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1.4 MOMENTUM IN TWO DIMENSIONS. Momentum momentum of an object to be the product of mass (m) and velocity (v). Momentum is a vector quantity with SI Units.

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Presentation on theme: "1.4 MOMENTUM IN TWO DIMENSIONS. Momentum momentum of an object to be the product of mass (m) and velocity (v). Momentum is a vector quantity with SI Units."— Presentation transcript:

1 1.4 MOMENTUM IN TWO DIMENSIONS

2 Momentum momentum of an object to be the product of mass (m) and velocity (v). Momentum is a vector quantity with SI Units of kgms -1 (or Ns, since 1N = 1kgms -2 ).

3 Momentum in 2-Dimensions Vector Form of Newton’s Second Law of Motion Consider a particle reflecting off a surface without a change in speed. A particle has m = 2 kg and initial velocity v i = 20 m s -1 and the collision lasts for  t = 0.2 s, then determine the average force acting on the particle. v f = -20 ms -1 Acceleration a is given by, vivi vfvf m

4 Momentum in 2-Dimensions Vector Form of Newton’s Second Law of Motion a = -200ms -1 Acceleration is in opposite direction to v i. and since F = m a then F = 2 x (-200) = -400 N ie. 400 N away from the wall Ie, the wall applied a force of 400N on the ball away from the wall and due to Newtons 3 rd Law, the ball exerted a force of 400N towards the wall.

5 Vector Form of Newton’s Second Law

6 A ball of mass 0.50 kg moving at 4.0 m.s -1 rebounds off a wall, without any loss of speed, along the normal to the wall. The duration of the impact is 0.080 seconds. Calculate: Calculate: (a)The average acceleration of the ball during impact. (b)The average force applied to the ball by the wall during impact. (c)The average force applied to the wall by the ball during impact. v i = 4.0 m.s -1 Example 1 v f = - 4.0 m.s -1

7 Example 2

8 Newton’s Second Law in Terms of Momentum provided that the mass of the particle is fixed.

9 Example 3

10 A ball of mass 0.07 kg moving at 1.0 m.s -1 rebounds off a wall with a velocity of 0.60 m.s -1 as shown in the diagram. The duration of the impact is 0.010 seconds. Calculate: (a)The average force acting on the ball during impact. (b)The average acceleration of the ball during impact. (c)The average force exerted on the wall during impact. Example 4 v i = 1.0 m.s -1 v f = - 0.60 m.s -1

11 Example 5

12 Law of Conservation of Momentum In an isolated system, the total momentum of the system remains constant. isolated no net external forces act upon the system system a group of objects e.g. “two pucks” or “a person and the Earth”

13 Law of Conservation of Momentum

14 Multi-Image Photographs The collision of two objects (or the explosion of one) can be documented by taking a multi-image photograph. Using this, it is possible to determine whether momentum is conserved. See PowerPoint (Multi image collision examples)

15 1.Draw diagrams showing the situation before and after impact. 2.Label the momenta of each object in these diagrams using subscripts. 3.Find equations for the total momentum before and the total momentum after impact. BE CAREFUL TO USE VECTORS. 4.Use the Law of Conservation of Momentum and solve for the unknown. Conservation of Momentum Calculations

16 Conservation of Momentum NB.(1) No net external forces means an isolated system. (2) Total linear momentum refers to both size and direction (vector addition is needed to find the total) (3) Conserved means that it stays the same (throughout the interaction) (4) The objects may be deformed, broken apart, stuck together or exploded. However momentum is still conserved as long as no net external forces act.

17 Example A rail wagon of mass 4.0 tones, moving 3ms -1 North collides with another wagon of mass 2.0 tones. They stick together. What is their combined velocity? Take North to be the positive direction, Momentum in 2-Dimensions The Law of Conservation of Momentum

18 Momentum in 2-Dimensions The Law of Conservation of Momentum Assuming the system isolated, linear momentum is conserved.

19 Momentum in 2-Dimensions The Law of Conservation of Momentum Example A body at rest explodes breaking into 3 pieces. One piece flies off due East at 30ms -1. Another piece flies of due North at 30ms -1. What is the velocity of the 3 rd piece if its mass is 3 times that of the other pieces?

20 Cart A is travelling North with a velocity of 5.4 m.s -1 while Cart B is travelling South at 8.3 m.s -1. The mass of Cart A is 13 kg and the mass of Cart B is 9.0 kg. The carts collide and Cart B rebounds with a velocity of 7 m.s -1. Determine the velocity of Cart A after the collision. Example 6

21 The blue car with mass 1000 kg and is travelling at 20 m.s -1 East. The red car with mass 1000 kg and is travelling at 10 m.s -1 North. What is the final velocity of the two cars stuck together? Example 7

22 A spherical mass of 9.0 kg explodes into 3 pieces. One piece, of mass 3.0 kg flies off due North at 10 m.s -1 whereas another piece of mass 4.0 kg is thrown West at a speed of 13 m.s -1. Find the velocity of the third piece. Example 8

23 Application: Spacecraft Propulsion Rockets Initially the rocket has no momentum. When the gases leave the back of the rocket, their momentum must be balanced by the rocket gaining momentum forwards.

24 Application: Spacecraft Propulsion https://www.youtube.com/watch?v=rt5dcrm8 X1w

25

26 Solar Sails

27 Consider a photon reflected from a solar sail. The photon’s change in momentum is directed away from the sail. Hence the sail must gain momentum in the opposite direction of the photon (Conservation of Momentum). sail

28 Solar Sails sail

29 Solar Sails sail

30 Solar Sails


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