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Instructor: Irvin Roy Hentzel Office 432 Carver Phone

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1 Instructor: Irvin Roy Hentzel Office 432 Carver Phone 515-294-8141
Math 307 Spring, 2003 Hentzel Time: 1:10-2:00 MWF Room: 1324 Howe Hall Instructor: Irvin Roy Hentzel Office 432 Carver Phone Text: Linear Algebra With Applications, Second Edition Otto Bretscher

2 Monday, March 24 Chapter 5.3 Page Problems 2,6,8,12,34 Main Idea: Orthonormal vectors make Orthogonal matrices. Key Words: QR-Factorization, (A B)T = BT AT, Transpose, VoW = V T W = WT V. Goal: Learn about orthogonal matrices and the matrix of orthogonal projections.

3 Previous Assignment Page 199 Problem 14 Using paper and pencil, perform the Gram-Schmidt process on the sequences of vectors given in Exercises 1 through 14. V1 V2 V3

4 W1 = V1 = 1 7 1 V2oW W2 = V W1 = = 0 W1oW

5 W3 = V3oW V3oW V W W2 = = 1 W1oW W2oW

6 Basis 1/ /Sqrt[2] 0 1/Sqrt[2] 1

7 Page 199 Problem 28 Using paper and pencil, find the QR factorizations of the matrices in Exercises 15 through 28.

8 | 1/10 -1/Sqrt[2] || | | | | 7/ /Sqrt[2] || 0 Sqrt[2] 0 | = | | | 1/ /Sqrt[2] || Sqrt[2]| | | | 7/ /Sqrt[2] || | | 7 7 6|

9 Page 199 Problem 40 Consider an invertible nxn matrix A whose columns are orthogonal, but not necessarily orthonormal. What does the QR Factorization of A look like?

10 Since A is invertible, the columns of A are non
zero. If A = [ C1 C Cn ] of lengths d1, d2, ... dn then

11 A is invertible, the columns of A are nonzero.
If A = [ C1 C Cn ] of lengths d1, d2, ... dn then | d | | d | | | A = [1/d1 C1 1/d2 C /dn Cn ] | | | | | dn|

12 Vectors V1 V2 ... Vn are orthonormal if
Vi o Vj = 0 for i =/= j and Vi o Vi = 1 for all i. Then nxn matrix is called orthogonal if its columns are orthonormal vectors.

13 Properties of orthogonal matrices.
(i) AT A = A AT = I (ii) A -1 = A T (iii) | A V | = | V | A preserves lengths. (iv) If A and B are orthogonal, then AB is orthogonal. (v) If A is orthogonal, then A -1 is orthogonal. Proof: Suppose [V1 V2 ... Vn ] is an orthogonal matrix.

14 Then | V1 T | | | | | | V2 T | | | | | | | | V1 V Vn| = | | | | | | | | | | | | | | | Vn T | | | | |

15 We show Part (i). This is just the statement that Vi o Vj = 0 if i =/= j and Vi o Vi = 1 for all i. This shows that A T A = I. But then A T is A -1 and so it works on the other side as well giving A A T = I.

16 Part (ii) is a consequence of Part (i).

17 Part (iii) | A V | 2 = A V o A V = (A V) T A V = V T A T A V = VT V = | V | 2

18 Part (iv) If A and B are orthogonal, then
(AB) T (AB) = B T A T A B = I. Thus the columns of AB are also orthonormal.

19 Part (v) If A is orthogonal, then A A T = I and so
the columns of A T are also orthonormal.

20 The matrix of an orthogonal projection.
Consider a subspace V or R n with orthonormal basis V1, V2 ... Vm. The matrix of the orthogonal projection onto V is | | A A T where A = | V1 V Vm |

21 Page 209 Example 7. Find the matrix of the orthogonal projection onto the subspace of R 4 spanned by | 1 | | 1 | ½ | 1 | ½ | -1 | | 1 | | -1 |

22 Solution | ½ ½ | | ½ ½ | | ½ - ½ || ½ ½ ½ ½ | = | 0 ½ ½ 0 | | ½ - ½ || ½ - ½ - ½ ½ | | 0 ½ ½ 0 |

23


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