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Lecture 6: Dendrites and Axons Cable equation Morphoelectronic transform Multi-compartment models Action potential propagation Refs: Dayan & Abbott, Ch.

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Presentation on theme: "Lecture 6: Dendrites and Axons Cable equation Morphoelectronic transform Multi-compartment models Action potential propagation Refs: Dayan & Abbott, Ch."— Presentation transcript:

1 Lecture 6: Dendrites and Axons Cable equation Morphoelectronic transform Multi-compartment models Action potential propagation Refs: Dayan & Abbott, Ch 6, Gerstner & Kistler, sects 2.5-6; C Koch, Biophysics of Computation, Chs 2,6

2 Longitudinal resistance and resistivity

3 Longitudinal resistance

4 Longitudinal resistance and resistivity Longitudinal resistance Longitudinal resistivity r L ~ 1-3 k  mm 2

5 Longitudinal resistance and resistivity Longitudinal resistance Longitudinal resistivity r L ~ 1-3 k  mm 2

6 Cable equation

7 current balance:

8 Cable equation current balance: on rhs:

9 Cable equation current balance: on rhs:  Cable equation:

10 Linear cable theory Ohmic current:

11 Linear cable theory Ohmic current: Measure V relative to rest:

12 Linear cable theory Ohmic current: Measure V relative to rest: Cable equation becomes

13 Linear cable theory Ohmic current: Measure V relative to rest: Cable equation becomes Now define electrotonic length and membrane time constant:

14 Linear cable theory Ohmic current: Measure V relative to rest: Cable equation becomes Now define electrotonic length and membrane time constant: 

15 Linear cable theory Ohmic current: Measure V relative to rest: Cable equation becomes Now define electrotonic length and membrane time constant:  Note: cable segment of length has longitudinal resistance = transverse resistance:

16 Linear cable theory Ohmic current: Measure V relative to rest: Cable equation becomes Now define electrotonic length and membrane time constant:  Note: cable segment of length has longitudinal resistance = transverse resistance:

17 dimensionless units:

18 Removes,  m from equation.

19 dimensionless units: Removes,  m from equation. Now remove the hats:

20 dimensionless units: Removes,  m from equation. Now remove the hats: ( t really means t/  m, x really means x/ )

21 Stationary solutions No time dependence:

22 Stationary solutions No time dependence: Static cable equation:

23 Stationary solutions No time dependence: Static cable equation: General solution where i e = 0 :

24 Stationary solutions No time dependence: Static cable equation: General solution where i e = 0 :

25 Stationary solutions No time dependence: Static cable equation: General solution where i e = 0 : Point injection:

26 Stationary solutions No time dependence: Static cable equation: General solution where i e = 0 : Point injection: Solution:

27 Stationary solutions No time dependence: Static cable equation: General solution where i e = 0 : Point injection: Solution:

28 Stationary solutions No time dependence: Static cable equation: General solution where i e = 0 : Point injection: Solution: Solution for general i e :

29 Boundary conditions at junctions

30 V continuous

31 Boundary conditions at junctions V continuous Sum of inward currentsmust be zero at junction

32 Boundary conditions at junctions V continuous Sum of inward currentsmust be zero at junction closed end:

33 Boundary conditions at junctions V continuous Sum of inward currentsmust be zero at junction closed end: open end: V = 0

34 Green’s function Response to delta-function current source (in space and time)

35 Green’s function Response to delta-function current source (in space and time)

36 Green’s function Response to delta-function current source (in space and time) Spatial Fourier transform:

37 Green’s function Response to delta-function current source (in space and time) Spatial Fourier transform:

38 Green’s function Response to delta-function current source (in space and time) Spatial Fourier transform Easy to solve:

39 Green’s function Response to delta-function current source (in space and time) Spatial Fourier transform Easy to solve: Invert the Fourier transform:

40 Green’s function Response to delta-function current source (in space and time) Spatial Fourier transform Easy to solve: Invert the Fourier transform:

41 Green’s function Response to delta-function current source (in space and time) Spatial Fourier transform Easy to solve: Invert the Fourier transform: Solution for general i e (x,t) :

42 Pulse injection at x=0,t=0 :

43

44 u vs t at various x : x vs t max :

45 Pulse injection at x=0,t=0 : u vs t at various x : x vs t max : At what t does u peak?

46 Pulse injection at x=0,t=0 : u vs t at various x : x vs t max : At what t does u peak?

47 Pulse injection at x=0,t=0 : u vs t at various x : x vs t max : At what t does u peak? 

48 Pulse injection at x=0,t=0 : u vs t at various x : x vs t max : At what t does u peak? 

49 Pulse injection at x=0,t=0 : u vs t at various x : x vs t max : At what t does u peak?  

50 Pulse injection at x=0,t=0 : u vs t at various x : x vs t max : At what t does u peak?   Restoring ,  m :

51 Compare with no-leak case:

52 Just diffusion, no decay

53 Compare with no-leak case: Just diffusion, no decay Now when does it peak for a given x ?

54 Compare with no-leak case: Just diffusion, no decay Now when does it peak for a given x ?

55 Compare with no-leak case: Just diffusion, no decay Now when does it peak for a given x ? 

56 Compare with no-leak case: Just diffusion, no decay Now when does it peak for a given x ? 

57 Compare with no-leak case: Just diffusion, no decay Now when does it peak for a given x ?  Restoring ,  m :

58 Finite cable Method of images:

59 Finite cable Method of images:

60 Finite cable Method of images: General solution:

61 Finite cable Method of images: General solution:

62 Morphoelectronic transform

63 Frequency-dependent morphoelectronic transforms

64 Multi-compartment models

65 Discrete cable equations

66 Resistance between compartments:

67 Discrete cable equations Resistance between compartments: Current between compartments:

68 Discrete cable equations Resistance between compartments: Current between compartments: Current per unit area:

69 Discrete cable equations Resistance between compartments: Current between compartments: Current per unit area: 

70 Action potential propagation

71

72 a “reaction-diffusion equation”

73 Action potential propagation a “reaction-diffusion equation” Moving solutions: look for solution of the form

74 Action potential propagation a “reaction-diffusion equation” Moving solutions: look for solution of the form  Ordinary DE

75 Action potential propagation a “reaction-diffusion equation” Moving solutions: look for solution of the form  Ordinary DE

76 Action potential propagation a “reaction-diffusion equation” Moving solutions: look for solution of the form  Ordinary DE HH solved iteratively for s (big success of their model)

77 Propagation speed a/s 2 must be independent of a

78 Propagation speed a/s 2 must be independent of a

79 Propagation speed a/s 2 must be independent of a This is probably why the squid axon is so thick.

80 Multi-compartment model

81 Multicompartment calculation

82 Myelinated axons Nodes of Ranvier: active Na channels

83 Myelinated axons Nodes of Ranvier: active Na channels

84 Myelinated axons Treat as multilayer capacitor each layer of thickness  a : Nodes of Ranvier: active Na channels

85 Myelinated axons Treat as multilayer capacitor each layer of thickness  a : Nodes of Ranvier: active Na channels

86 Myelinated axons Treat as multilayer capacitor each layer of thickness  a : Integrate up from a1 to a2 (inverse capacitances add) Nodes of Ranvier: active Na channels

87 Myelinated axons Treat as multilayer capacitor each layer of thickness  a : Integrate up from a1 to a2 (inverse capacitances add) Nodes of Ranvier: active Na channels

88 Myelinated axons Treat as multilayer capacitor each layer of thickness  a : Integrate up from a1 to a2 (inverse capacitances add) Negligible leakage between nodes: cable equation becomes Nodes of Ranvier: active Na channels

89 Myelinated axons Treat as multilayer capacitor each layer of thickness  a : Integrate up from a1 to a2 (inverse capacitances add) Negligible leakage between nodes: cable equation becomes Diffusion constant: Nodes of Ranvier: active Na channels

90 How much myelinization? optimal a 1 /a 2 Find the value of y = a 1 /a 2 that maximizes D

91 How much myelinization? optimal a 1 /a 2 Find the value of y = a 1 /a 2 that maximizes D

92 How much myelinization? optimal a 1 /a 2 Find the value of y = a 1 /a 2 that maximizes D 

93 How much myelinization? optimal a 1 /a 2 Find the value of y = a 1 /a 2 that maximizes D  Agrees with experiment

94 Speed of propagation Diffusion equation with diffusion constant

95 Speed of propagation Diffusion equation with diffusion constant 

96 Speed of propagation Diffusion equation with diffusion constant   Speed of propagation proportional to a 2

97 Speed of propagation Diffusion equation with diffusion constant   Speed of propagation proportional to a 2 (cf a 1/2 for unmyelinated axon)


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