Presentation is loading. Please wait.

Presentation is loading. Please wait.

Chapter 15: Chemical Equilibria. Manipulating Equilibrium Expressions : N 2 (g) + 3 H 2 (g)  2 NH 3 (g) K = =5.5 x 10 5 Reversing Reactions.

Similar presentations


Presentation on theme: "Chapter 15: Chemical Equilibria. Manipulating Equilibrium Expressions : N 2 (g) + 3 H 2 (g)  2 NH 3 (g) K = =5.5 x 10 5 Reversing Reactions."— Presentation transcript:

1 Chapter 15: Chemical Equilibria

2

3

4

5

6

7 Manipulating Equilibrium Expressions : N 2 (g) + 3 H 2 (g)  2 NH 3 (g) K = =5.5 x 10 5 Reversing Reactions Multiplying by a Factor

8

9

10 Given these initial concentrations, what will the final concentrations be when equilibrium is reached?

11 Given these initial concentrations, what will the final concentrations be when equilibrium is reached?

12 K in terms of pressure: K p vs. K c K p = K c (RT)  n  n = change in numbers of moles of gas 2 NH 3 (g) ==== N 2 (g) + 3 H 2 (g) K c = 5.8 x 10 5 K p = ------------- =

13

14

15

16

17 LeChatelier’s Principle: Doing the math 1-Liter flask contains 0.50 mol butane and 1.25 mol isobutane (at equilibrium). 0.50 mol butane are added. What happens, and what is the result?

18

19


Download ppt "Chapter 15: Chemical Equilibria. Manipulating Equilibrium Expressions : N 2 (g) + 3 H 2 (g)  2 NH 3 (g) K = =5.5 x 10 5 Reversing Reactions."

Similar presentations


Ads by Google