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Quadratic Applications

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Presentation on theme: "Quadratic Applications"— Presentation transcript:

1 Quadratic Applications
Maximizing Profit!

2 Formulas Profit formula is P = Total Revenue – Production Costs
Total Revenue = price • quantity sold Production Costs = cost per item • quantity sold

3 EX: Selling dresses It costs you $10 to make each dress
Other dresses follow the general model q = -20s , where q is the quantity (number sold) and s is the selling price P = Total Revenue – Production Costs, so: Revenue = price • quantity sold… sq Production Costs = cost per item • quantity sold…10q This gives us P = sq – 10q

4 Dresses, continued P = sq – 10q q = -20s + 1200
P = s(-20s ) – 10(-20s ) P = -20s s + 200s – 12000 P = -20s s – 12000 The maximum profit occurs at the vertex…

5 By finding the vertex of the parabola, we will find the selling price that will generate the most profit. The x-axis represents selling price, so the value of the x-coordinate at the vertex represents the best price. The y-value at the vertex will give the amount of profit made.

6 - The selling price that generates the maximum profit is $35 Find the x-coordinate of the vertex by applying the formula . In this case, the variable is s rather than x. The other values are a = - 20, the coefficient in the s2 term, and 1400, the coefficient in the s term.


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