Presentation is loading. Please wait.

Presentation is loading. Please wait.

Alkenes and Alkynes Chapter #3.

Similar presentations


Presentation on theme: "Alkenes and Alkynes Chapter #3."— Presentation transcript:

1 Alkenes and Alkynes Chapter #3

2 Alkene Introduction Hydrocarbon with carbon-carbon double bonds
Sometimes called olefins, “oil-forming gas” General formula CnH2n n≥2 Examples n=2 C2H4

3 Common Names Usually used for small molecules. Examples:
CH3 CH2=CH2 CH2=CH-CH3 CH2=C-CH3 ethylene propylene isobutylene Vinyl carbons are the carbons sharing a double bond in blue Vinyl hydrogens are the hydrogens bonded to vinyl carbons in red

4 IUPAC Nomenclature Parent is longest chain containing the double or
triple bond. -ane changes to –ene (or -diene, -triene) for double bonds, or –yne (or –diyne, -triyne). Number the chain so that the double bond, or triple bond has the lowest possible number. In a ring, the double bond is assumed to be between carbon 1 and carbon 2.

5 Name These Alkenes

6 Name These Alkenes 1-butene

7 Name These Alkenes 1-butene 2-methyl-2-butene

8 Name These Alkenes 1-butene 2-methyl-2-butene 3-methylcyclopentene

9 Name These Alkenes 1-butene 2-sec-butyl-1,3-cyclohexadiene
2-methyl-2-butene 3-methylcyclopentene

10 Name These Alkenes 1-butene 2-sec-butyl-1,3-cyclohexadiene
2-methyl-2-butene 3-n-propyl-1-heptene 3-methylcyclopentene

11 Alkene Substituents = CH2 methylene - CH = CH2 vinyl - CH2 - CH = CH2
allyl - CH2 - CH = CH2 allyl Name = ?

12 Alkene Substituents = CH2 methylene - CH = CH2 vinyl - CH2 - CH = CH2
allyl - CH2 - CH = CH2 allyl Name = Methylenecyclohexane Name =

13 Alkene Substituents = CH2 methylene - CH = CH2 vinyl - CH2 - CH = CH2
allyl Name = Methylenecyclohexane Name = vinylcyclohexane

14 Alkyne Common Names Acetylene is the common name for the two carbon alkyne. To give common names to alkynes having more than two carbons, give alkyl names to the carbon groups attached to the vinyl carbons followed by acetylene.

15 Alkyne Examples

16 Alkyne Examples Isopropyl methyl acetylene

17 Alkyne Examples Isopropyl methyl acetylene
sec-butyl Cyclopropyl acetylene

18 Cis-trans Isomerism Similar groups on same side of double bond, alkene
is cis. Similar groups on opposite sides of double bond, alkene is trans. Cycloalkenes are assumed to be cis. Trans cycloalkenes are not stable unless the ring has at least 8 carbons.

19 Name these:

20 Name these: trans-2-pentene

21 Name these: trans-2-pentene

22 Name these: trans-2-pentene cis-1,2-dibromoethene

23 Which of the following show cis/trans isomers. a. 1-pentene. b
Which of the following show cis/trans isomers? a. 1-pentene b. 2-pentene c. 1-chloro-1-pentene d. 2-chloro-1-pentene e. 2-chloro-2-pentene

24 Solution to the Question

25 Solution to the Question

26 Which of the following show cis/trans isomers. a. 1-pentene-No. b
Which of the following show cis/trans isomers? a. 1-pentene-No b. 2-pentene- Yes c. 1-chloro-1-pentene- Yes d. 2-chloro-1-pentene- No e. 2-chloro-2-pentene- yes

27 E-Z Nomenclature Use the Cahn-Ingold-Prelog rules to assign priorities
to groups attached to each carbon in the double bond. Highest priority is #1 and is the element with the largest atomic number. If high priority groups are on the same side, the name is Z (for zusammen). If high priority groups are on opposite sides, the name is E (for entgegen).

28 Example, E-Z 1 2 2 1 1 2 1 2 2Z 5E

29 Example, E-Z 1 2 2 1 1 2 1 2 2Z 5E 3,7-dichloro-(2Z, 5E)-2,5-octadiene

30 Physical Properties Low boiling points, increasing with mass.
Branched alkenes have lower boiling points. Less dense than water. Nonpolar (Hydrophobic)

31 Alkene Synthesis Elimination Reactions: Dehydrohalogenation (-HX)
Dehydration of alcohols (-H2O) Examples: Zaitsev’s rule: The major product contains the most substituted double bond

32 Alkene Reactions I. Addition Reactions a. Hydration C=C C-C
O-H H+ C=C C-C Follows Markovnikov’s Rule + H-O-H Alcohol b. Hydrogenation H H Catalyst C=C C-C Catalyst = Ni, Pt, Pd + H-H Alkane c. Halogenation X X C-C C=C + X-X Dihalide X = Cl, Br, I

33 Regiospecificity Markovnikov’s Rule: The proton (H+) of an acid adds to the carbon in the double bond that already has the most H’s. “Rich get richer.” H O-H Examples: H H H+ C-C H H C=C + H-O-H H CH3 H CH3 Major Products H Cl H H C-C C=C + H-Cl H H H CH3 H CH3

34 Alkene Reactions (2) I. Addition Reactions (cont.)
d. Hydrohalogenation H X Follows Markovnikov’s Rule C-C C=C + H-X Alkyl halide e. Glycol Formation H-O O-H C=C C-C + H-O-O-H Glycol

35 Alkene Reactions Step 1: Pi electrons attack the electrophile.
Step 2: Nucleophile attacks the carbocation

36 Terpenes Composed of 5-carbon isopentyl groups.
Isolated from plants’ essential oils. C:H ratio of 5:8, or close to that. Pleasant taste or fragrant aroma. Examples: Myrcene (From bay or myrcia plants) α-Pinene (From pine trees) Β-Selinene (From celery) Menthol (From peppermint oil) Camphor (From evergreen trees) R-Carvone (From spearmint)

37 Classification Terpenes are classified by the number of
carbons they contain, in groups of 10. A monoterpene has 10 C’s, 2 isoprenes. A diterpene has 20 C’s, 4 isoprenes. A sesquiterpene has 15 C’s, 3 isoprenes.

38 Terpenes head tail head head tail head tail tail head Geraniol (roses)
Head to tail link of two isoprenes Called diterpene Menthol (pepermint) Head to tail link of two isoprenes another diterpene

39 Structure of Terpenes Two or more isoprene units, 2-methyl-1,3-butadiene with some modification of the double bonds. myrcene, from bay leaves

40 ALKENE REVIEW

41 Describe the geometry around the carbon–carbon double bond.
a. Tetrahedral b. Trigonal pyramidal c. Trigonal planar d. Bent e. Linear 41

42 Answer a. Tetrahedral b. Trigonal pyramidal c. Trigonal planar d. Bent
e. Linear 42

43 Give the formula for an alkene.
a. CnH2n-4 b. CnH2n-2 c. CnH2n d. CnH2n+2 e. CnH2n+4 43

44 Answer a. CnH2n-4 b. CnH2n-2 c. CnH2n d. CnH2n+2 e. CnH2n+4 44

45 Name CH3CH=CHCH=CH2. a. 2,4-butadiene b. 1,3-butadiene
c. 2,4-pentadiene d. 1,3-pentadiene e. 1,4-pentadiene 45

46 Answer a. 2,4-butadiene b. 1,3-butadiene c. 2,4-pentadiene
d. 1,3-pentadiene e. 1,4-pentadiene 46

47 Calculate the unsaturation number for C6H10BrCl.
d. 3 47

48 Answer a. 0 b. 1 c. 2 d. 3 U = 0.5 [2(6) + 2 – (12)] = 1 48

49 Name . a. Trans-2-pentene b. Cis-2-pentene c. Trans-3-methyl-2-pentene
d. Cis-3-methyl-2-pentene 49

50 Name a. Trans-2-pentene b. Cis-2-pentene c. Trans-3-methyl-2-pentene
d. Cis-3-methyl-2-pentene 50

51 Name a. E-2-pentene b. Z-2-pentene c. E-3-methyl-2-pentene
d. Z-3-methyl-2-pentene e. Z-2-methyl-2-pentene 51

52 Name a. E-2-pentene b. Z-2-pentene c. E-3-methyl-2-pentene
d. Z-3-methyl-2-pentene e. Z-2-methyl-2-pentene 52

53 a. ClCH2CH2Cl b. ClCH=CHCl c. CH2=CH2 d. CH2=CHCl 53

54 Answer a. ClCH2CH2Cl b. ClCH=CHCl c. CH2=CH2 d. CH2=CHCl
Chlorine is added across the double bond, then HCl is lost. 54

55 a. (CH3)2CHOH b. CH3CH2CH2OH c. HOCH2CH2CH2OH d. CH3CH(OH)CH2OH 55

56 Answer a. (CH3)2CHOH b. CH3CH2CH2OH c. HOCH2CH2CH2OH d. CH3CH(OH)CH2OH
Water adds by Markovnikov’s orientation across the double bond. 56

57 Identify the product formed from the polymerization of tetrafluoroethylene.
a. Polypropylene b. Poly(vinyl chloride), (PVC) c. Polyethylene d. Poly(tetrafluoroethylene), Teflon 57

58 Answer a. Polypropylene b. Poly(vinyl chloride), (PVC) c. Polyethylene
d. Poly(tetrafluoroethylene), Teflon Teflon is formed from the polymerization of tetrafluoroethylene. 58

59 a. CH3CCCH3 b. CH2=CHCH=CH2 c. CH3CH=CHCH3 d. CH3CH2CH2CH3 59

60 Answer a. CH3CCCH3 b. CH2=CHCH=CH2 c. CH3CH=CHCH3 d. CH3CH2CH2CH3
Hydrogen adds across the double bond to form an alkane. 60

61 a. (CH3)2CHOSO3H b. CH3CH=CH2 c. (CH3)2C=O d. CH3CH2COOH 61

62 7.15 Answer a. (CH3)2CHOSO3H b. CH3CH=CH2 c. (CH3)2C=O d. CH3CH2COOH
Acid dehydrates alcohols to form alkenes. 62

63 Give the products from the catalytic cracking of alkanes.
a. Alkanes b. Alkenes c. Alkynes d. Alkanes + alkenes e. Alkanes + alkynes 63

64 Answer a. Alkanes b. Alkenes c. Alkynes d. Alkanes + alkenes
e. Alkanes + alkynes 64

65 Give the products from the dehydrogenation of alkanes.
a. Alkanes b. Alkenes c. Alkynes d. Alkanes + alkenes e. Alkanes + alkynes 65

66 Give the products from the dehydrogenation of alkanes.
a. Alkanes b. Alkenes c. Alkynes d. Alkanes + alkenes e. Alkanes + alkynes 66

67 End Chapter #3


Download ppt "Alkenes and Alkynes Chapter #3."

Similar presentations


Ads by Google