1. If b2 = a, then b is a square root of a.
9.1 Square Roots
SQUARE ROOT OF A NUMBER
If b2 = a, then b is a square root of a.
Examples: 32 = 9, so 3 is a square root of 9.
(-3)2 = 9, so -3 is a square root of 9.

2. Evaluate the expression. - 𝟒
Chapter 9 Test Review
Evaluate the expression.
- 𝟒

3. Evaluate the expression. 𝟏𝟒𝟒
Chapter 9 Test Review
Evaluate the expression.
𝟏𝟒𝟒

4. Evaluate the expression. 𝟏𝟎𝟎
Chapter 9 Test Review
Evaluate the expression.
𝟏𝟎𝟎

5. Evaluate the expression. - 𝟐𝟓
Chapter 9 Test Review
Evaluate the expression.
- 𝟐𝟓

6. 9.2 Solving Quadratic Equations by Finding Square Roots
When b = 0, this equation becomes ax2 + c = 0.
One way to solve a quadratic equation of the form
ax2 + c = 0 is to isolate the x2 on one side of the equation. Then find the square root(s) of each side.

7. Chapter 9 Test Review
Solve the equation.
x2 = 144

8. Chapter 9 Test Review
Solve the equation.
8x2 = 968

9. Chapter 9 Test Review
Solve the equation.
5x2 – 80 = 0

10. Chapter 9 Test Review
Solve the equation.
3x2 – 4 = 8

11. 9.3 Simplifying Radicals PRODUCT PROPERTY OF RADICALS ab = a ∙ b
EXAMPLE: = 4∙5 = ∙ 5 = 2 5

12. Simplify the expression. 𝟒𝟓
Chapter 9 Test Review
Simplify the expression. 𝟒𝟓

13. Simplify the expression. 𝟐𝟖
Chapter 9 Test Review
Simplify the expression. 𝟐𝟖

14. Simplify the expression. 36 24
Chapter 9 Test Review
Simplify the expression.
36 24

15. Simplify the expression. 8 6
Chapter 9 Test Review
Simplify the expression.
8 6

16. 9.5 Solving Quadratic Equations by Graphing
The x-intercepts of graph y = ax2 + bx + c are the solutions of the related equations ax2 + bx + c = 0.
Recall that an x-intercept is the x-coordinate of a point where a graph crosses the x-axis.
At this point, y = 0.

17. Chapter 9 Test Review
Use a graph to estimate the solutions of the equation. Check your solutions algebraically.
x2 – 3x = -2

18. Chapter 9 Test Review
Use a graph to estimate the solutions of the equation. Check your solutions algebraically.
-x2 + 6x = 5

19. Chapter 9 Test Review
Use a graph to estimate the solutions of the equation. Check your solutions algebraically.
x2 – 2x = 3

20. 9.6 Solving Quadratic Equations by the Quadratic Formula
The solutions of the quadratic equation ax2 + bx + c = 0 are:
x = −𝑏 ± 𝑏 2 −4𝑎𝑐 2𝑎
when a ≠ 0 and b2 – 4ac > 0.

21. Use the quadratic formula to solve the equation. 3x2 – 4x + 1 = 0
Chapter 9 Test Review
Use the quadratic formula to solve the equation.
3x2 – 4x + 1 = 0

22. Use the quadratic formula to solve the equation. -2x2 + x + 6 = 0
Chapter 9 Test Review
Use the quadratic formula to solve the equation.
-2x2 + x + 6 = 0

23. Use the quadratic formula to solve the equation. 10x2 – 11x + 3 = 0
Chapter 9 Test Review
Use the quadratic formula to solve the equation.
10x2 – 11x + 3 = 0

24. 9.7 Using the Discriminant
In the quadratic formula, the expression inside the radical is the DISCRIMINANT.
x = −𝑏 ± 𝑏 2 −4𝑎𝑐 2𝑎
DISCRIMINANT
𝐛 𝟐 - 4ac

25. Chapter 9 Test Review
Find the value of the discriminant. Then determine whether the equation has two solutions, one solution, or no real solution.
3x2 – 12x + 12 =0

26. Chapter 9 Test Review
Find the value of the discriminant. Then determine whether the equation has two solutions, one solution, or no real solution.
2x2 + 10x + 6 =0

27. Chapter 9 Test Review
Find the value of the discriminant. Then determine whether the equation has two solutions, one solution, or no real solution.
-x2 + 3x - 5 =0