1. Acceleration & Circular Motion Centripetal Acceleration Tangential Acceleration

2. Centripetal acceleration a c tangential acceleration is how fast the speed changes Centripetal acceleration is how fast the velocity changes because of its direction change.

4. Centripetal acceleration a c vovo vfvf v f =v o +v v f = v o = v

5. Centripetal acceleration a c vovo vfvf v f =v o +v v f = v o = v vfvf v

6. Centripetal acceleration a c vovo vfvf v f =v o +v v f = v o = v vfvf v r r s

7. Centripetal acceleration a c vovo vfvf vfvf v r r s

8. Centripetal acceleration Inward

9. Tangential Acceleration tangential acceleration is how fast the speed changes a T = change in speed (time taken)

10. Fig. 4.18, p.94

11. Fig. 4.19, p.95

12. Fig. 4.19a, p.95

13. Fig. 4.19b, p.95

14. A car rounds a corner of radius 12.0 m at a speed of 6 m/s while also pressing on the gas. If the cars speed is increasing at a rate of 4 m/s^2, what is the magnitude of the cars total acceleration?

15. While traveling due southward at a speed of 20 m/s a cars acceleration is 6.0 m/s^2 directed 60 degrees North of East. A) what is the radius of the cars path? B) is the car speeding up or slowing down?

16. Fig. 4.21, p.96 Sue PeteBetty conveyor ground V s/g =0 V c/g =10 m/s V P/c =5 m/sV B/c =0 m/s V P/g =?

17. Fig. 4.21, p.96 Sue PeteBetty conveyor ground V s/g =0 V c/g =10 m/s V P/c =5 m/sV B/c =0 m/s V P/g = V P/c+ V c/g =15 m/s

18. Fig. 4.21, p.96 Sue PeteBetty conveyor ground V s/g =0 V c/g =10 m/s V P/c =-5 m/sV B/c =10 m/s V P/B =?

19. Fig. 4.21, p.96 Sue PeteBetty conveyor ground V s/g =-8 V c/g =10 m/s V P/c =5 m/sV B/c =0 m/s V P/S =?

20. Fig. 4.21, p.96 Sue PeteBetty conveyor ground V s/g =-8 V c/g =10 m/s V P/c =5 m/sV B/c =0 m/s V P/S = V P/c + V c/g + V g/S

21. Fig. 4.22, p.97

22. Fig. 4.22a, p.97

23. Fig. 4.22b, p.97

24. Fig. 4.23, p.97

25. Fig. 4.24, p.98

26. Fig. 4.25, p.99