1.  Naimah, Willie, Lorena, Maceo, Sean, Qwest, Elizabeth, Monet see me  Shaquana, Alexia, Nierra see me

2.  68. Cameras: Important Facts The camera is $126. This is 2/3 of the price that a photography store charges. What is the cost of the camera at the photography store?

3.  126 = 2 c 3 3 ● 126 = 2 c ● 3 Multiply the reciprocal on 2 3 2 both sides 378 = c 2 189 = c The cost of the camera is $189.

4.  71. Dances: Important Facts  Student council has a budget of $1,000.  So far they have spent $350. a. Write an equation to represent the amount of money left to spend. Let m = the amount of money left to spend m + 350 = 1,000 - 350 -350 m = 650 b. They then spent 225 on decorations. Write an equation to represent the amount of money left. 350 + 225 + m = 1,000 575 + m = 1,000

5.  c. If the student council spent their entire budget, write an equation to represent how many $6 tickets they must sell to make a profit. Let t represent the number of tickets they must sell to make a profit. 6t = 1000 6 6 t = 166.67 They must sell 167 tickets to make a profit.

6.  Do p. 86-88 25, 57, 61, 65, 79

7.  Objectives: By the end of class, students will be able to:  Solve equations with more than one step. with 90% or above mastery.

8. 13. – 34 = 6m – 4 +4 +4 Add 4 on both sides -30 = 6m 6 6 Divide 6 on both sides -5 = m

9.  15. y - 6 = 8 5 + 6 +6 Add 6 on both sides y = 14 5 (5) y = 14 (5) Multiply 5 on both sides 5 y = 70

10.  19. n – 2 = 2 7 (7) n – 2 = 2 (7) Multiply 7 on both sides 7 n – 2 = 14 +2 + 2 n = 16

11. 23. Financial Literacy: Important Facts Raul chose the business plan and has budgeted $100 per month. Write an equation for this situation, and determine how many minutes per month he can use the phone and stay within budget. Let m = number of minutes per month.15m + 49.99 = 100.00 - 49.99 - 49.99.15m = 50.01.15.15 m = 333.40 650 + 333 = 950 minutes Raul can use 983 minutes.

12.  Do p. 93 1 - 5, 7 and 8  Do on the white boards

13. 27. Find three consecutive odd integers whose sum is 57. Let n = the smallest consecutive odd integer Let n + 2 = the next largest odd integer Let n + 4 = the largest consecutive odd integer n + (n + 2) + (n + 4) = 57 3n + 6 = 57 - 6 -6 3n = 51 3 3 n = 17 the smallest odd integer So, 17, 19, 21 are three consecutive odd integers whose sum is 57.

14. 40. Family: The ages of 3 brothers are consecutive integers with the sum of 96. Let n = the smallest consecutive integer Let n + 1 = the next largest consecutive integer Let n + 2 = the largest consecutive integer n + (n + 1) + (n + 2) = 96 3n + 3 = 96 - 3 -3 3n = 93 3 3 n = 31 the youngest age So, 31, 33, and 35 are the brother’s ages.

15.  Do on whiteboards  Do p. 93 #9, 10  P. 102 Do 48

16.  1. p. 102 #52  2. p. 102 #53