Presentation is loading. Please wait.

Presentation is loading. Please wait.

A solution of a system of two equations in two variables is an ordered pair of numbers that makes both equations true. A solution to two equations (1,

Similar presentations


Presentation on theme: "A solution of a system of two equations in two variables is an ordered pair of numbers that makes both equations true. A solution to two equations (1,"— Presentation transcript:

1 A system of equations is a set of two or more equations that are to be solved.

2 A solution of a system of two equations in two variables is an ordered pair of numbers that makes both equations true. A solution to two equations (1, 3) for y = 2x + 1 and y = 5x - 2

3 Example 1: Solving Systems of Linear Equations by Graphing
y = 2x – 7 3x + y = 3 Step 1: Solve both equations for y. 3x + y = 3 y = 2x – 7 –3x –3x y = 3 – 3x Step 2: Graph. The lines intersect at (2, –3), so the solution is (2, –3).

4 Example 1A Continued Check y = 2x – 7 3x + y = 3 –3 = 2(2) – 7
? –3 = 2(2) – 7 3(2) + (–3) = 3 ? ? –3 = –3  3 = 3  ?

5 Not all systems of linear equations have graphs that intersect in one point. There are three possibilities for the graph of a system of two linear equations, and each represents a different solution set.

6

7 Example 2: Solving Systems of Linear Equations by Graphing
2x + y = 9 y – 9 = –2x Step 1: Solve both equations for y. 2x + y = 9 y – 9 = –2x –2x –2x y = –2x + 9 y = –2x + 9 Step 2: Graph. The lines are the same, so the system has infinitely many solutions.

8 Example 1B Continued Check y = y –2x + 9 = –2x + 9 +2x +2x 9 = 9  ? ?

9 Example 3 y = –4x + 1 5x + y = –1 Step 1: Solve both equations for y. y = –4x + 1 5x + y = –1 –5x –5x y = –5x – 1 Step 2: Graph. The lines are intersect at (–2, 9), so the solution is (–2, 9).

10 Example 3 Continued Check y = –4x + 1 5x + y = –1 9 = –4(–2) + 1
? 9 = –4(–2) + 1 5(–2) + (9) = –1 ? ? 9 = 9  –1 = –1  ?

11 Application: Example 1 A bus leaves the school traveling west at 50 miles per hour. After it travels 15 miles, a car follows the bus, traveling at 55 miles per hour. After how many hours will the car catch up with the bus? Let t = time in hours Let d = distance in miles bus distance: d = 50t + 15 car distance: d = 55t

12 Application: Example 1 Continued
Graph each equation. The point of intersection appears to be (3, 165). Check d = 50t + 15 200 165 = 50(3) + 15 ? 150 Distance (mi) 165 = 165  100 50 d = 55t 165 = 55(3) ? Time (h) 165 = 165  The car will catch up after 3 hours, 165 miles from the school.

13 Lesson Quiz Solve each system of equations by graphing. Check your answer. 1. A car left Cincinnati traveling 55 mi/h. After it had driven 225 miles, a second car left Cincinnati on the same route traveling 70 mi/h. How long after the 2nd car leaves will it reach the first car? 15 h 2. y = x; y = 3x (0, 0) 3. y = 4 – x; x + y = 1 no solution

14 Lesson Quiz for Student Response Systems
1. Solve the system of equations. y = 2 – x 2y = 4 – 2x A. no solution B. infinitely many solutions C. (1, 1) D. (2, 2) 14 14

15 Lesson Quiz for Student Response Systems
2. Solve the system of equations. y = 5 – x 3 – x = y A. no solution B. infinitely many solutions C. (3, 5) D. (5, 3) 15 15

16 Lesson Quiz for Student Response Systems
3. Solve the system of equations. y = 5 – 2x 3x = y A. no solution B. infinitely many solutions C. (1, 3) D. (3, 1) 16 16


Download ppt "A solution of a system of two equations in two variables is an ordered pair of numbers that makes both equations true. A solution to two equations (1,"

Similar presentations


Ads by Google