1. How to ? Subnetting

2. Scenario How Many Networks? 2 How Many Network addresses are required? 2 Addresses Used: 192.168.10.0 subnet mask 255.255.255.0 192.168.20.0 subnet mask 255.255.255.0 How Many wasted addresses on each network? Network 1 Network 2 25 hosts Network1 Network2 2 52 2 27

3. Current Address Space 192.168.10.0/24 192.168.20.0/24 Total Addresses = 256 Useable Addresses = 254 Total Addresses = 256 Wasted Addresses = 254 Wasted Addresses = 227 0 255 First Address Last Address 0 255

4. How to Subnet - 1 Write down last byte of host address as binary number: 192.168.10.00000000 How many bits do you need to borrow? 192.168.10.0 0 0 0 0 0 0 0 Rewrite Host part 192.168.10.0 0 0 0 0 0 0 0 Host part Given class C address – 192.168.10.0/24, how can you create two different network addresses Borrow bits from host byte 1 bit borrowed = 2 1 networks 2 bit borrowed = 2 2 networks 4 networks – 2 = 2 Required

5. How to Subnet - 2 192.168.10.0 0 0 0 0 0 0 0 Host part How Many hosts per network? 2 6 = 64 hosts What are different network addresses? 192.168.10.0 192.168.10.64 192.168.10.128 192.168.10.192 First Address - Unuseable Last Address - Unuseable Useable Addresses 192.168.10.64 192.168.10.128

6. How to Subnet – new subnet mask 192.168.10.0 0 0 0 0 0 0 0 Underline network part: How many bits for network id 26 bits = new subnet mask or 255.255.255.128+64 or255.255.255.192 192.168.10.64/26 192.168.10.128/26 Assign NEW SUBNET MASK TO to different networks

7. New Address Spaces 0 63 64 127 128 191 192 255 New Address Space : 256/4 = 64 192.168.10.0/24 has changed to four address blocks as shown below: 192.168.10.0/26 192.168.10.64/26 192.168.10.128/26 192.168.10.191/26

8. What changed after Subnetting Address Address Space is segmented - 256 addresses are segmented to four blocks of 64 each Subnet mask changed from 24 to 26 Number of useable IP addressed reduced from 254 to 62

9. Any Questions Complete your worksheet now