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6.1 Solving Systems by Graphing: System of Linear Equations: Two or more linear equations Solution of a System of Linear Equations: Any ordered pair that.

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Presentation on theme: "6.1 Solving Systems by Graphing: System of Linear Equations: Two or more linear equations Solution of a System of Linear Equations: Any ordered pair that."— Presentation transcript:

1 6.1 Solving Systems by Graphing: System of Linear Equations: Two or more linear equations Solution of a System of Linear Equations: Any ordered pair that makes all the equations in a system true. Trend line: Line on a scatter plot, drawn near the points, that shows a correlation

2 Consistent: System of equations that has at least one solution. 1) Could have the same or different slope but they intersect. 2) The point where they meet is a solution

3 Consistent Independent: System of equations that has EXACTLY one solution. 1) Have different slopes 2) Only intersect once 3) The point of intersection is the solution.

4 Consistent Dependent: System of equations that has infinitely many solutions. 1) Have same slopes 2) Same y-intercepts 3) Each point is a solution.

5 Inconsistent: System of equations that has no solutions. 1) Have same slopes 2) different y-intercepts 3) No solutions

6 Remember:

7

8 GOAL:

9 SOLVING A SYSTEM BY GRAPHING: To solve a system by graphing we must: 1) Write the equations in slope-intercept form (y=mx+b) 2) Graph the equations 3) Find the point of intersection 4) Check

10 Ex: What is the solution of the system? Use a graph to check your answer.

11 SOLUTION: 1) Write the equations in slope-intercept form (y=mx+b)

12 SOLUTION:2) Graph the equations

13 SOLUTION:3) Find the solution Looking at the graph, we see that these two equations intersect at the point : (-2, 0)

14 SOLUTION:4) Check We know that (-2,0) is the solution from our graph.

15 YOU TRY IT: What is the solution of the system? Use a graph to check your answer.

16 SOLUTION: 1) Write the equations in slope-intercept form (y=mx+b)

17 SOLUTION:2) Graph the equations

18 SOLUTION:3) Find the solution Looking at the graph, we see that these two equations intersect at the point : (2,4)

19 SOLUTION:4) Check We know that (2,4) is the solution from our graph.

20 SYSTEM WITH INFINITELY MANY SOLUTIONS: Using the same procedure we can see that sometimes the system will give us infinitely many solutions (any point will make the equations true). Ex: What is the solution to the system? Use a graph.

21 SOLUTION: 1) Write the equations in slope-intercept form (y=mx+b)

22 SOLUTION:2) Graph the equations Notice: Every point of one line is on the other.

23 SYSTEM WITH NO SOLUTIONS: Using the same procedure we can see that sometimes the system will give us infinitely many solutions (any point will make the equations true). Ex: What is the solution to the system? Use a graph.

24 SOLUTION: 1) Write the equations in slope-intercept form (y=mx+b)

25 SOLUTION:2) Graph the equations Notice: These lines will never intersect. NO SOLUTIONS.

26 WRITING A SYSTEM OF EQUATIONS: Putting ourselves in the real world, we must be able to solve problems using systems of equations. Ex: One satellite radio service charges $10.00 per month plus an activation fee of $20.00. A second service charges $11 per month plus an activation fee of $15. For what number of months is the cost of either service the same?

27 SOLUTION: Looking at the data we must be able to do 5 things: 1) Relate- Put the problem in simple terms. Cost = service charge + monthly dues 2) Define- Use variables to represent change: Let C = total Cost Let x = time in months

28 SOLUTION: (continue) 3) Write- Create two equations to represent the events. Satellite 1: C = $10 x + $20 4) Graph the equations: Remember to put them in slope/intercept form (y = mx + b) The two equations are already in y=mx+b form. Satellite 2: C = $11 x + $15

29 SOLUTION: 4) Continue Cost 1 23 4 10 20 30 40 50 60 70 80 90 100 5 6 Months

30 SOLUTION: 5) Interpret the solution. Notice: These lines intersect at at (5, 70). Cost 123 4 10 20 30 40 50 60 70 80 90 100 5 6 This means that the two satellite services will cost the same in 5 months and $70. Months

31 YOU TRY IT: Scientists studied the weights of two alligators over a period of 12 months. The initial weight and growth rate of each alligator are shown below. After how many months did the two alligators weight the same?

32 SOLUTION: Looking at the data, Here are the 5 things we must do: 1) Relate- Put the problem in simple terms. Total Weight = initial weight + growth per month. 2) Define- Use variables to represent change: Let W = Total weight Let x = time in months

33 SOLUTION: (continue) 3) Write- Create two equations to represent the events. Alligator 1: W = 1.5x + 4 4) Graph the equations: Remember to put them in slope/intercept form (y = mx + b) The two equations are already in y=mx+b form. Alligator 2: W= 1.0 x + 6

34 SOLUTION: 4) Continue Weight 1 23 4 1 2 3 4 5 6 7 8 9 10 5 6 Months

35 SOLUTION: 5) Interpret the solution. Notice: These lines intersect at at (4, 10) This means that the two Alligators will Weight 10 lbs after 4 months. Months Weight 123 4 1 2 3 4 5 6 7 8 9 10 5 6

36 VIDEOS: Solve by Graphing https://www.khanacademy.org/math/algebra/syst ems-of-eq-and-ineq/fast-systems-of- equations/v/solving-linear-systems-by-graphing

37 CLASSWORK: Page 363-365 Problems: As many as needed to master the concept.


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