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Trigonometric Functions - Contents

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Presentation on theme: "Trigonometric Functions - Contents"— Presentation transcript:

1 Trigonometric Functions - Contents
Radian Measure Area/Circumference/Length of Arc Area of a Sector Area of a minor segment Small Angles Trigonometric Results Trigonometric Graphs Graphical Solutions Derivatives of Trigonometric Functions Integrals of Trigonometric Functions (Right Click Mouse  Pointer Options  Arrow Options  Visible)

2 Radian Measure 1 Unit 1 Unit 1c One radian is the angle that a one unit arc makes with centre of a unit circle. Proof Circumference = 2πr 2π = 360o π = 180o = 2π (1) π radians = 180o = 2π  The circumference is 2π

3 Radian Measure Conversions
Example 1 Convert into degrees. 3 Example 2 Convert 45o into radians. 3 = 5x180 3 π = 180o = 300o 180o = π radians 1o = π/180 radians Example 3 Convert 1.6c into degrees. 45o = π/180 x 45 radians = 45π/180 radians π radians = 180o = π/4 radians 1 radians = 180/π deg 1.6 radians = 180/π x 1.6 deg = 91o 40’

4 Area/Circumference/Length of Arc
Circumference = 2r = D Area = r2 r Length of Arc l = r  ( is in radians)

5 Area/Circumference/Length of Arc
Circumference = 2r = D = 2 x 3 = 6 (exact) 4 ≈ 18.8 cm (Approximate) Area = r2 3 cm =  x 32 = 9 (exact) Length of Arc ≈ 28.3 cm2 (Approximate) l = r  ( is in radians) = 3 x /4 = 3/4 (exact) ≈ 2.4 cm (Approximate)

6 Area of a Sector Area of Sector A = ½ r2  Proof Example
( is in radians) Area of Sector Area of Circle = Angle  Revolution Example Find the area of a sector with radius 3cm and angle /6. A r2 = 2 A =  r2 2 A = ½ r2  A = ½ r2  = ½ 32 x /6. = 3/4 cm2. ≈ cm2.

7 Area of a Minor Segment Area of Sector A = ½ r2 ( - sin ) Example
b a Area = ½ab sin  A = ½ r2 ( - sin ) ( is in radians) Example Find the area of a minor segment formed with radius 3cm and angle /6. Proof Area of Minor Segment = Area of Sector - Triangle = ½ r2  - ½ r2 sin  = ½ r2 ( - sin ) = ½ r2 ( - sin ) = ½ 32 x (/6 - sin /6) = ½ 32 x (/6 - ½) = (3/4 – 3/8)cm2 ≈ cm2.

8 What happens to a/h as x 0.
Small Radian Angles For small angles Sin x ≈ x h Tan x ≈ x x o a=1 Cos x ≈ 1 Therefore Cos x = a/h lim Sin x = 1 x x0 What happens to a/h as x 0. lim Tan x = 1 x x0 a/h  1/1 1

9 What happens to o/h as x 0.
Small Radian Angles For small angles Sin x ≈ x h Tan x ≈ x x o a=1 Cos x ≈ 1 Therefore Sin x = o/h lim Sin x = 1 x x0 What happens to o/h as x 0. lim Tan x = 1 x x0 o/h x  0/1  0

10 What happens to o/a as x 0.
Small Radian Angles For small angles Sin x ≈ x h Tan x ≈ x x o a=1 Cos x ≈ 1 Therefore Tan x = o/a lim Sin x = 1 x x0 What happens to o/a as x 0. lim Tan x = 1 x x0 o/a  0/1  0

11 Small Radian Angles Example: Evaluate: lim Sin 5x x lim Sin 5x
= lim 5(Sin 5x) 5x x0 5 lim (Sin 5x) 5x x0 = = 5 x 1 = 5

12 Trigonometric Results
π/2 π - θ θ 2nd 1st S A Note: π=180o π T C 3rd 4th π + θ 2π - θ 3π/2

13 Trigonometric Results
Sin π/3 = √3/2 Sin π/6 = 1/2 Cos π/3 = 1/2 Cos π/6 = √3/2 60o π/3 Tan π/3 = √3 Tan π/6 = 1/√3 π/6 2 2 √3 60o π/3 60o π/3 1 2 π/3 = 60o π/6 = 30o

14 Trigonometric Results
Sin π/4 = 1/√2 Cos π/4 = 1/√2 π/4 45o Tan π/4 = 1 √2 1 π/4 45o 1 π/4 = 45o

15 Trigonometric Results
A S C T Sin is -ve in the 3rd Quadrant. Find the exact value of: 4 5x180o 4 Sin Sin = = Sin 225o = Sin (180o + 45o) = -Sin 45o = -1 √2

16 Trigonometric Results
Solve for 0 ≤ θ ≤ 2π A S C T Evaluate Sin θ = 1/2 Sin is +ve in the 1st & 2nd Quadrants. θ = 30o 30o 2 1 θ = π/6 θ = π - π/6 θ = 5π/6

17 Trigonometric Graphs y = sin(x) π/2 3π/2 Geogebra

18 Trigonometric Graphs y = cos(x) π/2 3π/2 Geogebra

19 Trigonometric Graphs y = tan(x) π/2 3π/2 Geogebra

20 Trigonometric Graphs y = cosec(x) π/2 3π/2 Geogebra

21 Trigonometric Graphs y = sec(x) π/2 3π/2 Geogebra

22 Trigonometric Graphs y = cot(x) π/2 3π/2 Geogebra

23 Trigonometric Graphs The a Sin x Family of Curves y = sin(x)
Geogebra

24 Trigonometric Graphs The Sin bx Family of Curves y = sin 3x y = sin 2x
Geogebra

25 Trigonometric Graphs The Sin x + c Family of Curves y = sin x
Geogebra

26 Graphical Solution Graphical solve y = cos x and y = x y = x y = cos x
One Solution π/4 π/2

27 Derivative of Trigonometric Functions
Function of Function Rule Derivative Sin x d dx [sin f(x)] = f’(x) cos f(x) d dx (sin x) = cos x Cos x d dx (cos x) = sin x d dx [cos f(x)] = -f’(x) sin f(x) Tan x d dx (tan x) = sec2 x d dx [tan f(x)] = f’(x) sec2 f(x)

28 Derivative of Trigonometric Functions
Derivative Examples Sin 4x d dx (sin 4x) = 4 cos 4x d dx [sin f(x)] = f’(x) cos f(x) Tan (3x + 1) d dx [tan (3x + 1)] = 3 sec2 (3x + 1) d dx [tan f(x)] = f’(x) sec2 f(x) Cos (x2 - 2x + 1) d dx [cos (x2 - 2x + 1)] = -(2x - 2) sin (x2 -2x + 1) = 2(1 - x) sin (x2 -2x + 1) d dx [cos f(x)] = -f’(x) sin f(x)

29 Integrals of Trigonometric Functions
Function of Function Rule Integral Sin x sin x dx = - cos x + C sin (ax +b) dx = - 1/a cos (ax + b) + C Cos x cos x dx = sin x + C cos (ax +b) dx = 1/a sin (ax + b) + C Tan x sec2 x dx = tan x + c sec2 (ax +b) dx = 1/a tan (ax + b) + C

30 Integral of Trigonometric Functions
Integration Examples sin (ax +b) dx = - 1/a cos (ax + b) + C sin (3x +2) dx = -1/3 cos (3x + 2) + C

31 Integral of Trigonometric Functions
Integration Examples sin x dx = - cos x + C sin x dx = π 2 - cos x π 2 = - cos (-cos 0) π 2 = 0 – (-1) = 1


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