1. Opener: Ca 2+ + O 2- → Na + + N 3- → Ca 2+ + N 3- →

2. Opener: Ca 2+ + O 2- → CaO Na + + N 3- → Ca 2+ + N 3- →

3. Opener: Ca 2+ + O 2- → CaO 3Na + + N 3- → Na 3 N Ca 2+ + N 3- →

4. Opener: Ca 2+ + O 2- → CaO 3Na + + N 3- → Na 3 N 3Ca 2+ + 2N 3- → Ca 3 N 2

5. More Practice: K + + S 3-  Be 2+ + F -  Al 3+ + Cl -  Ga 3+ + O 2- 

6. More Practice: 3K + + S 3-  K 3 S Be 2+ + F -  Al 3+ + CI -  Ga 3+ + O 2- 

7. More Practice: 3K + + S 3-  K 3 S Be 2+ + 2F -  BeF 2 Al 3+ + CI -  Ga 3+ + O 2- 

8. More Practice: 3K + + S 3-  K 3 S Be 2+ + 2F -  BeF 2 Al 3+ + 3CI -  AlCI 3 Ga 3+ + O 2- 

9. More Practice: 3K + + S 3-  K 3 S Be 2+ + 2F -  BeF 2 Al 3+ + 3CI -  AlCI 3 2Ga 3+ + 3O 2-  Ga 2 O 3

10. Monoatomic ions (ions made up of only one atom) are named by changing the end of the element name to -ide for example: bromine (Br) becomes bromide (Br - ) tellurium (Te) becomes telluride (Te -2 ) sulfur (S) becomes sulfide (S -2 )

11.  When naming an ionic compound, you first give the name of the cation element, then the anion with the -ide ending.  For example; NaCl is sodium chloride Lets name the compounds from the first practice slide….

12. Now practice: Ca 2+ + O 2- → CaO 3Na + + N 3- → Na 3 N 3Ca 2+ + 2N 3- → Ca 3 N 2

13. Now practice: Ca 2+ + O 2- → CaO Calcium Oxide Na + + N 3- → Na 3 N Sodium Nitride Ca 2+ + N 3- → Ca 3 N 2 Calcium Nirtide

14. Now, you name the compounds from this practice slide! 3K + + S 3-  K 3 S Be 2+ + 2F -  BeF 2 Al 3+ + 3CI -  AlCI 3 2Ga 3+ + 3O 2-  Ga 2 O 3

15. Now, you name the compounds from this practice slide! 3K + + S 3-  K 3 SPotassium Sulfide Be 2+ + 2F -  BeF 2 Al 3+ + 3CI -  AlCI 3 2Ga 3+ + 3O 2-  Ga 2 O 3

16. Now, you name the compounds from this practice slide! 3K + + S 3-  K 3 SPotassium Sulfide Be 2+ + 2F -  BeF 2 Beryllium Fluoride Al 3+ + 3CI -  AlCI 3 2Ga 3+ + 3O 2-  Ga 2 O 3

17. Now, you name the compounds from this practice slide! 3K + + S 3-  K 3 SPotassium Sulfide Be 2+ + 2F -  BeF 2 Beryllium Fluoride Al 3+ + 3CI -  AlCI 3 Aluminum Chloride 2Ga 3+ + 3O 2-  Ga 2 O 3

18. Now, you name the compounds from this practice slide! 3K + + S 3-  K 3 SPotassium Sulfide Be 2+ + 2F -  BeF 2 Beryllium Fluoride Al 3+ + 3CI -  AlCI 3 Aluminum Chloride 2Ga 3+ + 3O 2-  Ga 2 O 3 Gallium Oxide

19. Polyatomic Ions  Polyatomic ions are ions made up of more than one atom  There are 15 polyatomic ions (ions made up of more than one atom)  I will give you the chart on page 178 of the text for the test, so when you see the formula, you need to be able to tell me the name.

20.  Here are some of them….  OH- hydroxide  SO 4 2- sulfate  SO 3 2- sulfite  O 2 2- peroxide  NO 2 - nitrite  NO 3 - nitrate  MnO 4 - permanganate

21. The same rules apply when dealing with polyatomic ions. (remember, the charge associated with the polyatomic ion applies to the entire ion) K + + CN - → KCN 2Na + + O 2 2- → Na 2 O 2 Mg 2+ + 2NO 2 - → Mg(NO 2 ) 2 (by putting parenthesis around the Nitrite portion of the compound, the following subscript tells us that there are 2 nitrite ions for every one Magnesium ion in this compound)

22. More Practice: Li + + MnO 4 - → Ca 2+ + NO 2 - → Na + + SO 3 2- →

23. More Practice: Li + + MnO 4 - → LiMnO 4 Ca 2+ + NO 2 - → Na + + SO 3 2- →

24. More Practice: Li + + MnO 4 - → LiMnO 4 Lithium Permanganate Ca 2+ + NO 2 - → Na + + SO 3 2- →

25. More Practice: Li + + MnO 4 - → LiMnO 4 Lithium Permanganate Ca 2+ + 2NO 2 - → Ca(NO 2 ) 2 Na + + SO 3 2- →

26. More Practice: Li + + MnO 4 - → LiMnO 4 Lithium Permanganate Ca 2+ + 2NO 2 - → Ca(NO 2 ) 2 Calcium Nitrite Na + + SO 3 2- →

27. More Practice: Li + + MnO 4 - → LiMnO 4 Lithium Permanganate Ca 2+ + 2NO 2 - → Ca(NO 2 ) 2 Calcium Nitrite 2Na + + SO 3 2- → Na 2 SO 3

28. More Practice: Li + + MnO 4 - → LiMnO 4 Lithium Permanganate Ca 2+ + 2NO 2 - → Ca(NO 2 ) 2 Calcium Nitrite 2Na + + SO 3 2- → Na 2 SO 3 Sodium Sulfite

29. Naming Compounds that have TRANSITION METALS  because transition metals can have more than one charge, you must include the charge of the metal, in the form of a Roman Numeral, in the name. For example… Fe 2+ + 2OH -  Fe(OH) 2 The product is named Iron (II) Hydroxide Fe 3+ + 3OH -  Fe(OH) 3 This product would be named Iron (III) Hydroxide