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Week 10 - Monday
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What did we talk about last time? More permutations Addition rule Inclusion and exclusion
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A bundle of 120 wires has been laid underground between two telephone exchanges 10 miles apart Unfortunately, it was discovered that the individual wires are not labeled Visually, there is no way of knowing which wire is which, making connections at either end impossible Your job is to label the wires at both ends Walking is your only transportation You have a battery and a light bulb to test continuity You have tape and a pen for labeling the wires What is the shortest distance in miles you will need to walk to correctly identify and label each wire?
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Student Lecture
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How many different subsets of size r can you take out of a set of n items? Subset of size 3 out of a set of size 5? Subset of size 4 out of a set of size 5? Subset of size 5 out of a set of size 5? Subset of size 1 out of a set of size 5? This is called an r-combination, written
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In r-permutations, the order matters In r-combinations, the order doesn't Thus, the number of r-combinations is just the number of r-permutations divided by the possible orderings
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How many ways are there to choose 5 people out of a group of 12? What if two people don't get along? How many 5 person teams can you make from a group of 12 if those two people cannot both be on the team?
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How many five-card poker hands contain two pairs? If a five-card hand is dealt at random from an ordinary deck of cards, what is the probability that the hand contains two pairs?
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What if you want to take r things out of a set of n things, but you are allowed to have repetitions? Think of it as putting r things in n categories Example: n = 5, r = 4 We could represent this as x||xx|x| That's an r x's and n – 1 |'s 12345 xxxx
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So, we can think of taking an r-combination with repetitions as choosing r items in a string that is r + n – 1 long and marking those as x's Consequently, the number of r-combinations with repetitions is
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Let's say you grab a handful of 10 Starbursts Original Starbursts come in Cherry Lemon Strawberry Orange How many different handfuls are possible? How many possible handfuls will contain at least 3 cherry?
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This is a quick reminder of all the different ways you can count things: Order MattersOrder Doesn't Matter Repetition Allowed nknk Repetition Not Allowed P(n,k)P(n,k)
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Hopefully, you are all familiar with Pascal's Triangle, the beginning of which is: If we number rows and columns starting at 0, note that the value of row n, column r is exactly 1 11 121 1331 14641 1510 51 1615201561
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Pascal's Triangle works because of Pascal's Formula: We can easily show its truth:
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a + b is called a binomial Using combinations (or Pascal's Triangle) it is easy to compute (a + b) n We could prove this by induction, but you probably don't care
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Compute (1 – x) 6 using the binomial theorem
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Let A and B be events in the sample space S 0 ≤ P(A) ≤ 1 P( ) = 0 and P(S) = 1 If A B = , then P(A B) = P(A) + P(B) It is clear then that P(A c ) = 1 – P(A) More generally, P(A B) = P(A) + P(B) – P(A B) All of these axioms can be derived from set theory and the definition of probability
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What is the probability that a card drawn randomly from an Anglo-American 52 card deck is a face card (jack, queen, or king) or is red (hearts or diamonds)? Hint: Compute the probability that it is a face card Compute the probability that it is red Compute the probability that it is both
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Expected value is one of the most important concepts in probability, especially if you want to gamble The expected value is simply the sum of all events, weighted by their probabilities If you have n outcomes with real number values a 1, a 2, a 3, … a n, each of which has probability p 1, p 2, p 3, … p n, then the expected value is:
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A normal American roulette wheel has 38 numbers: 1 through 36, 0, and 00 18 numbers are red, 18 numbers are black, and 0 and 00 are green The best strategy you can have is always betting on black (or red) If you bet $1 on black and win, you get $1, but you lose your dollar if it lands red What is the expected value of a bet?
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Given that some event A has happened, the probability that some event B will happen is called conditional probability This probability is:
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Given two, fair, 6-sided dice, what is the probability that the sum of the numbers they show when rolled is 8, given that both of the numbers are even?
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Let sample space S be a union of mutually disjoint events B 1, B 2, B 3, … B n Let A be an event in S Let A and B 1 through B n have non-zero probabilities For B k where 1 ≤ k ≤ n
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Bayes' theorem is often used to evaluate tests that can have false positives and false negatives Consider a test for a disease that 1 in 5000 people have The false positive rate is 3% The false negative rate is 1% What's the probability that a person who tests positive for the disease has the disease? Let A be the event that the person tests positively for the disease Let B 1 be the event that the person actually has the disease Let B 2 be the event that the person does not have the disease Apply Bayes' theorem
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If events A and B are events in a sample space S, then these events are independent if and only if P(A B) = P(A)∙P(B) This should be clear from conditional probability If A and B are independent, then P(B|A) = P(B)
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Keep reading Chapter 9 Finish probability
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Work on Homework 8 Due Friday
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