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Microwave Radiometry. 2Outline Introduction Thermal Radiation Black body radiation –Rayleigh-Jeans Power-Temperature correspondence Non-Blackbody radiation.

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Presentation on theme: "Microwave Radiometry. 2Outline Introduction Thermal Radiation Black body radiation –Rayleigh-Jeans Power-Temperature correspondence Non-Blackbody radiation."— Presentation transcript:

1 Microwave Radiometry

2 2Outline Introduction Thermal Radiation Black body radiation –Rayleigh-Jeans Power-Temperature correspondence Non-Blackbody radiation –T B, brightness temperature –T AP, apparent temperature –T A, antenna temperature More realistic Antenna –Effect of the beam shape –Effect of the losses of the antenna

3 3 Thermal Radiation All matter (at T>0K) radiates electromagnetic energy! Atoms radiate at discrete frequencies given by the specific transitions between atomic energy levels. (Quantum theory) –Incident energy on atom can be absorbed by it to move an e- to a higher level, given that the frequency satisfies the Bohr’s equation. –f = ( E 1 - E 2 ) /h where, h = Planck’s constant = 6.63x10 -34 J

4 4 Thermal Radiation absorption => e- moves to higher level emission => e- moves to lower level (collisions cause emission) Absortion Spectra = Emission Spectra atomic gases have (discrete) line spectra according to the allowable transition energy levels.

5 5 Molecular Radiation Spectra Molecules consist of several atoms. They are associated to a set of vibrational and rotational motion modes. Each mode is related to an allowable energy level. Spectra is due to contributions from; vibrations, rotation and electronic transitions. Molecular Spectra = many lines clustered together; not discrete but continuous.

6 6 Atmospheric Windows Absorbed (blue area) Transmitted (white)

7 7 Radiation by bodies (liquids - solids) Liquids and solids consist of many molecules which make radiation spectrum very complex, continuous; all frequencies radiate. Radiation spectra depends on how hot is the object as given by Planck’s radiation law.

8 8 CommonTemperature -conversion 90 o F = 305K = 32 o C 70 o F = 294K = 21 o C 32 o F = 273K=0 o C 0 o F = 255K = -18 o C -280 o F = 100K = -173 o C

9 9 Spectral brightness B f [Planck]

10 10Sun

11 11 Solar Radiation T sun = 5,800 K

12 12 Properties of Planck’s Law f m = frequency at which the maximum radiation occurs f m = 5.87 x 10 10 T [Hz] where T is in Kelvins Maximum spectral Brightness B f ( f m ) B f ( f m ) = c 1 T 3 where c 1 = 1.37 x 10 -19 [W/(m 2 srHzK 3 )]

13 13 Stefan-Boltzmann Total brightness of body at T Total brightness is 20M W/m 2 sr 13M W/m 2 sr 67% where the Stefan-Boltzmann constant is  = 5.67x10 -8 W/m 2 K 4 sr

14 14 Blackbody Radiation - given by Planck’s Law Measure spectral brightness B f [Planck] For microwaves, Rayleigh-Jeans Law, condition hf/kT<<1 (low f ), then e x -1 x At T<300K, the error < 1% for f<117GHz), and error< 3% for f<300GHz)

15 15 Rayleigh-Jeans Approximation Rayleigh-Jeans f<300Hz  >2.57mm) T< 300K Mie Theory frequency BfBf Wien

16 16 Total power measured due to objects Brightness, B f B=Brightness=radiance [W/m 2 sr] B f = spectral brightness (B per unit Hz) B = spectral brightness (B per unit cm) F n = normalized antenna radiation pattern  = solid angle [steradians] A r =antenna aperture on receiver

17 17 Power-Temperature correspondence

18 18 Analogy with a resistor noise Antenna Pattern T R T Analogous to Nyquist; noise power from R Direct linear relation power and temperature *The blackbody can be at any distance from the antenna.

19 19 Non-blackbody radiation But in nature, we find variations with direction, B(  ) Isothermal medium at physical temperature T T B (  ) =>So, define a radiometric temperature (bb equivalent) T B For Blackbody,

20 20 Emissivity, e The brightness temperature of a material relative to that of a blackbody at the same temperature T. (it’s always “cooler”) T B is related to the self-emitted radiation from the observed object(s).

21 21 Quartz versus BB at same T Emissivity depends also on the frequency.

22 22 Ocean color Pure Water is turquoise blue The ocean is blue because it absorbs all the other colors. The only color left to reflect out of the ocean is blue. “Sunlight shines on the ocean, and all the colors of the rainbow go into the water. Red, yellow, green, and blue all go into the sea. Then, the sea absorbs the red, yellow, and green light, leaving the blue light. Some of the blue light scatters off water molecules, and the scattered blue light comes back out of the sea. This is the blue you see.” Robert Stewart, Professor Department of Oceanography, Texas A&M University

23 23 Apparent Temperature, T AP Is the equivalent T in connection with the power incident upon the antenna T AP (  )

24 24 Antenna Temperature, T A Noise power received at antenna terminals.

25 25 Antenna Temperature (cont…) Using we can rewrite as for discrete source such as the Sun.

26 26 Antenna Beam Efficiency,  M Accounts for sidelobes & pattern shape T A =  M T ML +(1-  M )T SL

27 27 Radiation Efficiency,  l Heat loss on the antenna structure produces a noise power proportional to the physical temperature of the antenna, given as T N = (1-  l )T o The  l accounts for losses in a real antenna T A ’=  l T A +(1-  l )T o TATA TA’TA’

28 28 Combining both effects T A ’=  l  M T ML +  l (1-  M )T SL +(1-  l )T o *where, T A ’ = measured, T ML = to be estimated T ML = 1/(  l  M) T A’ + [(1-  M )/  M] T SL +(1-  l )T o/  l  M


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