) = -f (x) For every point (x, y), the point (-x, -y) is also on the graph. Test for symmetry: Replace x by –x , y by –y in equation. Check for equivalent equation. X-Axis Symmetry (For every point (x, y), the point (x, -y) is also on the graph.) Test for symmetry: Replace y by –y in equation. Check for equivalent equation. y = x2 Y-axis Symmetry y = x3 Origin Symmetry x = y2 X-axis Symmetry Symmetry Test -y = (-x)3 -y = -x3 y = x3 Symmetry Test y = (-x)2 y = x2 Symmetry Test x = (-y)2 X = y2

11 A Rational Function Graph & Symmetry
x x y /2 -1/ Undefined ½ 1 Intercepts: No intercepts exist If y = 0, there is no solution for x. If x = 0, y is undefined The line x = 0 is called a vertical asymptote. The line y = 0 is called a horizontal asymptote. Symmetry: y = 1/-x => No y-axis symmetry -y = 1/-x => y = 1/x => origin symmetry -y = 1/x => y = -1/x => no x-axis symmetry

12 Application: Solar Energy
The solar electric generating systems at Kramer Junction, California, use parabolic troughs to heat a heat-transfer fluid to a high temperature. This fluid is used to generate steam that drives a power conversion system to produce electricity. For troughs, 7.5 feet wide, an equation for the cross-section is: 16y2 = 120x – 225 (a) Find the intercepts of the graph of the equation (b) Test for symmetry with respect to the x-axis, y-axis, and origin

13 Application: Cigarette Use
A study by the Partnership for a Drug-Free America indicated that, in 1998, 42% of teens in grades 7 through 12 had recently used cigarettes. A similar study in 2005 indicated that 22% of such teens had recently used cigarettes. Write a linear equation that relates the percent of teens y to the number of years after 1998, x. Find the intercepts of the graph of your equation. Do the intercepts have any meaningful interpretation? Use your equation to predict the percent for the year Is this result reasonable?

14 2.5 Proportions & Variation
Proportion equality of 2 ratios. Proportions are used to solve problems in everyday life. If someone earns $100 per day, then how many dollars can the person earn in 5 days? x (x)(1) = (100)(5) x = 2. If a car goes 210 miles on 10 gallons of gas, the car can go 420 miles on X gallons (210)(x) = (420)(10) x (210)(x) = 4200 x = / = 20 gallons If a person walks a mile in 16 min., that person can walk a half mile in x min. x (x)(1) = ½(16) ½ x = 8 minutes = = =

15 Direct Variation y = kx y is directly proportional to x.
y varies directly with x k is the constant of proportionality Example: y = 9x (9 is the constant of proportionality) Let y = Your pay Let x – Number of Hours worked Your pay is directly proportional to the number of hours worked. Example1: Salary (L) varies directly as the number of hours worked (H). Write an equation that expresses this relationship. Salary = k(Hours) L = kH Example 2: Aaron earns $200 after working 15 hours. Find the constant of proportionality using your equation in example1.. 200 = k(15) So, k = 200/15 = 13.33

16 Inverse Variation y = k y is inversely proportional to x x y varies inversely as x Example: y varies inversely with x. If y = 5 when x = 4, find the constant of proportionality (k) 5 = k So, k = 20 4 Example: P. 199 #7 : F varies inversely with d2; F = 10 when d = 5 F = k/ d2 10 = k/52 10 = k/25 K = 250 => F = 250/ d2

17 Another Example (Inverse Variation)
y = k y is inversely proportional to x x y varies inversely as x P. 197: Example 2: The maximum weight W that can be safely supported by a 2-inch by 4-inch piece of point varies inversely with its length L. Experimenters indicate that the maximum weight that a 10 foot long 2 x 4 Piece of pine can support is 500 lbs. Write a general formula relating the Maximum weight W that can be safely supported by a length of 25 feet. W = k/L So, = k/10 => k = Thus, W = 5000/L So, Maximum weight safely supported for Length of 25ft is: W = 5000/25 = 200 lbs.

18 Direct Variation with Power
y = kxn y is directly proportional to the nth power of x Example: Distance varies directly as the square of the time (t) Distance = kt2 D = kt2 Joint Variation y = kxp y varies jointly as x and p

19 Example: (Joint Variation)
y = kxp y varies jointly as x and p P. 198 Example4: The force F of the wind on a flat surface positioned at a right angle To the direction of the wind varies jointly with the area A of the Surface and the square of the speed v of the wind. A wind of 30 miles per hour blowing on a window measuring 4 ft By 5 ft has a force of 150 lbs. What is the force on a window measuring 3 ft by 4 ft caused by a wind of 50 mph? F = kAv A = 4 x 5 = v = 30 150 = k (20)(900) 150 = 18000k K = 150/18000 = 1/120 F = (1/120)Av2 , so, when wind = 50mph on 3 x 4 (A = 12), F = (1/120)(12)(2500) = 250lbs

20 Example: Combined Variation
P. 199 S#13 The square of T varies directly with the cube of A and Inversely with the square of D T = 2 when A = 2 and D = 4. Write a general formula to describe each variation T2 = kA = k(8) k = 64  k = 8 D Thus, T2 = 8A3 D2


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