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Holt CA Course 1 Solving Equations by Dividing 1-10 Warm Up Warm Up Lesson Presentation Lesson Presentation California Standards California StandardsPreview

Holt CA Course 1 Solving Equations by Dividing 1-10 Warm Up Divide. 1. 2. 3. 4. 5.6. 613 104 72 12 65 5 60 6 40 10 130 5 91 7 2613

Holt CA Course 1 Solving Equations by Dividing 1-10 Algebra & Functions Algebra & Functions (AF1.1) - Write and solve one-step linear equations in one variable. California Standards

Holt CA Course 1 Solving Equations by Dividing 1-10 Objective: You will learn how to solve whole number equations by dividing.

Holt CA Course 1 Solving Equations by Dividing 1-10 Dividing by a number is the inverse of multiplying by that number. To solve an equation that contains multiplication, use division to “undo” (Remember: “zero” each other) the multiplication. 4m = 32 44 Caution ! 4m means “4  m.” m = 8 1

Holt CA Course 1 Solving Equations by Dividing 1-10 5p = 75p is multiplied by 5. 5 p = 15 Divide both sides by 5 to undo the multiplication. Check 5p = 75 Substitute 15 for p in the equation. Solve the equation. Check your answer. 15 is the solution. 75 = 75 Example 1: Solving Equations by Dividing 5(15) = 75 5 5p = 75 1

Holt CA Course 1 Solving Equations by Dividing 1-10 16 = 8rr is multiplied by 8. 8 2 = r Divide both sides by 8 to undo the multiplication. Check 16 = 8r Substitute 2 for r in the equation. Solve the equation. Check your answer. 2 is the solution. 16 = 16 Example 2: Solving Equations by Dividing 16 = 8(2) 8 16 = 8r 1

Holt CA Course 1 Solving Equations by Dividing 1-10 8a = 72 a is multiplied by 8. 8 a = 9 Divide both sides by 8 to undo the multiplication. Check 8a = 72 Substitute 9 for a in the equation. Solve the equation. Check your answer. 9 is the solution. 72 = 72 Check It Out! Example 3 8(9) = 72 8 8a = 72 1

Holt CA Course 1 Solving Equations by Dividing 1-10

Holt CA Course 1 Solving Equations by Dividing 1-10 18 = 3ww is multiplied by 3. 3 6 = w Divide both sides by 3 to undo the multiplication. Check 18 = 3w Substitute 6 for w in the equation. Solve the equation. Check your answer. 6 is the solution. 18 = 18 Check It Out! Example 4 18 = 3(6) 3 18 = 3w 1

Holt CA Course 1 Solving Equations by Dividing 1-10

Holt CA Course 1 Solving Equations by Dividing 1-10 Procedure

Holt CA Course 1 Solving Equations by Dividing 1-10 Home Learning On-Line Tutoring

Holt CA Course 1 Solving Equations by Dividing 1-10 The area of a rectangle is 56 square inches. Its length is 8 inches. What is its width? Example 5: Problem Solving Application Remember! For a rectangle, area = length  width l a = l w

Holt CA Course 1 Solving Equations by Dividing 1-10 Example 5 Continued 1 Understand the Problem The answer will be the width of the rectangle in inches. List the important information: The area of the rectangle is 56 square inches. The length of the rectangle is 8 inches. Draw a diagram to represent this information. 56 8 w

Holt CA Course 1 Solving Equations by Dividing 1-10 Example 5 Continued 2 Make a Plan You can write and solve an equation using the formula for area. To find the area of a rectangle, multiply its length by its width. w l l A = l w 56 = 8w

Holt CA Course 1 Solving Equations by Dividing 1-10 Example 5 Continued 56 = 8w Solve 3 88 7 = w So the width of the rectangle is 7 inches. w is multiplied by 8. Divide both sides by 8 to undo the multiplication.

Holt CA Course 1 Solving Equations by Dividing 1-10 Example 5 Continued Look Back Arrange 56 identical squares in a rectangle. The length is 8, so line up the squares in rows of 8. You can make 7 rows of 8, so the width of the rectangle is 7. 4

Holt CA Course 1 Solving Equations by Dividing 1-10 Check It Out! Example 6 The area of a rectangle is 48 square inches. Its width is 8 inches. What is its length?

Holt CA Course 1 Solving Equations by Dividing 1-10 Check It Out! Example 6 Continued 1 Understand the Problem The answer will be the length of the rectangle in inches. List the important information: The area of the rectangle is 48 square inches. The width of the rectangle is 8 inches. Draw a diagram to represent this information. 48 l 8

Holt CA Course 1 Solving Equations by Dividing 1-10 Check It Out! Example 6 Continued 2 Make a Plan You can write and solve an equation using the formula for area. To find the area of a rectangle, multiply its length by its width. w l l A = l w l 48 = l 8 lA = lwlA = lw

Holt CA Course 1 Solving Equations by Dividing 1-10 Check It Out! Example 6 Continued l 48 = 8 l Solve 3 88 l 6 = l So the length of the rectangle is 6 inches. l is multiplied by 8. Divide both sides by 8 to undo the multiplication.

Holt CA Course 1 Solving Equations by Dividing 1-10 Check It Out! Example 6 Continued Look Back Arrange 48 identical squares in a rectangle. The width is 8, so line up the squares in columns of 8. You can make 6 columns of 8, so the length of the rectangle is 6. 4

Holt CA Course 1 Solving Equations by Dividing 1-10 Solve each equation. 1. 10y = 300 2. 2y = 82 3. 63 = 9y 4. 78 = 13x Lesson Quiz 5. The area of a board game is 468 square inches. Its width is 18 inches. What is the length? y = 30 y = 41 y = 7 x = 6 26 inches

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