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Corrosion Management on Pipeline with Cathodic Protection

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Presentation on theme: "Corrosion Management on Pipeline with Cathodic Protection"— Presentation transcript:

1 Corrosion Management on Pipeline with Cathodic Protection
Ilmu Bahan dan Korosi

2 Outline Pipeline Risks and Corrosion
Cp Technique : Galvanic Sacrificial Anode (Principle, Installation) Cp Technique : Impressed Current (Principle, Installation) Case Study : Sacrificial Anode Case Study : Impressed Current

3 Risks on Pipeline RISK = PROBABILITY x SEVERITY
The product of the frequency with which an event is anticipated to occur and the consequence of the event outcome. RISK = PROBABILITY x SEVERITY

4 Risks on Pipeline PRESSURE DROP LEAKAGE CORROSION

5 Corrosion Control Coating : insulation
Cathodic Protection: DC current injection towards pipeline, result: pipeline is “shifted” as cathode. Sacrificial anode Impressed current

6 Galvanic Sacrificial Anode - Principle
Metal Driving voltage (Vd) Negative Vd = active metal =tendency to corrode Pipeline: connected with active metal Anode: Mg, Zn Cathode: pipeline Corrosion on Mg, Zn hence “sacrificial”

7 Galvanic Sacrificial Anode-Principle
Material Driving Voltage (V) Silver (Ag/Ag+) (cathodic) Copper (Cu/Cu2+) +0.34 Water (O2+H20+4e- = 4OH-) +0.401 Hydrogen (H2) (reference) Iron (Fe/Fe2+) -0.44 Zinc (Zn/Zn2+) -0.76 Magnesium (Mg2+) (anodic)

8 Galvanic Sacrificial Anode-Installation
(Source: Peabody’s Control of Pipeline Corrosion)

9 Galvanic Sacrificial Anode-Installation
(Source: Peabody’s Control of Pipeline Corrosion)

10 (Source: Peabody’s Control of Pipeline Corrosion)
Impressed Current (Source: Peabody’s Control of Pipeline Corrosion) Minimum potential: -0.85V Reference electrode: Copper Sulfate

11 Galvanic Sacrificial Anode-Design
Calculate total area to be protected (Ap) Determine the current density (ρ) Calculate total protection current (Itot = ρ .Ap) Calculate R per anode : R = f(d,l,ρ) Calculate Ia per anode : (Vd-0.85/R) Calculate total anode needed : Initial : N=Itot/In Lifetime: N = f(mass,lifetime,A/poundyear)

12 Impressed Current-Principle
Rectifier Variable voltage, variable current Higher current density (> 1 A) Higher soil resistivity (> 104 Ωcm)

13 Impressed Current-Installation
Types of anode: Graphite : big CR (pound/A/year) High Silicon Cast Iron : medium CR Platinum & niobium : small CR Rectifier rating: Voltage, Amperes, Watt, Freq. Cooling System : Air, Oil Efficiency CR: Consumption Rate

14 Impressed Current - Installation
(Source: Peabody’s Control of Pipeline Corrosion)

15 Impressed Current - Design
Calculate total area to be protected (Ap) Determine curent density (ρ) Calculate total protection current (Ip) Calculate total anode needed (N) Initial Lifetime Calculate total anode resistance (Rtot = f(N,ρ,d,L,spacing)) Calculate rectifier specification (Vdc, Idc, Pdc = f(Rtot,Ip)

16 Pipeline Cathodic Protection– Case Study

17 Galvanic Sacrificial Anode – Case Study
Variabel Nilai Pipe Diameter (d) a. 2 inch = m b. 1 inch = m Pipe Length (l) a. 2 inch pipe: 300m b. 1 inch pipe: 1300m Soil Resistivity (average) 4500 Ωcm Current Density (ρ) 9mA/sqmm Type of Anode Magnesium, weight 9 pon, r = 8.89cm, l = 53.54cm Coating efficiency (n) 50% Lifetime 20 years

18 Galvanic Sacrificial Anode – Case Study
Step 1: surface area of pipeline Step 2: total protection area Step 3: total protection current

19 Galvanic Sacrificial Anode – Case Study
Step 4: Anode resistance (Dwight’s Equation) Step 5: Current per Anode

20 Galvanic Sacrificial Anode – Case Study
Step 6: Total Number of Anode Initial Lifetime Selected number of anodes: 31.

21 Galvanic Sacrificial Anode – Case Study
Step 7: Distribution and Layout Distribution Layout Type of Pipe Effective Surface (Ac) Number of Anode (Ac/A) Diameter 2inch (0.0508m) Diameter 1inch (0.0254m) Total 31

22 Impressed Current Case Study
Variabel Value Pipe Diameter (d) 6 inch = 0,1524 m Pipe Lengyth (l) 6800 feet = 2072 m = 2,072 km Soil Resistivity (average) 2000 Ωcm Current Density (ρ) 30mA/sqmm Type of Anode Stated in next section Coating Efficiency (n) 50% Coating Impedance 25000Ω/m2 Maximum Groundbed Resistance 2Ω Lifetime 15years

23 Impressed Current Case Study
Step 1: surface area of pipeline Step 2: total protection area Step 3: total protection current Step 4: determine type of anodes Iron Silicon Chromium. Weight: 110 pon, cross section 4 sqft (0,371m2), diameter 10 inch (0,833 feet = 2,54cm), length 84 inchi (7 feet = 20,32cm)

24 Impressed Current Case Study
Step 5: total number of anodes Current limit (silicon: A/m2) Lifetime Total anodes: 4.

25 Impressed Current –Case Study
Step 6: groundbed resistance calculation Resistance limit: 2Ω (to limit rectifier’s spec) Spacing: S = 30 feet , Anode Length: L = 7 feet Anode Diameter: D = feet Groundbed resistance is below limit. If not, choose longer spacing.

26 Impressed Current - Principle
Step 7: rectifier specification Specification: 21VDC, 302W . Final Results: Anodes : Iron Silicon Chromium, 4 anodes. Rectifier : 21VDC, 302W.


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