# Developing Formulas for Triangles and Quadrilaterals

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Developing Formulas for Triangles and Quadrilaterals
Geometry H2 (Holt 10-1) K. Santos

Area of a Parallelogram
Area = product of its base and height A= bh Base must be perpendicular to the height b h 5cm 3cm 9cm

Example Find the perimeter of a parallelogram, in which the base is 4ft and the area is 12 ππ‘ 2 .

Area of a Triangle Area = one half of the product of its base and height A= 1 2 bh or A = πβ 2 Base perpendicular to height h h h b b b If b = 4β and h = 6β

Exampleβfinding a side
The area of a triangle is 24 ππ 2 and its height is 3 cm. Find the length of its corresponding base.

Area of a Trapezoid Area = (average of the bases)(height) A = π 1 + π 2 2 h π 1 h π 2 Remember: height is perpendicular to both bases

Example 1--Trapezoid Find the area of the trapezoid. 20 in 25 in 18 in 36 in

Example 2--Trapezoid Find the area of the trapezoid. 11 ft 13 ft 16 ft

Area of a Rhombus The area of a rhombus is half the product of the lengths of its diagonals. A = π 1 π 2 2 π 2 π 1 Example: Find the area if the diagonals are: 6 in and 8 in

Area of a Kite The area of a kite is half the product of the lengths of its diagonals. π 1 A = π 1 π 2 2 π 2 Example 1: Kite with diagonals 9 cm & 8 cm

Example 2--Kite Find the area of the kite. 5β 4β A = π 1 π 2 2 6β

Formulas Square: A = bh Rectangle: A = bh Parallelogram: A = bh Trapezoid: A = π 1 + π 2 2 h Triangle: A = Β½ bh Rhombus: A = π 1 π 2 2 Kite: A = π 1 π 2 2

The area of a region is equal to the sum of the areas of its nonoverlapping parts. Best way to find this area is to find the area of rectangle + area of triangle

ExampleβPartitioning Shapes
Find the area of the shape below: Find the sum of the areas of the rectangle and the triangle

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