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EGR 1101: Unit 13 Lecture #1 Second-Order Differential Equations in Mechanical Systems (Section 10.5 of Rattan/Klingbeil text)

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Presentation on theme: "EGR 1101: Unit 13 Lecture #1 Second-Order Differential Equations in Mechanical Systems (Section 10.5 of Rattan/Klingbeil text)"— Presentation transcript:

1 EGR 1101: Unit 13 Lecture #1 Second-Order Differential Equations in Mechanical Systems (Section 10.5 of Rattan/Klingbeil text)

2 Review: Procedure  Steps in solving a linear ordinary differential equation with constant coefficients: 1. Find the transient solution. 2. Find the steady-state solution. 3. Find the total solution by adding the results of Steps 1 and 2. 4. Apply initial conditions (if given) to evaluate unknown constants that arose in the previous steps.

3 Forcing Function = 0?  Recall that if the forcing function (the right- hand side of your differential equation) is equal to 0, then the steady-state solution is also 0.  In such cases, you get to skip straight from Step 1 to Step 3!

4 Second-Order Equations

5 Imaginary Numbers?  In solving some second-order linear ordinary differential equations with constant coefficients, you’ll get imaginary numbers as you work through Step #1 (transient solution).  To simplify your solution in such situations, use Euler’s identity:

6 Today’s Examples 1. Free vibration of a spring-mass system 2. Forced vibration of a spring-mass system

7 MATLAB Commands for Example #2 >>fplot('1/(1-0.9^2)*(cos(0.9*t)-cos(t))', [0 200])  To investigate the system’s behavior as the forcing frequency approaches the system’s natural frequency, change the two occurrences of 0.9 in this command to 0.99, and then change to 0.999.

8 Resonance at work  Glass shattered by resonance: http://www.youtube.com/watch?v=17tqXgvCN0E http://www.youtube.com/watch?v=17tqXgvCN0E  Tacoma Narrows Bridge collapse: http://www.youtube.com/watch?v=3mclp9QmCGs http://www.youtube.com/watch?v=3mclp9QmCGs

9 EGR 1101: Unit 13 Lecture #2 Second-Order Differential Equations in Electrical Systems (Section 10.5 of Rattan/Klingbeil text)

10 Low-Pass and High-Pass Filters  A low-pass filter is a circuit that passes low-frequency signals and blocks high- frequency signals.  A high-pass filter is a circuit that does just the opposite: it blocks low-frequency signals and passes high-frequency signals.

11 Today’s Examples 1. Second-order low-pass filter

12 Mechanical-Electrical Analogy  Governing equation of forced spring-mass system from previous lecture: Initial conditions:  Governing equation of our second-order filter: Initial conditions:

13 Mechanical-Electrical Analogy (Continued)  Solution of forced spring-mass system from previous lecture:  Solution of our second-order filter:


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