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Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0.

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Presentation on theme: "Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0."— Presentation transcript:

1 Bell Work: Solve for x: 5y + x – 2y – 4 + 3x = 0

2 Answer: x = -3/4 y + 1

3 Lesson 43: Least Common Multiple, Least Common Multiples of Algebraic Expressions

4 If we are given the numbers 4, 5, and 8 And are asked to find the smallest number that is evenly divisible by each of the numbers, a reasonable guess would be the product of the numbers, which is 160, because we know that each of the numbers will divide 160 evenly 160/4 = 40 160/5 = 32160/8 = 20

5 But 160 is not the smallest number that is evenly divisible by the three numbers. The number 40 is. 40/4 = 10 40/5 = 8 40/8 = 5

6 We call the smallest number that can be divided evenly by each of a group of specified numbers the least common multiple (LCM) of the specified numbers.

7 We can find the LCM of some numbers by making mental calculations, but it is nice to have a special procedure to use if some of the numbers are large numbers. The procedure is as follows:

8 1. Write each number as a product of prime factors. 2. Compute the LCM by using every factor of the given numbers as a factor of the LCM. Use each factor the greatest number of times it is a factor in any of the numbers.

9 To demonstrate this procedure we will find the LCM of 18, 81, and 500 First we write each number as a product of prime factors: 18 = 2 x 3 x 3 81 = 3 x 3 x 3 x 3 500 = 2 x 2 x 5 x 5 x 5

10 Now we find the LCM by using the procedure in Step 2. The number 2 is a factor of both 18 and 500. it appears twice in 500, so it will appear twice in the LCM. 2 x 2

11 The number 3 is a factor of both 18 and 81. it appears four times in 81, so it will appear four times in the LCM. 2 x 2 x 3 x 3 x 3 x 3

12 Therefore, 40,500 is the smallest number that is evenly divisible by each of the three numbers 18, 81, and 500.

13 Example: Find the LCM of 8, 15, and 100.

14 Answer: 8 = 2 x 2 x 2 15 = 3 x 5 100 = 2 x 2 x 5 x 5 2 x 2 x 2 x 3 x 5 x 5 = 600

15 Example: Find the Least Common Multiple of 30, 75, and 80.

16 Answer: 30 = 2 x 3 x 5 75 = 3 x 5 x 5 80 = 2 x 2 x 2 x 2 x 5 2 x 2 x 2 x 2 x 3 x 5 x 5 = 1200

17 Practice: Find the LCM of 560, 588, and 1250.

18 Answer: 560 = 2 x 2 x 2 x 2 x 5 x 7 588 = 2 x 2 x 3 x 7 x 7 1250 = 2 x 5 x 5 x 5 x 5 2 x 2 x 2 x 2 x 3 x 5 x 5 x 5 x 5 x 7 x 7 = 1, 470, 000

19 The least common multiple is most often encountered when it is used as the least common denominator. If we are asked to add the fractions ¼ + 5/8 + 7/12 We rewrite each of these fractions as a fraction whose denominator is 24, which is the least common multiple of 4, 8 and 12. 6/24 + 15/24 + 14/24 = 35/24

20 In lesson 44 we will discuss the method of adding algebraic fractions. To prepare for that, we will practice finding the least common multiple of algebraic expressions.

21 Example: Find the least common multiple of 15a b and 10ab. 23

22 Answer: 15a b = 3 x 5 x a x a x b 10ab = 2 x 5 x a x b x b x b LCM = 2 x 3 x 5 x a x a x b x b x b = 30a b 2 3 23

23 Practice: Find the LCM of 4x m and 6x m. 23

24 Answer: 4x m = 2  2  x  x  m 6x m = 2  3  x  x  x  m LCM = 2  2  3  x  x  x  m = 12x m 2 3 3

25 Practice: Find the LCM of 12x am and 14x am. 22 34

26 Answer: 84x am 34

27 HW: Lesson 43 #1-30


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