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Satellites What keeps them in orbit?. Satellites A satellite is any projectile given a large enough velocity so its path follows the curvature of the.

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Presentation on theme: "Satellites What keeps them in orbit?. Satellites A satellite is any projectile given a large enough velocity so its path follows the curvature of the."— Presentation transcript:

1 Satellites What keeps them in orbit?

2 Satellites A satellite is any projectile given a large enough velocity so its path follows the curvature of the earth.

3 How fast is the earth moving? The earth moves 8000 m in the “X” direction and 4.9 m in the “Y” direction every second. Therefore, if a projectile moves equal or greater than that speed it will follow the curvature of the earth (it will never collide with earth)

4 Satellite in Orbit (cannonball example)

5 What makes a satellite go? All objects in circular motion must have an applied force (usually thrust force). The centripetal force (inward force) acting on a satellite is gravity. Gravity pulls any satellite towards the center of the earth. Gravity must equal applied force in order for satellites to orbit What happens if its less? greater?

6 Facts about satellites As the distance from earth increase:  Radius increase  Force of gravity decreases  Acceleration decreases  Result = required velocity is less

7 Satellite problem constants Radius of the earth = 6.38 x 10 6 m Mass of the earth = 5.97 x 10 24 kg Remember…the radius of a satellite is the height above the surface of the earth plus the radius of the earth.

8 Satellites d = distance above Earth + radius of Earth Use meters!

9 Satellite Practice Problems #1 Find the altitude of a satellite orbiting earth if it is moving at 6,900 m/s and the pull of gravity is 5.69 m/s 2 Answer: a = v 2 r Solve for “r”

10 Satellite Practice Problems #1 R = (6,900 m/s) 2 5.69 m/s 2 R = 8.4 x 10 6 m - 6.38 x 10 6 m R = 2.02 x 10 6 m

11 Satellite Practice Problems #2 Find the velocity needed to keep a satellite orbiting if it is accelerating at a rate of 8.2 m/s 2 and it is 5.00 E5 m above the surface of the earth. Answer: a = v 2 r v 2 = a x r …v = (sqrt)8.2 x 6.87 E6 m v = 7500 m/s


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