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Problem Format Example: If you travel 30 km in 15 min, what is your speed? 1.List what is known and what you are looking for 2.Select the formula you.

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Presentation on theme: "Problem Format Example: If you travel 30 km in 15 min, what is your speed? 1.List what is known and what you are looking for 2.Select the formula you."— Presentation transcript:

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2 Problem Format Example: If you travel 30 km in 15 min, what is your speed? 1.List what is known and what you are looking for 2.Select the formula you need to solve the problem 3. Show setup work 4. Show answer (include magnitude and units) and circle or box in answer d=30 km t =.25 hr v= ? v=d/t v=30km/.25hr 120 km/hr

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4 Percentage Error Percentage Error = Absolute Error x 100% Accepted value Absolute Error = Observed value – accepted value Experimental= 9.92Accepted= 9.81 (9.92 – 9.81)/ 9.81 x 100% = 1 %

5 Rate: anything compared to time Rate = Quantity time Motion: all motion is relative. (it’s compared to something else)

6 Distance -A scalar quantity -How far moved or traveled -Linear amount covered

7 Displacement -a vector quantity -The magnitude and direction of a change in position -How far and in what direction traveled from starting point Displacement: x = x f - x i * Can be positive or negative

8 Speed : rate at which distance is covered Speed = distance time * Scalar Quantity

9 Velocity -rate at which displacement occurs -Speed in a given direction- if in a straight line V = x or v = x f – x i t t f - t i * Vector Quantity

10 Velocity/ Graphing 1.If the line on a displacement v. time graph is a straight line, this shows uniform velocity 2.The slope of a displacement/time graph is velocity 3.Average velocity = total displacement/time interval 4.Average velocity = the slope of a straight line joining 2 points on a displacement/time graph 5.Instantaneous Velocity = the slope of a tangent to a displacement/time graph Distance(m) Time (sec) Velocity v. Time Graphs

11 Acceleration = change in velocity/ time a= v/ t a = v f – v i t Acceleration can be: positive negative (deceleration) Acceration due to gravity = 9.81 m/s 2

12 Terminal Velocity -occurs when an object is falling through a material which provides resistance -The maximum speed reached -When the force of gravity = force of resistance -There is no furture acceleration

13 g -acceleration due to gravity -Can be put in formula in place of “a” -= -9.81 m/s 2 -Up = + ; down = - Free Fall -An object falling in a vacuum in the absences of air resistance. No terminal velocity

14 Graphs Velocity = slope of displacement/time graph Acceleration= slope of a velocity/time graph Displacement = area beneath the slope of a velocity/time graph


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