Download presentation

Presentation is loading. Please wait.

Published byCecily Craig Modified over 9 years ago

1
1 Press Ctrl-A ©G Dear 2011 – Not to be sold/Free to use Stopping Distances Stage 6 - Year 11 Applied Mathematic (Preliminary General 1)

2
2 End of Slide 50 km/h 23 m 60 km/h 30 m 80 km/h 47 m 100 km/h 70 m

3
3 www.liikenneturva.fi/www/en/animaatiot/pysahtymismatka_ENG.swf

4
4 50 km/h 0m10m20m30m40m50m60m70m www.rta.nsw.gov.au/roadsafety/speedandspeedcameras/speedingresearch.html 29 metres No Impact

5
5 60 km/h 0m10m20m30m40m50m60m70m www.rta.nsw.gov.au/roadsafety/speedandspeedcameras/speedingresearch.html 38 metres Impact at 44 km/h

6
6 70 km/h 0m10m20m30m40m50m60m70m www.rta.nsw.gov.au/roadsafety/speedandspeedcameras/speedingresearch.html 48 metres Impact at 62 km/h

7
7 80 km/h 0m10m20m30m40m50m60m70m www.rta.nsw.gov.au/roadsafety/speedandspeedcameras/speedingresearch.html 59 metres Impact at 78 km/h

8
8 90 km/h 0m10m20m30m40m50m60m70m www.rta.nsw.gov.au/roadsafety/speedandspeedcameras/speedingresearch.html 70 metres Impact at 90 km/h End of Slide

9
9 End of Slide http://www.auburn.nsw.gov.au/uploadedFiles/Stopping%20Distance%20v08%281%29.pdf

10
10 End of Slide http://www.auburn.nsw.gov.au/uploadedFiles/Stopping%20Distance%20v08%281%29.pdf

11
11 End of Slide

12
12 End of Slide A car travelling at 100 km/h [28 m/s] breaks with a deceleration of 14m/s 2. How long does it take to stop after breaking? v = u + at Final Velocity 0 m/s Starting Velocity 100 km/h Deceleration 5 m/s 2 Time ?

13
13 End of Slide How long does it take to stop after breaking? v = u + at v = 0 m/s u = 28 m/s a = -14 m/s 2 0 =28- 14t +14t 14t = 28 ÷14 t = 2 seconds A car travelling at 100 km/h [28 m/s] breaks with a deceleration of 14m/s 2.

14
14 End of Slide How far does it take to stop after breaking? s = ut + ½at 2 v = 0 m/s u = 28 m/s a =-14 m/s 2 s = t = 2 s 28x 2x 2+ 0.5x -14x 22x 22 = 28 metres A car travelling at 100 km/h [28 m/s] breaks with a deceleration of 14m/s 2. Distance

15
15 End of Slide What is the total stopping distance? v = 0 m/s u = 28 m/s a = -14 m/s 2 t = 2 s s = 28 m Reaction Time = 1.2 seconds Distance = 1.2sx 28 m/s = 34 metres Total = 34 + 28 = 62 metres A car travelling at 100 km/h [28 m/s] breaks with a deceleration of 14m/s 2.

16
16 End of Show Drive a vehicle with ABS. [Anti-locking Breaking System] Video

Similar presentations

© 2024 SlidePlayer.com Inc.

All rights reserved.

To make this website work, we log user data and share it with processors. To use this website, you must agree to our Privacy Policy, including cookie policy.

Ads by Google