1. To introduce the general form of a quadratic equation To write quadratic equations that model real-world data To approximate the x-intercepts and other points on a parabola using graphs, tables, and symbolic methods To find the vertex of a parabola from knowing its x- intercepts To model real-world situations with the vertex form of a quadratic equation

2. Making the Most of It Find the dimensions of at least eight different rectangular regions, each with perimeter 24 meters. You must use all of the fencing material for each garden. Find the area of each garden. Make a table to record the width, length, and area of the possible gardens. It’s okay to have widths that are greater than their corresponding lengths. Width (m) Length (m) Area (m 2 )

3. Enter the data for the possible widths into list L1. Enter the area measures into list L2. Which garden width values would give no area? Add these points to your lists. Label a set of axes and plot points in the form (x, y), with x representing width in meters and y representing area in square meters. Describe as completely as possible what the graph looks like. Does it make sense to connect the points with a smooth curve?

4. Making the Most of It Where does your graph reach its highest point? Which rectangular garden has the largest area? What are its dimensions? Width (m) Length (m) Area (m 2 )

5. Create a graph of (width, length) data. What is the length of the garden that has a width of 2 meters? Width 4.3 meters? Write an expression for length in terms of width x. Using your expression for the length from the previous step, write an equation for the area of the garden. Enter this equation into Y1 and graph it. Does the graph confirm your answer for the size of the rectangle with the largest area?

6. Locate the points where the graph crosses the x- axis. What is the real-world meaning for these points? Do you think the general shape of a garden with maximum area would change for different perimeters? Explain your answer.

7. The two points on the x-axis are the x-intercepts. The x-values of those points are the solutions to the equation y=f(x) when the function value is equal to zero. These solutions are the roots of the equation f(x)=0.

8. Example A Use a graph and your calculator’s table function to approximate the roots of 0=x 2 +3x – 5

9. The line through the vertex that cuts a parabola into two mirror images is called the line of symmetry. If you know the roots, you can find the vertex and the line of symmetry.

10. Example B Find the equation of the line of symmetry, and find the coordinates (h, k) of the vertex of the parabola y=x 2 + 3x - 5. Then write the equation in the form y=a(x - h) 2 + k.

11. Example B Averaging the two roots 1.193 and - 4.193 gives 1.5. The x-coordinate for the vertex is - 1.5. Use the equation to find the value of y at x = -1.5

13. The graph is a transformation of the parent function, f (x)=x 2. The vertex, (h, k), is (1.5, 7.25), so there is a translation left 1.5 units and down 7.25 units. Substitute the values h and k into the equation to get y=(x - 1.5) 2 - 7.25. Enter the equation into Y2 and graph it.