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Section 3: Dilutions Dilutions Calculations. DDilutions llowers concentration, or molarity but… ttotal moles of solute does not change A. Dilutions.

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Presentation on theme: "Section 3: Dilutions Dilutions Calculations. DDilutions llowers concentration, or molarity but… ttotal moles of solute does not change A. Dilutions."— Presentation transcript:

1 Section 3: Dilutions Dilutions Calculations

2 DDilutions llowers concentration, or molarity but… ttotal moles of solute does not change A. Dilutions mol L M = mol L M =

3 A. Dilutions 6 mol in 100 mL 6 mol in 200 mL same # of mol

4 A. Dilutions

5  Dilutions A. Dilutions initial Molarity initial Volume Molarity of dilute solution Volume of dilute solution

6 HHow many mL of 2.00 M MgSO 4 must be diluted to prepare 100 mL of 0.400 M MgSO 4 ? V 1 = (0.400 M) x (100 mL) = (2.00 M) B. Calculations  Finding Volume (V 1 ) 20.0 mL M1M1 V2V2 M2M2 V1V1 (2.00 M) x V 1 = (0.400 M) x (100 mL)

7 2200 mL of 10.0 M NaOH is diluted to 500 mL, what is the molarity of the dilute solution? M 2 = (10.0 M) x (200 mL) = (500 mL) B. Calculations  Finding Molarity (M 2 ) 4.00 M M1M1 V2V2 M2M2 V1V1 (10.0 M) x (200 mL) = M 2 x (500 mL)


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