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CHEMICAL EQUATIONS: MORE WRITING AND BALANCING PRACTICE Go through this PowerPoint for extra tips and extra practice!

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Presentation on theme: "CHEMICAL EQUATIONS: MORE WRITING AND BALANCING PRACTICE Go through this PowerPoint for extra tips and extra practice!"— Presentation transcript:

1 CHEMICAL EQUATIONS: MORE WRITING AND BALANCING PRACTICE Go through this PowerPoint for extra tips and extra practice!

2 CHEMICAL EQUATIONS Two basic rules apply in writing chemical equations:  We cannot write an equation for a reaction unless we know how the substances react and what new substances they form  Every chemical equation must be balanced (the number of atoms of each element on the left side must be the same as the number of atoms of that element on the right side of the equation) Chemical equations are balanced according to the law of conservation of mass  nothing is created from nowhere or destroyed to nowhere.  Mass of matter present after the reaction is the same as before the reaction  A rearrangement of entities at the molecular level has occurred

3 COMMUNICATING CHEMICAL REACTIONS Chemical Equations from Word Equations  Hydrogen gas burns in the presence of oxygen gas to produce water vapour H 2(g) + O 2(g)  H 2 O (g) (unbalanced) 2H 2(g) + O 2(g)  2H 2 O (g) (balanced)  Sodium metal reacts with chlorine gas to form sodium chloride Na (s) + Cl 2(g)  NaCl (s) (unbalanced) 2Na (s) + Cl 2(g)  2NaCl (s) (balanced)  A solution of silver nitrate reacts with a solution of potassium chloride to form a precipitate of silver chloride and a solution of potassium nitrate AgNO 3(aq) + KCl (aq)  AgCl (s) + KNO 3(aq)

4 COMMUNICATING CHEMICAL REACTIONS Word Equations from Chemical Equations  NaOH (aq) + HCl (aq)  NaCl (aq) + H 2 O (l) A sodium hydroxide solution and a hydrochloric acid solution will react to produce a solution of sodium chloride and liquid water  2Na (s) + 2H 2 O (l)  H 2(g) + 2NaOH (aq) Solid sodium metal and water will react to produce hydrogen gas and a solution of sodium hydroxide  C (s) + O 2(g)  CO 2(g) Solid carbon and oxygen gas will react (burn) to produce carbon dioxide gas  CaCO 3(s)  CaO (s) + CO 2(g) Solid calcium carbonate (when heated) will decompose to form solid calcium oxide and carbon dioxide gas

5 PRACTICE Rewrite the following word equations as formula equation and balance them: a)Solid potassium metal reacts with oxygen gas to produce solid potassium oxide b)Methane gas reacts with oxygen gas to produce carbon dioxide gas and water vapour c)Mercury(II) sulfide is decomposed into liquid mercury and solid sulfur d)Aqueous cobalt(III) nitrate reacts with solid zinc to produce aqueous zinc nitrate and solid cobalt.

6 PRACTICE Answers: (remember: when there is no coefficient in front of a compound, there is an invisible “1” there) a)Solid potassium metal reacts with oxygen gas to produce solid potassium oxide 4K (s) + O 2(g)  2K 2 O (s) b)Methane gas reacts with oxygen gas to produce carbon dioxide gas and water vapour CH 4(g) + 2O 2(g)  CO 2(g) + 2H 2 O (g) c)Mercury(II) sulfide is decomposed into liquid mercury and solid sulfur 8HgS (s)  8Hg (l) + S 8(s) d)Aqueous cobalt(III) nitrate reacts with solid zinc to produce aqueous zinc nitrate and solid cobalt 2Co(NO 3 ) 3(aq) + 3Zn (s)  3Zn(NO 3 ) 2(aq) + 2Co (s)

7 CHEMICAL EQUATIONS A balanced chemical equation has the total atoms/ions on reactant side equal to the total number of the same kind of atom/ions on the product side Coefficients are used as necessary in front of the chemical formulas of the skeletal equation to produce a balanced equation States of matter are provide after each chemical formula Summary and Practice on Pages 49 – 50 of Text

8 BALANCING CHEMICAL REACTION EQUATIONS General steps for balancing chemical equations  Write an equation using the correct chemical formulas  Check the formulas of the reactants and products  Determine if the equation is balanced  Count the number of atoms of each element on the left side and the right side. Count polyatomic ion as a group if its formula is unchanged  Balance the equation one element at a time  Pick an element and balance the equation for that element by placing coefficients in front of the formulas to equalize the number of that element on both sides of the equation  A typical starting point is with the most complex formula  Balance diatomic elements last  Check to see if the equation is balanced  Sometimes balancing one element will put another element out of balance. If that happens, repeat steps 3 and 4 until the equation is balanced. Make sure the coefficients you use are the smallest possible whole numbers. Never try to balance an equation by changing the subscripts in a formula – that would make the formula incorrect!

9 EXAMPLES

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11 DO NOT change correct chemical formulas and/or subscripts to make atoms of an element balance add some real or imaginary chemical species to either side of the equation just to make atoms of an element balance DO perform a check to make sure all atoms/ions balance  most chemical equations are balanced by what is called the inspection method  This is somewhat a trial and error method which succeeds in most instances Practice is necessary to become successful Useful strategies develop as practice continues.

12 PRACTICE Balance the following chemical equations 1.__Na (s) + __O 2(g)  __Na 2 O (s) 2.__HI (g)  __H 2(g) + __I 2(g) 3.__SnF 4(aq) + __Cr (s)  __CrF 3(aq) + __Sn (s) 4.__(NH 4 ) 3 PO 4(aq) + __CaBr 2(aq)  __Ca 3 (PO 4 ) 2(s) + __NH 4 Br (aq) 5.__C 3 H 8(g) + __O 2(g)  __CO 2(g) + __H 2 O (g) 6.__Al(NO 3 ) 3(aq) + __NaOH (aq)  __NaNO 3(aq) + __Al(OH) 3(s)

13 PRACTICE Answers: (Remember: it is not necessary to write down the coefficient when it is “1,” I put it here to make it easier to understand. It is more conventionally correct to NOT put it.) 1.4Na (s) + 1O 2(g)  2Na 2 O (s) 2.2HI (g)  1H 2(g) + 1I 2(g) 3.3SnF 4(aq) + 4Cr (s)  4CrF 3(aq) + 3Sn (s) 4.2(NH 4 ) 3 PO 4(aq) + 3CaBr 2(aq)  1Ca 3 (PO 4 ) 2(s) + 6NH 4 Br (aq) 5.1C 3 H 8(g) + 5O 2(g)  3CO 2(g) + 4H 2 O (g) 6.1Al(NO 3 ) 3(aq) + 3NaOH (aq)  3NaNO 3(aq) + 1Al(OH) 3(s)


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