Presentation is loading. Please wait.

Presentation is loading. Please wait.

Mathematics Intermediate Tier Shape and space GCSE Revision.

Similar presentations


Presentation on theme: "Mathematics Intermediate Tier Shape and space GCSE Revision."— Presentation transcript:

1 Mathematics Intermediate Tier Shape and space GCSE Revision

2 Intermediate Tier – Shape and space revision
Contents : Angle calculations Angles and polygons Bearings Units Perimeter Area formulae Area strategy Volume Nets and surface area Spotting P, A & V formulae Transformations Constructions Loci Pythagoras Theorem Similarity Trigonometry Circle angle theorems

3 Use the rules to work out all angles
“F” angles are equal 570 h i Use the rules to work out all angles Angle calculations a 720 210 Angles in a half turn = 1800 Angles in a triangle = 1800 j 120 350 Angles in a full turn = 3600 1620 b 1350 980 730 k l Angles in a quadrilateral = 3600 Opposite angles are equal 1530 c d e Angles in an isosceles triangle m 80 “Z” angles are equal 420 f g

4 There are 3 types of angles in regular polygons
Angles and polygons Angles at = the centre No. of sides Exterior = angles No. of sides Interior = e angles e i e c Calculate the value of c, e and i in regular polygons with 8, 9, 10 and 12 sides Answers: 8 sides = 450, 450, 1350 9 sides = 400, 400, 1400 10 sides = 360, 360, 1440 12 sides = 300, 300, 1500 To calculate the total interior angles of an irregular polygon divide it up into triangles from 1 corner. Then no. of x 180 Total i = 5 x 180 = 9000

5 Bearings N Bristol N Bath 0560 2360
A bearing should always have 3 figures. A bearing is an angle measured in a clockwise direction from due North What are these bearings ? N Here are the steps to get your answer Bristol 2360 N Notice that there is a 1800 difference between the outward journey and the return journey 560 Bath 0560 2360 What is the bearing of Bristol from Bath ? What is the bearing of Bath from Bristol ?

6 Learn these rough imperial to metric conversions
km m cm mm x 1000 x 10 x 100 ÷ 1000 ÷ 10 ÷ 100 Length Units Learn these metric conversions kl l cl ml Capacity kg m cg mg Weight Imperial  Metric 5 miles  8 km 1 yard  0.9 m 12 inches  30 cm 1 inch  2.5 cm Learn these rough imperial to metric conversions

7 Be prepared to leave answers to circle questions in terms of 
Perimeter Be prepared to leave answers to circle questions in terms of  especially in the non-calculator exam The perimeter of a shape is the distance around its outside measured in cm, m, etc. Perimeter = 4 x L of a square 6.5m Circumference =  x D of a circle 5m 26m Perimeter = 2(L + W) of a rectangle 7.2m 2m 15cm Perim = D + ( x D)  2 Perim = 15 + ( x 15)  2 Perim =  31.4m 3m Circumference =  x D of a semi-circle Perimeter = ? 1m 7.85m 4.71m 18.4m = = 14.56m

8 Be prepared to leave answers to circle questions in terms of 
The area of a 2D shape is the amount of space covered by it measured in cm2, m2 etc. Area formulae Be prepared to leave answers to circle questions in terms of  especially in the non-calculator exam Area of = L x W square 7m Area of = b x h parallelogram 10m 5m 4m Area of = (a + b) x h Trapezium 2m 6m 5m 4m 49m2 40m2 16m2 Area of = L x W rectangle 9m 2m Area of = b x h triangle 8m 9m 6m Area of =  x r2 circle 8m 10cm Area = ( x r x r)  2 Area = ( x 5 x 5)  2 Area = 12.5 18m2 24m2 Area of = b x h rhombus 7m 6m 5m 3m 7m 42m2 50.24m2 7.5m2

9 Area strategy What would you do to get the area of each of these shapes? Do them step by step! 1. 9m 1.5m 2m 8m 3. 6m 4m 2. 7m 2m 10m 6m 1.5m 5. 3m 4. 6m

10 Volume The volume of a 3D solid shape is the amount of space inside it measured in cm3, m3 etc. Volume of = Area at end x L a prism 4m A = 14m2 Volume = L x L x L of cube 3m 27m3 56m3 Volume of = ( x r2) x L cylinder 7m 10m 2m Volume of = L x W x H cuboid 3m 7m 42m3 384.65m3

11 To find the surface area of a cuboid it helps to draw the net
6 Nets and surface area 12cm2 12cm2 4cm2 2 2 4cm2 12cm2 Cuboid 2 by 2 by 6 Net of the cuboid 12cm2 Volume = 2 x 2 x 6 = 24cm3 Total surface area = = 56cm2 To find the surface area of a cuboid it helps to draw the net Find the volume and surface area of these cuboids: 3. 5 by 5 by 5 1. 5 by 4 by 3 2. 6 by 6 by 1 V = 5 x 4 x 3 = 60cm3 V = 6 x 6 x 1 = 60cm3 V = 5 x 5 x 5 = 125cm3 SA = 94cm2 SA = 96cm2 SA = 150cm2

12 r(+ 3) 4rl r(r + l) 1d2 4 4r2 3 4r3 3 r + ½r 4l2h 1r2h 3 1rh
Spotting P, A & V formulae r(+ 3) 4rl P A Which of the following expressions could be for: Perimeter Area Volume r(r + l) A 1d2 4 4r2 3 4r3 3 A A r + ½r V 4l2h P 1r2h 3 1rh 3 V r + 4l A V 1r 3 P rl 3lh2 4r2h P V V A

13 y x y = x y = - x x = 1 Transformations 1. Reflection Reflect the
triangle using the line: y = x then the line: y = - x x = 1

14 y x Transformations 2. Rotation C B A D
Describe the rotation of A to B and C to D y x 2. Rotation When describing a rotation always state these 3 things: No. of degrees Direction Centre of rotation e.g. a rotation of 900 anti-clockwise using a centre of (0, 1) C B A D

15 3 -4 Transformations 3. Translation Vertical translation
What happens when we translate a shape ? The shape remains the same size and shape and the same way up – it just…… Transformations slides 3. Translation Horizontal translation Use a vector to describe a translation 3 -4 Give the vector for the translation from…….. Vertical translation D C 6 1. A to B 6 5 2. A to D A B -3 4 3. B to C 4. D to C -3 -1

16 y x Transformations 4. Enlargement O Enlarge this shape by a scale
factor of 2 using centre O Transformations y x 4. Enlargement O

17 Have a look at these constructions and work out what has been done
Perpendicular bisector of a line Have a look at these constructions and work out what has been done 900 Triangle with 3 side lengths Bisector of an angle 600

18 Loci A locus is a drawing of all the points which satisfy a rule or a set of constraints. Loci is just the plural of locus. A goat is tethered to a peg in the ground at point A using a rope 1.5m long 1.5m Draw the locus to show all that grass he can eat 1. A 1.5m A goat is tethered to a rail AB using a rope (with a loop on) 1.5m long Draw the locus to show all that grass he can eat 2. A B

19 Similarity Shapes are congruent if they are exactly the same shape
and exactly the same size Similarity Shapes are similar if they are exactly the same shape but different sizes How can I spot similar triangles ? These two triangles are similar because of the parallel lines Triangle C Triangle B Triangle A All of these “internal” triangles are similar to the big triangle because of the parallel lines

20 Triangle 2 y Triangle 1 Similarity y = 17.85  2.1 = 8.5m
These two triangles are similar.Calculate length y y =  2.1 = 8.5m x 2.1 Same multiplier 15.12m 17.85m x 2.1 Multiplier =  7.2 = 2.1 y 7.2m Triangle 1

21 ? ? ? D F E D F E A B C Pythagoras Theorem
Calculating the Hypotenuse Pythagoras Theorem D F E 45cm 21cm ? Calculate the size of DE to 1 d.p. Hyp2 = a2 + b2 How to spot a Pythagoras question DE2 = Be prepared to leave your answer in surd form (most likely in the non-calculator exam) DE2 = DE2 = 2466 DE = Right angled triangle D F E 6cm 3cm ? Calculate the size of DE in surd form Hyp2 = a2 + b2 DE = DE = 49.7cm DE2 = No angles involved in question DE2 = DE2 = 45 Hyp2 = a2 + b2 Calculating a shorter side DE = 45 162 = AC A B C 16m 11m ? Calculate the size of AC to 1 d.p. DE = 9 x 5 256 = AC DE = 35 cm = AC2 How to spot the Hypotenuse 135 = AC2 135 = AC Longest side & opposite = AC AC = 11.6m

22 Look out for the following Pythagoras questions in disguise:
Finding lengths in isosceles triangles y x Find the distance between 2 co-ords O Finding lengths inside a circle 1 (angle in a semi -circle = 900) Finding lengths inside a circle 2 (radius x 2 = isosc triangle) O

23 ? D F E D B C Trigonometry H O Right angled A triangle An angle
Calculating an angle Trigonometry D F E 53cm 26cm Calculate the size of  to 1 d.p. SOHCAHTOA How to spot a Trigonometry question Tan  = O/A H Tan  = 26/53 Tan  = O Right angled triangle  = 0 A An angle involved in question Calculating a side D B C 11m ? Calculate the size of BC to 1 d.p. 730 SOHCAHTOA Sin  = O/H O A Sin 73 = 11/H Label sides H, O, A Write SOHCAHTOA Write out correct rule Substitute values in If calculating angle use 2nd func. key H = 11/Sin 73 H H = m

24 A F B C E D c Circle angle theorems Rule 1 - Any angle in a
semi-circle is 900 A F Which angles are equal to 900 ? c B C E D

25 Which angles are equal here?
Circle angle theorems Rule 2 - Angles in the same segment are equal Which angles are equal here? Big fish ?*!

26 Circle angle theorems Rule 3 - The angle at the centre
is twice the angle at the circumference c c c An arrowhead A little fish A mini quadrilateral c c Look out for the angle at the centre being part of a isosceles triangle Three radii

27 D A + C = 1800 C A B B + D = 1800 Circle angle theorems
Rule 4 - Opposite angles in a cyclic quadrilateral add up to 1800 D A + C = 1800 C A and B B + D = 1800

28 c Circle angle theorems Rule 5 - The angle between the tangent
and the radius is 900 c A tangent is a line which rests on the outside of the circle and touches it at one point only

29 c Circle angle theorems Rule 7 - Tangents from an external point
are equal (this usually creates a kite with two 900 angles in….. …… or two isosceles triangles) c 900 900


Download ppt "Mathematics Intermediate Tier Shape and space GCSE Revision."

Similar presentations


Ads by Google