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Arithmetic Sequences Lesson 1.3. Arithmetic Sequence This is a sequence in which the difference between each term and the preceding term is always constant.

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Presentation on theme: "Arithmetic Sequences Lesson 1.3. Arithmetic Sequence This is a sequence in which the difference between each term and the preceding term is always constant."— Presentation transcript:

1 Arithmetic Sequences Lesson 1.3

2 Arithmetic Sequence This is a sequence in which the difference between each term and the preceding term is always constant. {10, 7, 4, 1, -2, -5,…} Is {2, 4, 7, 11, 16,…} an arithmetic sequence? Recursive Form of arithmetic sequence u n = u n-1 + d For some constant d and all n ≥ 2

3 Example If {u n } is an arithmetic sequence with u 1 = 2.5 and u 2 = 6 as its first two terms a. Find the common difference b. Write the sequence as a recursive function c. Give the first six terms of the sequence d. Graph the sequence

4 Explicit Form of Arithmetic Sequence In an arithmetic sequence {u n } with common difference d, u n = u 1 + (n-1)d for every n ≥ 1. If u 1 = -5 and d = 3 we can find the explicit form by, u n = -5 + (n-1)3 = -5 + 3n – 3… leaving us with the explicit form of 3n - 8

5 Example If we wanted to know the 38 th term of the arithmetic sequence whose first three terms are 15, 10, and 5, how would we do that?

6 Here’s How u n = u 1 + (n-1)d = 15 + (38-1)(-5) = 15 + (-5)(37) = 15 + -185 = -170 Lets look at example 6 on page 24 because it is far too exhaustive to write down!

7 Summation Notation What is the sum of this sequence?

8 Graphing Calculator Exploration We are going to use the sum sequence key on our graphing calculators Find the sum of this little diddy

9 Partial Sums of Arithmetic Sequences If {u n } is an arithmetic sequence with common difference d, then for each positive integer k, the kth partial sum can be found by using either of the following formulas There is a proof on this on page 27…if anybody really cares

10 Example Find the 14 th partial sum of the arithmetic sequence 21, 15, 9, 3,… U 14 = u 1 + (14 – 1)(-6) = 21 + (13)(-6) = 21 + (-78) = -57

11 Find the Sum of all multiples of 4 from 4 to 404! We know that we are adding 4 + 8 + …, so 4x1, 4x2, 4x3, … and we can take 404 ÷ 4 to get the 101 term. What this means is there is 101 multiples of 4 in between 4 and 404 u 1 =4, k=101, and u 101 = 404! Use form 1

12 Here is a little story about Larry Larry owns an automobile dealership. He spends $18,000 on advertising during the first year, and he plans to increase his advertising expenditures by $1400 in each subsequent year. How much will Larry spend on advertising during the first 9 years?

13 Now…Get To Work Slackers!


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