1. You send four samples (a foraminifera, a leaf, and two pieces of wood) to a lab for measurement. They send you the following results:  13 C Fraction Modern Percent Modern Foram #1+1.5 ‰0.5050.0 % Leaf-28 ‰0.5050.0 % Wood-25 ‰0.2525.0 % Wood-25 ‰1.89189.0% 1. What is the 14 C age of the three samples? 2. Which of the samples has the most 14 C atoms per gram of sample carbon? 3. Calculate the calibrated age ranges for these samples using one of the programs available on the web (e.g. Calib; http://calib.qub.ac.uk/calib/ or Oxcal http://c14.arch.ox.ac.uk/embed.php?File=oxcal.html). Try using error of ±25 years and ±50 years to see how that affects the date ranges.http://calib.qub.ac.uk/calib/ 4. What would be the D 14 C and  14 C values for these samples - assume you measured them in 2014?

2. Additional problems Corals that grew during the year 1900 off the coast of Hawaii, Galapagos, and the Great Barrier Reef contain 14 C Fraction Modern values of 0.945, 0.924 and 0.950, respectively. a) Now calculate the ∆ 14 C values for the carbon in seawater from which these corals precipitated. (Use the true 14 C half-life of 5730 y in your calculations). b) Calculate the reservoir ages (equivalent to the radiocarbon age for the seawater carbon) for each of these coral sites. (Remember to use the Libby 14 C half-life of 5568 y in your calculations).

3. Additional problem 3a) The Fraction Modern values for coexisting planktonic and benthic foraminifera from a horizon in an ocean sediment core from the full glacial period were 0.11 and 0.100, respectively. What was the radiocarbon age difference between these coexisting benthic and planktonic foraminifera? b) The age difference measured for benthic and planktonic foraminifera in the Atlantic ocean today is 350 radiocarbon years. If you want to measure the difference between your answer above in part 3a, and 350 years, your AMS has to measure with precision equivalent to 1/3 of this difference. Calculate what that precision is equal to in Fraction Modern.