Download presentation

Presentation is loading. Please wait.

Published byElvin Bell Modified over 5 years ago

1
Quadratic Equations Algebra I

2
Vocabulary

3
Solutions – Called roots, zeros or x intercepts. The point(s) where the parabola crosses the x axis. Minimum – The lowest point of the parabola on the y axis (on the calculator, when the y value is the lowest). Maximum – The highest point of the parabola on the y axis (on the calculator, when the y value is the highest).

4
Vocabulary Number of roots – Can have one, two or no roots. Vertex – The minimum or maximum point. Positive Parabola – Going up. Negative Parabola – Going down.

5
Vocabulary Axis of Symmetry – Directly down the middle of the parabola. The only point in the middle of the parabola is the vertex. Each point on the parabola that is on one side of the axis of symmetry has a corresponding point on the other side of the axis of symmetry.

6
Axis of Symmetry Axis of symmetry equation – finding the x value. x = Ex) y = -3x² – 6x + 4 a = -3 b = -6 c = 4

7
Axis of Symmetry Axis of symmetry equation – finding the x value. Ex) y = -3x² – 6x + 4 a = -3 x = -(-6)/2(-3) b = -6 x = -1 c = 4

8
Axis of Symmetry Find the y value by substituting the x value into the equation and solve for y. Ex) y = -3x² – 6x + 4 x = -1 y = -3(-1)²- 6(-1) + 4 y = 7 Vertex (-1, 7)

9
Axis of Symmetry Calculator – Enter the equation into the y= function on the calculator – Look at the graph to determine a positive or negative parabola – Go to 2 nd graph to see the table Scroll up and down to find where the y values start to repeat, there will be one point that doesn’t repeat, this is the vertex. The number in the x column is the x value and the corresponding number in the y column is the y value.

10
Example y = x²- x - 6

11
Example y = x²- x – 6 (not found in calculator) a = 1 x = -(-1)/2(1) b = -1 x = ½ c = -6 y = (½)²- ½ - 6 y = -6¼ Vertex (½, -6¼)

12
Now you try… y = 2x²- 4x – 5 y = -x²+ 4x - 1

13
Now you try… y = 2x²- 4x – 5 (1,-7) minimum y = -x²+ 4x – 1 (2,3) maximum

14
Roots Can solve by factoring x²+ 6x – 7 = 0

15
Roots Can solve by factoring x²+ 6x – 7 = 0 (x + 7)(x – 1) = 0

16
Roots Can solve by factoring x²+ 6x – 7 = 0 (x + 7)(x – 1) = 0 Now set each factor =0

17
Roots Can solve by factoring x²+ 6x – 7 = 0 (x + 7)(x – 1) = 0 x + 7 = 0 x – 1 = 0 x = -7 x = 1 *** Two roots (sometimes called a double root)

18
Roots b²+ 4b = -4 (re write =0) b²+ 4b + 4 = 0

19
Roots b²+ 4b = -4 (re write =0) b²+ 4b + 4 = 0 Now factor

20
Roots b²+ 4b = -4 (re write =0) b²+ 4b + 4 = 0 Now factor (b + 2)(b + 2) = 0 b + 2 = 0 b = -2 ***This is a single root, only one answer.

21
Roots Roots can often times be found on the calculator – Enter the equation in the y= – Graph, this will show you how many roots – Go to the table – Find where the y value is zero

22
Roots x²- x + 4 = 0

23
Roots x²- x + 4 = 0 Prime, can’t factor No x intercept – no roots (see this when you graph) – always check the graph, some are prime, but still cross the x axis.

24
Roots n²+ 6n + 7 = 0 Prime – can’t factor, but it does cross the x axis. Sometimes we estimate the roots. One root is between -5 and -4, the other root is between -2 and -1. These are rational roots.

25
Roots

32
Now you try… x²- 2x – 24 = 0 3x²+ 5x + 11 = 0

33
Now you try… x²- 2x – 24 = 0 {-4,6} This is a solution set, NOT an ordered pair. These are the numbers where the parabola crosses the x axis. 3x²+ 5x + 11 = 0 No roots – no solution

34
Discriminant To find the discriminant use part of the quadratic formula. b²- 4ac

35
Discriminant If the discriminant is < 0, there are no roots. If the discriminant is > 0, there are two roots. If the discriminant is = 0, there is one root.

Similar presentations

© 2021 SlidePlayer.com Inc.

All rights reserved.

To make this website work, we log user data and share it with processors. To use this website, you must agree to our Privacy Policy, including cookie policy.

Ads by Google