1. Electrical Principles 1 G5 - ELECTRICAL PRINCIPLES [3 exam questions - 3 groups] G5AResistance; reactance; inductance; capacitance; impedance; impedance matching G5BThe Decibel; current and voltage dividers; electrical power calculations; sine wave root-mean-square (RMS) values; PEP calculations G5CResistors, capacitors, and inductors in series and parallel; transformers

2. Resistance, Impedance and Reactance RESISTANCE IS THE OPPOSITION TO THE FLOW OF DIRECT CURRENT (DC). REPRESENTED AS THE LETTER R REACTANCE IS THE OPPOSITION TO THE FLOW OF ALTERNATING CURRENT (AC) THAT A CAPACITOR OR INDUCTOR PRESENTS. REPRESENTED AS THE LETTER Z IMPEDANCE IS THE OPPOSITION TO THE FLOW OF ALTERNAING CURRENT (AC) AND VARIES AS FREQUENCY VARIES AND MAY INCLUDE X L, X C AND R COMPONENTS. Electrical Principles 2

3. 3 G5A01 What is impedance? A.The electric charge stored by a capacitor B.The inverse of resistance C.The opposition to the flow of current in an AC circuit D.The force of repulsion between two similar electric fields

4. Electrical Principles 4 G5A01 What is impedance? A.The electric charge stored by a capacitor B.The inverse of resistance C.The opposition to the flow of current in an AC circuit D.The force of repulsion between two similar electric fields

5. Electrical Principles 5 Resonant Circuit “Reactance”

6. Electrical Principles 6 G5A02 What is reactance? A.Opposition to the flow of direct current caused by resistance B.Opposition to the flow of alternating current caused by capacitance or inductance C.A property of ideal resistors in AC circuits D.A large spark produced at switch contacts when an inductor is de-energized

7. Electrical Principles 7 G5A02 What is reactance? A.Opposition to the flow of direct current caused by resistance B.Opposition to the flow of alternating current caused by capacitance or inductance C.A property of ideal resistors in AC circuits D.A large spark produced at switch contacts when an inductor is de-energized

8. Electrical Principles 8 G5A03 Which of the following causes opposition to the flow of alternating current in an inductor? A.Conductance B.Reluctance C.Admittance D.Reactance

9. Electrical Principles 9 G5A03 Which of the following causes opposition to the flow of alternating current in an inductor? A.Conductance B.Reluctance C.Admittance D.Reactance Inductor is also called a Coil

10. Electrical Principles 10 G5A04 Which of the following causes opposition to the flow of alternating current in a capacitor? A.Conductance B.Reluctance C.Reactance D.Admittance

11. Electrical Principles 11 G5A04 Which of the following causes opposition to the flow of alternating current in a capacitor? A.Conductance B.Reluctance C.Reactance D.Admittance

12. Electrical Principles 12 G5A05 How does a coil react to AC? A.As the frequency of the applied AC increases, the reactance decreases B.As the amplitude of the applied AC increases, the reactance increases C.As the amplitude of the applied AC increases, the reactance decreases D.As the frequency of the applied AC increases, the reactance increases

13. Electrical Principles 13 G5A05 How does a coil react to AC? D.As the frequency of the applied AC increases, the reactance increases

14. Electrical Principles 14 G5A06 How does a capacitor react to AC? A.As the frequency of the applied AC increases, the reactance decreases B.As the frequency of the applied AC increases, the reactance increases C.As the amplitude of the applied AC increases, the reactance increases D.As the amplitude of the applied AC increases, the reactance decreases

15. Electrical Principles 15 G5A06 How does a capacitor react to AC? A.As the frequency of the applied AC increases, the reactance decreases

16. Electrical Principles 16 G5A07 What happens when the impedance of an electrical load is equal to the internal impedance of the power source? A.The source delivers minimum power to the load B.The electrical load is shorted C.No current can flow through the circuit D.The source can deliver maximum power to the load

17. Electrical Principles 17 G5A07 What happens when the impedance of an electrical load is equal to the internal impedance of the power source? A.The source delivers minimum power to the load B.The electrical load is shorted C.No current can flow through the circuit D.The source can deliver maximum power to the load

18. Electrical Principles 18 G5A08 Why is impedance matching important? A.So the source can deliver maximum power to the load B.So the load will draw minimum power from the source C.To ensure that there is less resistance than reactance in the circuit D.To ensure that the resistance and reactance in the circuit are equal

19. Electrical Principles 19 G5A08 Why is impedance matching important? A.So the source can deliver maximum power to the load B.So the load will draw minimum power from the source C.To ensure that there is less resistance than reactance in the circuit D.To ensure that the resistance and reactance in the circuit are equal

20. Electrical Principles 20 G5A09 What unit is used to measure reactance? A.Farad B.Ohm C.Ampere D.Siemens

21. Electrical Principles 21 G5A09 What unit is used to measure reactance? A.Farad B.Ohm C.Ampere D.Siemens Ohm is also used to measure resistance.

22. Electrical Principles 22 G5A10 What unit is used to measure impedance? A.Volt B.Ohm C.Ampere D.Watt

23. Electrical Principles 23 G5A10 What unit is used to measure impedance? A.Volt B.Ohm C.Ampere D.Watt Same unit of measurement for Reactance, Resistance, Impedance.

24. Electrical Principles 24 G5A11 Why should core saturation of a conventional impedance matching transformer be avoided? A.Harmonics and distortion could result B.Magnetic flux would increase with frequency C.RF susceptance would increase D.Temporary changes of the core permeability could result

25. Electrical Principles 25 G5A11 Why should core saturation of a conventional impedance matching transformer be avoided? A.Harmonics and distortion could result B.Magnetic flux would increase with frequency C.RF susceptance would increase D.Temporary changes of the core permeability could result

26. Electrical Principles 26 G5A12 What is one reason to use an impedance matching transformer? A.To reduce power dissipation in the transmitter B.To maximize the transfer of power C.To minimize SWR at the antenna D.To minimize SWR in the transmission line

27. Electrical Principles 27 G5A12 What is one reason to use an impedance matching transformer? A.To reduce power dissipation in the transmitter B.To maximize the transfer of power C.To minimize SWR at the antenna D.To minimize SWR in the transmission line

28. Impedance Matching Electrical Principles 28

29. Electrical Principles 29 G5A13 Which of the following devices can be used for impedance matching at radio frequencies? A.A transformer B.A Pi-network C.A length of transmission line D.All of these choices are correct

30. Electrical Principles 30 G5A13 Which of the following devices can be used for impedance matching at radio frequencies? A.A transformer B.A Pi-network C.A length of transmission line D.All of these choices are correct

31. Electrical Principles 31 G5A14 Which of the following describes one method of impedance matching between two AC circuits? A.Insert an LC network between the two circuits B.Reduce the power output of the first circuit C.Increase the power output of the first circuit D.Insert a circulator between the two circuits

32. Electrical Principles 32 G5A14 Which of the following describes one method of impedance matching between two AC circuits? A.Insert an LC network between the two circuits B.Reduce the power output of the first circuit C.Increase the power output of the first circuit D.Insert a circulator between the two circuits

33. Amateur Radio Practices 33 Decibel Multipliers The Decibel scale is logarithmic. 3dB represents a 2-fold increase in power, 6dB is 4 fold, 10dB is 10- fold, 20dB is 100-fold. The S-Unit scale on a receiver meter is not an absolute scale and can vary from radio to radio. Although these meters are not calibrated, they can be useful for verifying antenna performance. One “S-Unit” represents a 4-fold change in power or 6dB.

34. Electrical Principles 34 G5B01 A two-times increase or decrease in power results in a change of how many dB? A.2 dB B.3 dB C.6 dB D.12 dB

35. Electrical Principles 35 G5B01 A two-times increase or decrease in power results in a change of how many dB? A.2 dB B.3 dB C.6 dB D. 12 dB Pm db=10log 10 ------ Pref Pm = Measured Power, Pref = Reference Power Pm = Measured Power, Pref = Reference Power

36. Electrical Principles 36 G5B02 How does the total current relate to the individual currents in each branch of a parallel circuit? A.It equals the average of each branch current B.It decreases as more parallel branches are added to the circuit C.It equals the sum of the currents through each branch D.It is the sum of the reciprocal of each individual voltage drop

37. Electrical Principles 37 G5B02 How does the total current relate to the individual currents in each branch of a parallel circuit? A.It equals the average of each branch current B.It decreases as more parallel branches are added to the circuit C.It equals the sum of the currents through each branch D.It is the sum of the reciprocal of each individual voltage drop

38. Electrical Principles 38 Ohm’s Law and Power Calculations E IR P IE E=Voltage (Volts) I=Current (Amps) R=Resistance (Ohms) P=Power (Watts) E = I * R P = I * E

39. Electrical Principles 39 G5B03 How many watts of electrical power are used if 400 VDC is supplied to an 800- ohm load? A.0.5 watts B.200 watts C.400 watts D.3200 watts

40. Electrical Principles 40 G5B03 How many watts of electrical power are used if 400 VDC is supplied to an 800- ohm load? A.0.5 watts B.200 watts C.400 watts D.3200 watts P = E 2 / R P = 160,000 / 800 P = 200 watts E IR

41. Electrical Principles 41 G5B04 How many watts of electrical power are used by a 12-VDC light bulb that draws 0.2 amperes? A.2.4 watts B.24 watts C.6 watts D.60 watts P IE

42. Electrical Principles 42 G5B04 How many watts of electrical power are used by a 12-VDC light bulb that draws 0.2 amperes? A.2.4 watts B.24 watts C.6 watts D.60 watts P = I * E P =.2 * 12 P = 2.4 watts P IE

43. Electrical Principles 43 G5B05 How many watts are being dissipated when a current of 7.0 milliamperes flows through 1.25 kilohms? A.Approximately 61 milliwatts B.Approximately 39 milliwatts C.Approximately 11 milliwatts D.Approximately 9 milliwatts

44. Electrical Principles 44 G5B05 How many watts are being dissipated when a current of 7.0 milliamperes flows through 1.25 kilohms? A.Approximately 61 milliwatts B.Approximately 39 milliwatts C.Approximately 11 milliwatts D.Approximately 9 milliwatts P=I * I * R P= I 2 * R P =.007*.007 * 1250 P=.06125 = 61 milliwatts E IR

45. Electrical Principles 45 RMS, Peak and Peak to Peak Voltages There are three key voltage measurements, RMS (Vrms), Peak (Vpk) and Peak to Peak (Vpp).

46. Electrical Principles 46 RMS, Peak and Peak to Peak Voltages The Peak voltage is relative to ground.

47. Electrical Principles 47 RMS, Peak and Peak to Peak Voltages RMS or Root Mean Square is more of an “average” voltage over the duration of the AC cycle. RMS voltage is calculated by multiplying 0.707 times the peak voltage.

48. Electrical Principles 48 RMS, Peak and Peak to Peak Voltages The Peak to Peak voltage measures from the peak of the positive swing to the peak of the negative swing.

49. PEP Peak envelope power is the average power supplied to the antenna transmission line by a transmitter during one radio frequency cycle at the crest of the modulation envelope, under normal operating conditions. powerantennatransmission linetransmitterradio frequency modulation envelopepowerantennatransmission linetransmitterradio frequency modulation envelope PEP was often used in non-broadcast amplitude modulation (AM) applications because it most accurately described the potential of mobile transmitters to interfere with each other. Its use is now somewhat deprecated, with the average transmitter power output (or sometimes effective radiated power) now typically being preferred. broadcastamplitude modulationdeprecated transmitter power outputeffective radiated powerbroadcastamplitude modulationdeprecated transmitter power outputeffective radiated power Electrical Principles 49

50. Electrical Principles 50 G5B06 What is the output PEP from a transmitter if an oscilloscope measures 200 volts peak-to-peak across a 50-ohm dummy load connected to the transmitter output? A.1.4 watts B.100 watts C.353.5 watts D.400 watts

51. Electrical Principles 51 G5B06 What is the output PEP from a transmitter if an oscilloscope measures 200 volts peak-to-peak across a 50-ohm dummy load connected to the transmitter output? A.1.4 watts B.100 watts C.353.5 watts D.400 watts PEP = ((V pp /2)*.707) 2 ------------------- R Load R Load

52. Electrical Principles 52 G5B07 Which measurement of an AC signal is equivalent to a DC voltage of the same value? A.The peak-to-peak value B.The peak value C.The RMS value D.The reciprocal of the RMS value

53. Electrical Principles 53 G5B07 Which measurement of an AC signal is equivalent to a DC voltage of the same value? A.The peak-to-peak value B.The peak value C.The RMS value D.The reciprocal of the RMS value

54. Electrical Principles 54 G5B08 What is the peak-to-peak voltage of a sine wave that has an RMS voltage of 120 volts? A.84.8 volts B.169.7 volts C.240.0 volts D.339.4 volts

55. Electrical Principles 55 G5B08 What is the peak-to-peak voltage of a sine wave that has an RMS voltage of 120 volts? A.84.8 volts B.169.7 volts C.240.0 volts D.339.4 volts Peak Voltage = RMS *1/.707 Peak Voltage = RMS * 1.414 Peak Voltage = 169.68 Peak to Peak = 169.68 * 2 Peak to Peak = 339.4

56. Electrical Principles 56 G5B08 What is the peak-to-peak voltage of a sine wave that has an RMS voltage of 120 volts? A.84.8 volts B.169.7 volts C.240.0 volts D.339.4 volts Peak Voltage = RMS *1/.707 Peak Voltage = RMS * 1.414 Peak Voltage = 169.68 Peak to Peak = 169.68 * 2 Peak to Peak = 339.4

57. Electrical Principles 57 G5B08 What is the peak-to-peak voltage of a sine wave that has an RMS voltage of 120 volts? A.84.8 volts B.169.7 volts C.240.0 volts D.339.4 volts

58. Electrical Principles 58 G5B09 What is the RMS voltage of sine wave with a value of 17 volts peak? A.8.5 volts B.12 volts C.24 volts D.34 volts

59. Electrical Principles 59 G5B09 What is the RMS voltage of sine wave with a value of 17 volts peak? A.8.5 volts B.12 volts C.24 volts D.34 volts

60. Electrical Principles 60 G5B11 What is the ratio of peak envelope power to average power for an unmodulated carrier? A..707 B.1.00 C.1.414 D.2.00

61. Electrical Principles 61 G5B11 What is the ratio of peak envelope power to average power for an unmodulated carrier? A..707 B.1.00 C.1.414 D.2.00

62. Electrical Principles 62 G5B12 What would be the voltage across a 50-ohm dummy load dissipating 1200 watts? A.173 volts B.245 volts C.346 volts D.692 volts

63. Electrical Principles 63 G5B12 What would be the voltage across a 50-ohm dummy load dissipating 1200 watts? A.173 volts B.245 volts C.346 volts D.692 volts E rms = PEP *R

64. Electrical Principles 64 G5B13 What percentage of power loss would result from a transmission line loss of 1 dB? A.10.9 % B.12.2 % C.20.5 % D.25.9 %

65. Electrical Principles 65 G5B13 What percentage of power loss would result from a transmission line loss of 1 dB? A.10.9 % B.12.2 % C.20.5 % D.25.9 %

66. Electrical Principles 66 G5B14 What is the output PEP from a transmitter if an oscilloscope measures 500 volts peak-to-peak across a 50-ohm resistor connected to the transmitter output? A.8.75 watts B.625 watts C.2500 watts D.5000 watts

67. Electrical Principles 67 G5B14 What is the output PEP from a transmitter if an oscilloscope measures 500 volts peak-to-peak across a 50-ohm resistor connected to the transmitter output? A.8.75 watts B.625 watts C.2500 watts D.5000 watts PEP = ((V pp /2)*.707) 2 ------------------- R Load

68. Electrical Principles 68 G5B15 What is the output PEP of an unmodulated carrier if an average reading wattmeter connected to the transmitter output indicates 1060 watts? A.530 watts B.1060 watts C.1500 watts D.2120 watts

69. Electrical Principles 69 G5B15 What is the output PEP of an unmodulated carrier if an average reading wattmeter connected to the transmitter output indicates 1060 watts? A.530 watts B.1060 watts C.1500 watts D.2120 watts

70. Inductance Electrical Principles 70 Inductance is the property in an electrical circuit where a change in the electric current through that circuit induces an electromotive force (EMF) that opposes the change in current (See Induced EMF).electrical circuitelectric currentelectromotive force (EMF)Induced EMF

71. Electrical Principles 71 G5C01 What causes a voltage to appear across the secondary winding of a transformer when an AC voltage source is connected across its primary winding? A.Capacitive coupling B.Displacement current coupling C.Mutual inductance D.Mutual capacitance

72. Electrical Principles 72 G5C01 What causes a voltage to appear across the secondary winding of a transformer when an AC voltage source is connected across its primary winding? A.Capacitive coupling B.Displacement current coupling C.Mutual inductance D.Mutual capacitance

73. Electrical Principles 73 G5C02 Where is the source of energy normally connected in a transformer? A.To the secondary winding B.To the primary winding C.To the core D.To the plates

74. Electrical Principles 74 G5C02 Where is the source of energy normally connected in a transformer? A.To the secondary winding B.To the primary winding C.To the core D.To the plates

75. Electrical Principles 75 G5C03 What is current in the primary winding of a transformer called if no load is attached to the secondary? A.Magnetizing current B.Direct current C.Excitation current D.Stabilizing current

76. Electrical Principles 76 G5C03 What is current in the primary winding of a transformer called if no load is attached to the secondary? A.Magnetizing current B.Direct current C.Excitation current D.Stabilizing current

77. Resistors in Series Resistors in Series are additive. R T = R 1 + R 2 + R 3 +R N ….

78. Resistors in Parallel When Resistors are connected in parallel, their combined resistance is less than the resistance of the smallest resistor. R1*R2 Two Resistors formula RT = --------- (Product of over Sum) R1+R2 1 1 1 1 1 Two or more.. -- = -- + -- + -- + -- (Reciprocal) RT R1 R2 R3 R……

79. Electrical Principles 79 G5C04 What is the total resistance of three 100-ohm resistors in parallel? A..30 ohms B..33 ohms C.33.3 ohms D.300 ohms

80. Electrical Principles 80 G5C04 What is the total resistance of three 100-ohm resistors in parallel? A..30 ohms B..33 ohms C.33.3 ohms D.300 ohms

81. Electrical Principles 81 G5C05 What is the value of each resistor if three equal value resistors in parallel produce 50 ohms of resistance, and the same three resistors in series produce 450 ohms? A.1500 ohms B.90 ohms C.150 ohms D.175 ohms

82. Electrical Principles 82 G5C05 What is the value of each resistor if three equal value resistors in parallel produce 50 ohms of resistance, and the same three resistors in series produce 450 ohms? A.1500 ohms B.90 ohms C.150 ohms D.175 ohms

83. Transformers Isolation / Matching Isolation – Unity turns ratio Same number of turns in the secondary as in the primary. Matching Step Up or Step Down Step up… More windings in Secondary Step Down…More windings in Primary

84. Calculating Turns Ratio Each winding of a transformer contains a certain number of turns of wire. The turns ratio is defined as the ratio of turns of wire in the primary winding to the number of turns of wire in the secondary winding. Turns ratio can be expressed using the formula Np Ratio = ------ Ns Np = Number of turns in the Primary Ns = Number of turns in the Secondary

85. Electrical Principles 85 G5C06 What is the voltage across a 500-turn secondary winding in a transformer if the 2250-turn primary is connected to 120 VAC? A.2370 volts B.540 volts C.26.7 volts D.5.9 volts

86. Electrical Principles 86 G5C06 What is the voltage across a 500-turn secondary winding in a transformer if the 2250-turn primary is connected to 120 VAC? A.2370 volts B.540 volts C.26.7 volts D.5.9 volts

87. Impedance Matching Maximum power is transferred from one circuit to another through a transformer when the impedances are equal, or matched. A transformer winding constructed with a definite turns ratio can perform an impedance matching function. The turns ratio will establish the proper relationship between the primary and secondary winding impedances. The ratio between the two impedances is referred to as the impedance ratio and is expressed by using the following equation. Np Zp --- = ---- Ns Zs Where Np = Number of turns in Primary Ns = Number of turns in Secondary Zp = Impedance of Primary Zs = Impedance of Secondary

88. Electrical Principles 88 G5C07 What is the turns ratio of a transformer used to match an audio amplifier having a 600-ohm output impedance to a speaker having a 4-ohm impedance? A.12.2 to 1 B.24.4 to 1 C.150 to 1 D.300 to 1

89. Electrical Principles 89 G5C07 What is the turns ratio of a transformer used to match an audio amplifier having a 600-ohm output impedance to a speaker having a 4-ohm impedance? A.12.2 to 1 B.24.4 to 1 C.150 to 1 D.300 to 1

90. Capacitors in Series When capacitors are connected in series, the total capacitance is less than any one of the series capacitors' individual capacitances. If two or more capacitors are connected in series, the overall effect is that of a single (equivalent) capacitor having the sum total of the plate spacings of the individual capacitors. An increase in plate spacing, with all other factors unchanged, results in decreased capacitance. C1*C2 Two Capacitors CT = --------- C1+C2 Two or more.. 1 1 1 1 1 -- = -- + -- + -- + -- CT C1 C2 C3 C……

91. Capacitors in Parallel When capacitors are connected in parallel, the total capacitance is the sum of the individual capacitors' capacitances. If two or more capacitors are connected in parallel, the overall effect is that of a single equivalent capacitor having the sum total of the plate areas of the individual capacitors. An increase in plate area, with all other factors unchanged, results in increased capacitance. Capacitors in Parallel are additive. CT = C1 + C 2 + C3 +C...

92. Inductors in Series When inductors are connected in series, the total inductance is the sum of the individual inductors' inductances. The definitive measure of inductance is the amount of voltage dropped across an inductor for a given rate of current change through it. If inductors are connected together in series (thus sharing the same current, and seeing the same rate of change in current), then the total voltage dropped as the result of a change in current will be additive with each inductor, creating a greater total voltage than either of the individual inductors alone. Greater voltage for the same rate of change in current means greater inductance. Inductors in Series are additive. LT = L1 + L 2 + L3 +L...

93. Inductors in Parallel When inductors are connected in parallel, the total inductance is less than any one of the parallel inductors' inductances. Rremember that the definitive measure of inductance is the amount of voltage dropped across an inductor for a given rate of current change through it. Since the current through each parallel inductor will be a fraction of the total current, and the voltage across each parallel inductor will be equal, a change in total current will result in less voltage dropped across the parallel array than for any one of the inductors considered separately. In other words, there will be less voltage dropped across parallel inductors for a given rate of change in current than for any of those inductors considered separately, because total current divides among parallel branches. Less voltage for the same rate of change in current means less inductance. 1 1 1 1 1 Two or more.. -- = -- + -- + -- + -- (Reciprocal) LT L1 L2 L3 L……

94. Electrical Principles 94 G5C08 What is the equivalent capacitance of two 5000 picofarad capacitors and one 750 picofarad capacitor connected in parallel? A.576.9 picofarads B.1733 picofarads C.3583 picofarads D.10750 picofarads

95. Electrical Principles 95 G5C08 What is the equivalent capacitance of two 5000 picofarad capacitors and one 750 picofarad capacitor connected in parallel? A.576.9 picofarads B.1733 picofarads C.3583 picofarads D.10750 picofarads

96. Electrical Principles 96 G5C09 What is the capacitance of three 100 microfarad capacitors connected in series? A..30 microfarads B..33 microfarads C.33.3 microfarads D.300 microfarads

97. Electrical Principles 97 G5C09 What is the capacitance of three 100 microfarad capacitors connected in series? A..30 microfarads B..33 microfarads C.33.3 microfarads D.300 microfarads

98. Electrical Principles 98 G5C10 What is the inductance of three 10 millihenry inductors connected in parallel? A..30 Henrys B.3.3 Henrys C.3.3 millihenrys D.30 millihenrys

99. Electrical Principles 99 G5C10 What is the inductance of three 10 millihenry inductors connected in parallel? C. 3.3 millihenrys

100. Electrical Principles 100 G5C11 What is the inductance of a 20 millihenry inductor in series with a 50 millihenry inductor? A..07 millihenrys B.14.3 millihenrys C.70 millihenrys D.1000 millihenrys

101. Electrical Principles 101 G5C11 What is the inductance of a 20 millihenry inductor in series with a 50 millihenry inductor? A..07 millihenrys B.14.3 millihenrys C.70 millihenrys D.1000 millihenrys

102. Electrical Principles 102 G5C12 What is the capacitance of a 20 microfarad capacitor in series with a 50 microfarad capacitor? A..07 microfarads B.14.3 microfarads C.70 microfarads D.1000 microfarads

103. Electrical Principles 103 G5C12 What is the capacitance of a 20 microfarad capacitor in series with a 50 microfarad capacitor? A..07 microfarads B.14.3 microfarads C.70 microfarads D.1000 microfarads

104. Electrical Principles 104 G5C13 What component should be added to a capacitor in a circuit to increase the circuit capacitance? A.An inductor in series B.A resistor in series C.A capacitor in parallel D.A capacitor in series

105. Electrical Principles 105 G5C13 What component should be added to a capacitor in a circuit to increase the circuit capacitance? A.An inductor in series B.A resistor in series C.A capacitor in parallel D.A capacitor in series

106. Electrical Principles 106 G5C14 What component should be added to an inductor in a circuit to increase the circuit inductance? A.A capacitor in series B.A resistor in parallel C.An inductor in parallel D.An inductor in series

107. Electrical Principles 107 G5C14 What component should be added to an inductor in a circuit to increase the circuit inductance? A.A capacitor in series B.A resistor in parallel C.An inductor in parallel D.An inductor in series

108. Electrical Principles 108 G5C15 What is the total resistance of a 10 ohm, a 20 ohm, and a 50 ohm resistor in parallel? A.5.9 ohms B.0.17 ohms C.10000 ohms D.80 ohms

109. Electrical Principles 109 G5C15 What is the total resistance of a 10 ohm, a 20 ohm, and a 50 ohm resistor in parallel? A.5.9 ohms B.0.17 ohms C.10000 ohms D.80 ohms

110. Electrical Principles 110 G5C16 What component should be added to an existing resistor in a circuit to increase circuit resistance? A.A resistor in parallel B.A resistor in series C.A capacitor in series D.A capacitor in parallel

111. Electrical Principles 111 G5C16 What component should be added to an existing resistor in a circuit to increase circuit resistance? A.A resistor in parallel B.A resistor in series C.A capacitor in series D.A capacitor in parallel

112. Electrical Principles 112 G5 - ELECTRICAL PRINCIPLES [3 exam questions - 3 groups]