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10 Algorithms in 20th Century Science, Vol. 287, No. 5454, p. 799, February 2000 Computing in Science & Engineering, January/February 2000 1946: The Metropolis Algorithm for Monte Carlo 1947: Simplex Method for Linear Programming // Com S 477/577, 418/518 1950: Krylov Subspace Iteration Method 1951: The Decompositional Approach to Matrix Computations 1957: The Fortran Optimizing Compiler 1959: QR Algorithm for Computing Eigenvalues 1962: Quicksort Algorithms for Sorting 1965: Fast Fourier Transform // Com S 477/577 1977: Integer Relation Detection 1987: Fast Multipole Method With the greatest influence on the development and practice of science and engineering …
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Quicksort C. A. R. Hoare 1962 Best practical sorting algorithm! p r pq prqq+1r A divide conquer After partition, A[i] A[j], p i q and q+1 j r. No work is needed on combining A[p..q] and A[q+1..r]!
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How to Partition? 6 2 7 4 9 5 10 pivot x i = p–1p j = r+1r 6 2 7 4 9 5 10 j i x x x x 5 2 7 4 9 6 10 ij
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Partitioning 5 2 7 4 9 6 10 ij x x x x 5 2 4 7 9 6 10 ji jiq = A[p..q] A[q+1..r]
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The Procedure Partition(A, p, r) x A[p] i p – 1 j r + 1 while true do repeat j j – 1 until A[j] x repeat i i + 1 until A[i] x if i < j then A[i] A[j] else return j // different from the procedure in the textbook
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The Quicksort Algorithm Quicksort(A, p, r) if p < r then q Partition(A, p, r) Quicksort(A, p, q) Quicksort(A, q+1, r)
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Performance of Quicksort Depends on how balanced the partitioning is. Worst Case: p = q < r Let n = r – p + 1 n 2 … n – 1 1 1 1 1 n – 2 1 (n ) time 2
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A Worst-Case Example The input array is already sorted. 2, 4, 5, 9, 11 2 4, 5, 9, 11 4 5, 9, 11 5 9, 11 9 11
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Best Case q – p + 1 = (r – p + 1) / 2 recursion tree n n/2 n/4 n/4 cost cn lg n (n lg n)
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Balanced Partitioning Suppose always a 9-to-1 proportional split. T(n) = T(9n/10) + T(n/10) + n n n/10 9n/10 n/100 9n/100 9n/100 81n/100 81n/1000 729n/1000 1 1 cn cn log n 10 log n 10/9 T(n) = (n lg n)
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Average Case Imagine a bad split followed by a good split. n 1 n – 1 (n – 1) / 2 Cost of two-step partitioning: n + n – 1 = (n) n (n – 1) / 2 + 1 (n – 1) / 2 similar to Cost of one-step partitioning: n = (n) T(n) = (n lg n)
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Comparison of Sorting Methods Method Space Average Max n=16 n=10000 Insertion sort n(1+ ) 1.25n + 13.25n 2.5n 433 1248615 Merge sort n(1+ ) 14.43n lnn + 4.92n 14.4n lnn 761 104716 Heapsort n 23.08n lnn + 0.01n 24.5n lnn 1068 159714 Quicksort n + 2 lgn 11.67n lnn – 1.74n 2n 470 81486 Median-of-3 n + 2 lgn 10.63n lnn – 2.12n n 487 74574 Quicksort 2 2 22 (Use the median of three randomly picked elements as the pivot.) D. E. Knuth, “The Art of Computer Programming”, Vol 3, 2 nd ed., p.382, 1998. Implemented on the MIX Computer.
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Issue with Quicksort Quicksort has the best average-case behavior. All permutations of the input sequence are assumed to be equally likely. Not necessarily true in practice! Make its behavior independent of the input ordering!
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Randomization An algorithm is randomized if its behavior depends on the input random numbers No particular input causes its worst-case behavior. Choose the pivot at random! Randomized-Partition(A, p, r) i Random(p, r) A[p] A[i] return Partition(A, p, r)
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An Example 6 2 7 4 9 5 10 p r Execution 1: Random(p, r) = p + 3 4 2 7 6 9 5 10 iijjjjjj 2 4 7 6 9 5 10 j
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Cont’d 6 2 7 4 9 5 10 p r Execution 2: Random(p, r) = p + 2 7 2 6 4 9 5 10 iijjjjiiii 5 2 6 4 9 7 10 ijj
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Randomized Quicksort Randomized-Quicksort(A, p, r) if p < r then q Randomized-Partition(A, p, r) Randomized-Quicksort(A, p, q) Randomized-Quicksort(A, q+1, r) A random sequence of good and bad choices can yield an efficient algorithm. Height of recursion tree: (lg n).
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Analysis of Partitioning Assumption for simplification: All elements are distinct. x…… prq A:A: After random partitioning A[k] x p k q A[k] x q+1 k r rank(x) is # elements x
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Ranks and Probabilities rank(x) = 1 x p = q rank(x) 2 …x…… p q p – q + 1 = rank(x) – 1 Probability P{rank(x) = i } = 1/n, 1 i n = r – p + 1 P{q = p} = 2/n, if rank(x) = 1, 2 P{q – p + 1 = i} = 1/n, if rank(x) = i+1, i = 2, …, n–1
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Average-case Running Time of Randomized-Quicksort T(n) = (1/n) ( T(1) + T(n – 1) + ( T(q) + T(n – q) ) ) + (n) rank(x) = 1 rank(x) = q + 1 T(n) = O(n lg n) But T(n) cannot better the best case running time (n lg n) of quicksort. (see a separate.pdf handout) Running time is (n lg n)! q = 1 n – 1 So T(n) = (n lg n).
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