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Determine the force of gravitational attraction between the earth (m = 5.98 x 10^24 kg) and a 70-kg physics student if the student is standing at sea level,

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Presentation on theme: "Determine the force of gravitational attraction between the earth (m = 5.98 x 10^24 kg) and a 70-kg physics student if the student is standing at sea level,"— Presentation transcript:

1 Determine the force of gravitational attraction between the earth (m = 5.98 x 10^24 kg) and a 70-kg physics student if the student is standing at sea level, a distance of 6.38 x 10^6 m from earth's center. Determine the force of gravitational attraction between the earth (m = 5.98 x 10^24 kg) and a 70-kg physics student if the student is in an airplane at 40000 feet above earth's surface. This would place the student a distance of 6.39 x 10^6m from earth's center. Prove that the acceleration of gravity on Earth's Surface is 9.8 around m/s^2 using the Law of Gravitation Guiding Conceptual Questions: Who discovered the Universal Law of Gravitation? How does this law affect our solar system? Because you have mass and everything around you has mass, you are inherently attracted to everything around you. (Yes even students, even students you can't stand).. explain why you can't feel this gravitational attraction on a daily basis. How does circular motion and centripital force and centrepital acceleration relate to this law? Guiding Mathematics Questions: Law of Gravitation Review: Circular Motion Review: What is the difference between the centripetal force and the centrifugal force? Where does the centripetal force and acceleration point? Compare the centripetal force and acceleration experienced by a driver who makes a sharp turn v.s a wide turn at the same velocity. How does he friction created by a car's tires affect your ability as the driver to turn? (Dry/Wet/Snow) Guiding Conceptual Questions: Guiding Mathematics Questions: A 0.5 kg ball, attached to the end of a horizontal cord, is rotated in a circle of radius 1.6 m on a frictionless horizontal surface. If the cord will break when the tension on it exceeds 98 N, what is the maximum speed it can have? A ball on the end of a string is revolved at a uniform rate ina vertical circle of radius 76 cm,. If its speed is 4.5 m/s and its mass in 0.45 kg, calculate the tension in the string when the ball is a) at the top of tits path, b) at the bottom of its path. How fast in RPM must a centrifuge rotate if a particle 10.0 cm from its axis of rotation is to experience an acceleration of 122,000 g';s? TEST FRIDAY! TEST FRIDAY! A 900-kg car moving at 10 m/s takes a turn around a circle with a radius of 25.0 m. Determine the acceleration and the net force acting upon the car. A 95-kg halfback makes a turn on the football field. The halfback sweeps out a path that is a portion of a circle with a radius of 12-meters. The halfback makes a quarter of a turn around the circle in 2.1 seconds. Determine the speed, acceleration and net force acting upon the halfback. What is the maximum velocity this car can go around this bend with out losing traction? Radius = 120 m, Mass of Car = 2300 kg, Coefficient of Friction = 0.8 Orbital Review: Guiding Conceptual Questions: Who discovered this relationship? Guiding Mathematics Questions: A satellite wishes to orbit the earth at a height of 100 km (approximately 60 miles) above the surface of the earth. Determine the speed, acceleration and orbital period of the satellite. (Given: M(earth) = 5.98 x 10^24 kg, R(earth) = 6.37 x 10^6 m)


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