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Solving Linear Systems

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Presentation on theme: "Solving Linear Systems"— Presentation transcript:

1 Solving Linear Systems
3-1,2 Solving Linear Systems Warm Up (Slide #2-3) Objective and Standards (Slide #4) Vocab (Slide #5–8) Lesson Presentation (Slide #9–31) Text Questions (NONE) Worksheets 3.1A, 3.2A (Slide #32) Lesson Quiz (Slide #33-34) Holt Algebra 2

2 Solving Linear Systems
3-1,2 Solving Linear Systems Warm Up Use substitution to determine if (1, –2) is an element of the solution set of the linear equation. no yes 1. y = 2x + 1 2. y = 3x – 5 Write each equation in slope-intercept form. 4. 4y – 3x = 8 3. 2y + 8x = 6 y = –4x + 3

3 Solving Linear Systems
3-1,2 Solving Linear Systems Warm Up Determine if the given ordered pair is an element of the solution set of 2x – y = 5 3y + x = 6 2. (–1, 1) no 1. (3, 1) yes Solve each equation for y. 3. x + 3y = 2x + 4y – 4 y = –x + 4 4. 6x y = 3y + 2x – 1 y = 2x + 3

4 Solving Linear Systems
3-1,2 Solving Linear Systems Objectives 1. Solve systems of linear equations with: Graphs and tables Substitution Elimination 2. Determine whether there will be one, none, or an infinite number of solutions by noting characteristics of each equation.

5 Solving Linear Systems
3-1,2 Solving Linear Systems Vocabulary system of equations linear system substitution elimination linear combinations

6 Solving Linear Systems
3-1,2 Solving Linear Systems A system of equations is a set of two or more equations containing two or more variables. A linear system is a system of equations containing only linear equations. A line is an infinite set of points that are solutions to a linear equation. The solution of a system of equations is the set of all points that satisfy each equation.

7 Solving Linear Systems
3-1,2 Solving Linear Systems There are two aspects of substitution: In one, a possible solution (ordered pair) is given and you simply substitute its x and y values into each equation to see if that point satisfies both. In the other, you substitute the equivalent expression for a variable from one equation into the other equation, solve for one variable, then use that value to solve for the other variable. (I know…it sounds all so confusing, but it’s really easy.)

8 Solving Linear Systems
3-1,2 Solving Linear Systems You can also solve systems of equations with the elimination method. With elimination, you get rid of one of the variables by adding or subtracting equations. You may have to multiply one or both equations by a number to create variable terms that can be eliminated. The elimination method is sometimes called the addition method or linear combinations. Reading Math

9 Solving Linear Systems
3-1,2 Solving Linear Systems Points to remember about linear equations and systems: On the graph of the system of two equations, the solution is the set of points where the lines intersect. A point is a solution to a system of equation if the x- and y-values of the point satisfy both equations.

10 Example 1A: Verifying Solutions of Linear Systems
3-1,2 Solving Linear Systems Example 1A: Verifying Solutions of Linear Systems To see if a given point is a solution to a linear system, substitute the (x,y) values into both equations. For example… “Is (1,3) the solution to this linear system?” (1, 3); x – 3y = –8 3x + 2y = 9 Ans: YES

11 Solving Linear Systems
3-1,2 Solving Linear Systems Check It Out! Example 1b Is (5,3) an element of the solution set for the system of equations? (5, 3); 6x – 7y = 1 3x + 7y = 5 Ans: NO

12 Solving Linear Systems
3-1,2 Solving Linear Systems Example 2A: Solving Linear Systems by Using Graphs and Tables on your graphing calculator Solve the system. Check your answer. First, solve each equation for y, then graph both: 2x – 3y = 3 y + 2 = x On the graph, the lines appear to intersect at the ordered pair (3, 1) Use the calculator’s “Table” or “Trace” function to verify. Sol’n: (3,1)

13 Solving Linear Systems
3-1,2 Solving Linear Systems Check It Out! Example 2b Use a graph and a table to solve the system. Check your answer. First, solve each equation for y. x + y = 8 2x – y = 4 Sol’n: (4, 4)

14 Solving Linear Systems
3-1,2 Solving Linear Systems Different Slopes will have ONE solution Same Slopes and Same Y-int. will have INFINITE Sol’ns. Same Slopes but Different Y-int. will have NO Solutions.

15 Solving Linear Systems
3-1,2 Solving Linear Systems An identity, such as 0 = 0, 8 = 8, -7 = -7, etc… is always true and indicates infinite solutions. A contradiction, such as 1 = 3, 5 = 9, -8 = 8, etc… is never true and indicates no solution. Remember!

16 Example 4: Summer Sports Application
3-1,2 Solving Linear Systems Example 4: Summer Sports Application One golf course charges $20 to rent golf clubs plus $55 per hour for golf cart rental. A different course charges $35 to rent clubs plus $45 per hour to rent a cart. Both places allow rentals in ½hr. increments. Q: For what number of hours is the cost of renting clubs and a cart the same for each course?

17 Solving Linear Systems
3-1,2 Solving Linear Systems Example 4 Continued Step 1 Write an equation for the cost of renting clubs and a cart at each golf course. Let x represent the number of hours and y represent the total cost in dollars. City Park Golf Course: y = 55x + 20 Sea Vista Golf Course: y = 45x + 35 Sol’n: 1.5hrs

18 Solving Linear Systems
3-1,2 Solving Linear Systems Check It Out! Example 4 Ravi is comparing the costs of long distance calling cards. To use card A, it costs $0.50 to connect and then $0.05 per minute. To use card B, it costs $0.20 to connect and then $0.08 per minute. For what number of minutes does it cost the same amount to use each card for a single call? Step 1 Write an equation for the cost for each of the different long distance calling cards. Let x represent the number of minutes and y represent the total cost in dollars. Card A: y = 0.05x Card B: y = 0.08x

19 Solving Linear Systems
3-1,2 Solving Linear Systems Check It Out! Example 4 Card A: y = 0.05x Card B: y = 0.08x Step 2 Here’s a situation where, since both are equal to “y”, you can set the two equations equal to each other. .05x = .08x + .20 -.05x x .30 = .03x ÷.03 ÷.03 10 = x So, both plans are the same for a 10minute call

20 Example 1A: Solving Linear Systems by Substitution
3-1,2 Solving Linear Systems Example 1A: Solving Linear Systems by Substitution Use variable substitution to solve the system: y = x – 1 x + y = 7 Step 1: Substitute the equivalent expression for “y” from the first equation in place of “y” in the second equation and solve for “x”. x + y = 7 x + (x – 1) = 7 2x – 1 = 7 2x = 8 x = 4 Then…

21 Solving Linear Systems
3-1,2 Solving Linear Systems Example 1A Continued Step 2: Substitute the x-value into one of the original equations to solve for y. y = x – 1 y = (4) – 1 y = 3 The solution is the ordered pair (4, 3).

22 Solving Linear Systems
3-1,2 Solving Linear Systems Example 1A Continued Check A graph or table supports your answer.

23 Example 1B: Solving Linear Systems by Substitution
3-1,2 Solving Linear Systems Example 1B: Solving Linear Systems by Substitution Use substitution to solve the systems of equations. 2y + x = 4 3x – 4y = 7 y = 2x – 1 3x + 2y = 26 5x + 6y = –9 2x – 2 = –y Sol’n: (3, 1/2) Sol’n: (4,7) Sol’n: (3,-4)

24 Check It Out! Example 1a Continued
3-1,2 Solving Linear Systems Check It Out! Example 1a Continued Check A graph or table supports your answer.

25 Example 2A: Solving Linear Systems by Elimination
3-1,2 Solving Linear Systems Example 2A: Solving Linear Systems by Elimination 3x + 2y = 4 4x – 2y = –18 3x + 5y = –16 2x + 3y = –9 4x + 7y = –25 –12x –7y = 19 Sol’n: (–2, 5) Sol’n: (3,-5) Sol’n: (.75, -4)

26 Solving Linear Systems
3-1,2 Solving Linear Systems Check It Out! Example 2b Use elimination to solve the system of equations. 5x – 3y = 42 8x + 5y = 28 Sol’n: (6,-4)

27 Example 3: Solving Systems with Infinitely Many or No Solutions
3-1,2 Solving Linear Systems Example 3: Solving Systems with Infinitely Many or No Solutions 3x + y = 1 56x + 8y = –32 6x + 3y = –12 2y + 6x = –18 7x + y = –4 2x + y = –6 Sol’n: NONE Sol’n: INFINITE Sol’n: NONE

28 Example 4: Zoology Application
3-1,2 Solving Linear Systems Example 4: Zoology Application A veterinarian needs 60 pounds of dog food that is 15% protein. He will combine a beef mix that is 18% protein with a bacon mix that is 9% protein. How many pounds of each does he need to make the 15% protein mixture? Let x present the amount of beef mix in the mixture. Let y present the amount of bacon mix in the mixture. Write one equation based on the amount of dog food Write another equation based on the amount of protein THEN…

29 Solving Linear Systems
3-1,2 Solving Linear Systems Example 4 Continued x + y = 60 0.18x +0.09y = 9 Solve the system. Sol’n: (40, 20)

30 Solving Linear Systems
3-1,2 Solving Linear Systems Check It Out! Example 4 A coffee blend contains Sumatra beans which cost $5/lb, and Kona beans, which cost $13/lb. If the blend costs $10/lb, how much of each type of coffee is in 50 lb of the blend? Let x represent the amount of the Sumatra beans in the blend. Let y represent the amount of the Kona beans in the blend. Write one equation based on the amount of each bean Write another equation based on cost of the beans: THEN…

31 Check It Out! Example 4 Continued
Solving Linear Systems 3-1,2 Check It Out! Example 4 Continued x + y = 50 5x + 13y = 500 Solve the system. Sol’n: (18.75, 31.25)

32 Solving Linear Systems
3-1,2

33 Solving Linear Systems
3-1,2 Solving Linear Systems Lesson Quiz: Part I Use substitution to determine if the given ordered pair is an element of the solution set of the system of equations. x + 3y = –9 x + y = 2 2. (–3, –2) 1. (4, –2) y – 2x = 4 y + 2x = 5 Solve the system using a table and graph. Check your answer. x + y = 1 3. 3x –2y = 8

34 Solving Linear Systems
3-1,2 Solving Linear Systems Lesson Quiz: Part II Which system has NO solution and which has INFINITE solutions. –4x = 2y – 10 y + 2x = –10 4. 5. y + 2x = –10 y + 2x = –10 6. Kayak Kottage charges $26 to rent a kayak plus $24 per hour for lessons. Power Paddles charges $12 for rental plus $32 per hour for lessons. Both places allow rentals in 15min (1/4hr) For what number of hours is the cost of equipment and lessons the same for each company?


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