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**Multiplying and Dividing Integers**

2-3 Multiplying and Dividing Integers Course 3 Warm Up Problem of the Day Lesson Presentation

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**Multiplying and Dividing Integers**

Course 3 2-3 Multiplying and Dividing Integers Warm Up Multiply or divide. 1. 5(8) 40 2. 6(12) 72 36 9 49 7 3. 4 4. 7 192 16 12 5. 18(7) 126 6.

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**Multiplying and Dividing Integers**

Course 3 2-3 Multiplying and Dividing Integers Problem of the Day Complete the pyramid by filling in the missing numbers. Each number is the sum of the numbers in the two boxes below it. –4 –8 4 –7 –1 5 –9 8 2 –3

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**Multiplying and Dividing Integers**

Course 3 2-3 Multiplying and Dividing Integers Learn to multiply and divide integers.

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**Insert Lesson Title Here**

Course 3 2-3 Multiplying and Dividing Integers Insert Lesson Title Here A positive number multiplied by an integer can be written as repeated addition. 3(–200) = –200 + (–200) + (–200) = –600 From what you know about adding and subtracting integers, you can see that a positive integer times a negative integer is negative.

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**Insert Lesson Title Here**

Course 3 2-3 Multiplying and Dividing Integers Insert Lesson Title Here You know that multiplying two positive integers together gives you a positive answer. Look for a pattern in the integer multiplication at right to understand the rules for multiplying two negative integers. 3(–200) = 2(–200) = 1(–200) = 0(–200) = –1(–200) = –2(–200) = –3(–200) = –600 + 200 –400 + 200 –200 + 200 The product of two negative integers is a positive integer. 200 400 600

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**MULTIPLYING AND DIVIDING TWO INTEGERS**

Course 3 2-3 Multiplying and Dividing Integers Insert Lesson Title Here MULTIPLYING AND DIVIDING TWO INTEGERS If the signs are the same, the sign of the answer is positive. If the signs are different, the sign of the answer is negative.

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**Additional Example 1A & 1B: Multiplying and Dividing Integers**

Course 3 2-3 Multiplying and Dividing Integers Additional Example 1A & 1B: Multiplying and Dividing Integers Multiply or divide. A. –6(4) Signs are different. = –24 Answer is negative. B. –8(–5) Signs are the same. = 40 Answer is positive.

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**Additional Example 1C & 1D: Multiplying and Dividing Integers**

Course 3 2-3 Multiplying and Dividing Integers Additional Example 1C & 1D: Multiplying and Dividing Integers Multiply or divide. –18 2 C. Signs are different. = –9 Answer is negative. –25 –5 D. Signs are the same. = 5 Answer is positive.

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**Multiplying and Dividing Integers**

Course 3 2-3 Multiplying and Dividing Integers Try This: Example 1A & 1B Multiply or divide. A. 5(–2) Signs are different. = –10 Answer is negative. B. –3(–2) Signs are the same. = 6 Answer is positive.

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**Multiplying and Dividing Integers**

Course 3 2-3 Multiplying and Dividing Integers Try This: Example 1C & 1D Multiply or divide. –24 3 C. Signs are different. = –8 Answer is negative. –12 –2 D. Signs are the same. = 6 Answer is positive.

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**Multiplying and Dividing Integers**

Course 3 2-3 Multiplying and Dividing Integers Order of Operations 1. Parentheses 2. Exponents 3. Multiply and divide from left to right. 4. Add and subtract from left to right. Remember!

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**Multiplying and Dividing Integers**

Course 3 2-3 Multiplying and Dividing Integers Additional Example 2A & 2B: Using the Order of Operations with Integers Simplify. A. 3(–6 – 12) Subtract inside the parentheses. = 3(–18) Think: The signs are different. = –54 The answer is negative. B. –5(–5 + 2) Subtract inside the parentheses. = –5(–3) Think: The signs are the same. = 15 The answer is positive.

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**Additional Example 2C: Using the Order of Operations with Integers**

Course 3 2-3 Multiplying and Dividing Integers Additional Example 2C: Using the Order of Operations with Integers Simplify. C. –2(14 – 5) Subtract inside the parentheses. = –2(9) Think: The signs are different. = –18 The answer is negative.

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**Multiplying and Dividing Integers**

Course 3 2-3 Multiplying and Dividing Integers Try This: Example 2A & 2B Simplify. A. 2(1 – 8) Subtract inside the parentheses. = 2(–7) Think: The signs are different. = –14 The answer is negative. B. 4(–3 – 8) Subtract inside the parentheses. = 4(–11) Think: The signs are different. = –44 The answer is negative.

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**Multiplying and Dividing Integers**

Course 3 2-3 Multiplying and Dividing Integers Try This: Example 2C Simplify. C. –3(6 – 9) Subtract inside the parentheses. = –3(–3) Think: The signs are the same. = 9 The answer is positive.

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**Multiplying and Dividing Integers**

Course 3 2-3 Multiplying and Dividing Integers The order of operations can be used to find ordered pair solutions of integer equations. Substitute an integer value for one variable to find the value of the other variable in the ordered pair.

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**Additional Example 3: Plotting Integer Solutions of Equations**

Course 3 2-3 Multiplying and Dividing Integers Additional Example 3: Plotting Integer Solutions of Equations Complete a table of solutions for y = 3x – 1 for x = –2, –1, 0, 1, and 2. Plot the points on a coordinate plane. y 10 8 6 4 2 2 4 6 8 x 3x – 1 y (x, y) –2 –1 1 2 (2, 5) 3(–2) – 1 –7 (–2, –7) (1, 2) 3(–1) – 1 –4 (–1, –4) x (0, –1) 10 8 6 4 3(0) – 1 –1 (0, –1) (–1, –4) 3(1) – 1 2 (1, 2) (–2, –7) 3(2) – 1 5 (2, 5)

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**Multiplying and Dividing Integers**

Course 3 2-3 Multiplying and Dividing Integers Try This: Example 3 Complete a table of solutions for y = 2x – 3 for x = –2, –1, 0, 1, and 2. Plot the points on a coordinate plane. y 10 8 6 4 2 2 4 6 8 x 2x – 3 y (x, y) –2 –1 1 2 2(–2) – 3 –7 (–2, –7) (2, 1) 2(–1) – 3 –5 (–1, –5) x (1, –1) 10 8 6 4 2(0) – 3 –3 (0, –3) (0, –3) (–1, –5) 2(1) – 3 –1 (1, –1) (–2, –7) 2(2) – 3 1 (2, 1)

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**Multiplying and Dividing Integers Insert Lesson Title Here**

Course 3 2-3 Multiplying and Dividing Integers Insert Lesson Title Here Lesson Quiz: Part 1 Perform the given operations. 1. –8(4) –32 2. –12(5) –10 6 Evaluate the expressions for the given value of the variable. 3. –4t – 9 for t = –6 15 –36 t for t = 9 –4

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**Multiplying and Dividing Integers Insert Lesson Title Here**

Course 3 2-3 Multiplying and Dividing Integers Insert Lesson Title Here Lesson Quiz: Part 2 5. Complete a table of solutions for y = 4x + 1 for x = –3, –1, 1, and 3. x 4x + 1 y (x, y) –3 –1 1 3 4(–3) + 1 –11 (–3, –11) 4(–1) + 1 –3 (–1, –3) 4(1) + 1 5 (1, 5) 4(3) + 1 13 (3, 13)

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