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Copyright©2000 by Houghton Mifflin Company. All rights reserved. 1 Chapter 4 Type of Chemical Reactions and Solution Stoichiometric Water, Nature of aqueous.

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Presentation on theme: "Copyright©2000 by Houghton Mifflin Company. All rights reserved. 1 Chapter 4 Type of Chemical Reactions and Solution Stoichiometric Water, Nature of aqueous."— Presentation transcript:

1 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 1 Chapter 4 Type of Chemical Reactions and Solution Stoichiometric Water, Nature of aqueous solutions, types of electrolytes, dilution. Types of chemical reactions: precipitation, acid-base and oxidation reactions. Stoichiometry of reactions and balancing the chemical equations.

2 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 2 Aqueous Solutions Water is the dissolving medium, or solvent.

3 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 3 Figure 4.1: (Left) The water molecule is polar. (Right) A space-filling model of the water molecule.

4 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 4 Figure 4.2: Polar water molecules interact with the positive and negative ions of a salt assisting in the dissolving process.

5 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 5 Some Properties of Water 4 Water is “bent” or V-shaped. 4 The O-H bonds are covalent. 4 Water is a polar molecule. 4 Hydration occurs when salts dissolve in water.

6 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 6 Figure 4.3: (a) The ethanol molecule contains a polar O—H bond similar to those in the water molecule. (b) The polar water molecule interacts strongly with the polar O—H bond in ethanol. This is a case of "like dissolving like."

7 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 7 A Solute 4 dissolves in water (or other “solvent”) 4 changes phase (if different from the solvent) 4 is present in lesser amount (if the same phase as the solvent)

8 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 8 A Solvent 4 retains its phase (if different from the solute) 4 is present in greater amount (if the same phase as the solute)

9 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 9 General Rule for dissolution  Like dissolve like  Polar dissolve polar (water dissolve ethanol)  Non-polar dissolve nonpolar (benzene dissolve fat)

10 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 10 Figure 4.5: When solid NaCl dissolves, the Na+ and Cl- ions are randomly dispersed in the water.

11 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 11 Electrolytes Strong - conduct current efficiently NaCl, HNO 3 Weak - conduct only a small current vinegar, tap water Non - no current flows pure water, sugar solution

12 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 12 Figure 4.4: Electrical conductivity of aqueous solutions.

13 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 13 Acids Strong acids -dissociate completely to produce H + in solution hydrochloric and sulfuric acid HCl, H 2 SO 4 Weak acids - dissociate to a slight extent to give H + in solution acetic and formic acid CH 3 COOH, CH 2 O

14 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 14 Bases Strong bases - react completely with water to give OH  ions. sodium hydroxide Weak bases - react only slightly with water to give OH  ions. ammonia

15 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 15 Figure 4.6: HCl(aq) is completely ionized.

16 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 16 Figure 4.7: An aqueous solution of sodium hydroxide.

17 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 17 Figure 4.8: Acetic acid (HC 2 H 3 O 2 ) exists in water mostly as undissociated molecules. Only a small percentage of the molecules are ionized.

18 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 18 Molarity Molarity (M) = moles of solute per volume of solution in liters:

19 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 19 Common Terms of Solution Concentration Stock - routinely used solutions prepared in concentrated form. Concentrated - relatively large ratio of solute to solvent. (5.0 M NaCl) Dilute - relatively small ratio of solute to solvent. (0.01 M NaCl): (MV) initial =(MV) Final

20 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 20 Figure 4.10: Steps involved in the preparation of a standard aqueous solution.

21 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 21 Figure 4.12: Dilution Procedure (a) A measuring pipet is used to transfer 28.7mL of 17.4 M acetic acid solution to a volumetric flask. (b) Water is added to the flask to the calibration mark. (c) The resulting solution is 1.00 M acetic acid.

22 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 22 Types of Solution Reactions 4 Precipitation reactions AgNO 3 (aq) + NaCl(aq)  AgCl(s) + NaNO 3 (aq) 4 Acid-base reactions NaOH(aq) + HCl(aq)  NaCl(aq) + H 2 O(l) 4 Oxidation-reduction reactions Fe 2 O 3 (s) + Al(s)  Fe(l) + Al 2 O 3 (s)

23 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 23 Simple Rules for Solubility 1.Most nitrate (NO 3  ) salts are soluble. 2.Most alkali (group 1A) salts and NH 4 + are soluble. 3.Most Cl , Br , and I  salts are soluble (NOT Ag +, Pb 2+, Hg 2 2+ ) 4.Most sulfate salts are soluble (NOT BaSO 4, PbSO 4, HgSO 4, CaSO 4 ) 5.Most OH  salts are only slightly soluble (NaOH, KOH are soluble, Ba(OH) 2, Ca(OH) 2 are marginally soluble) 6.Most S 2 , CO 3 2 , CrO 4 2 , PO 4 3  salts are only slightly soluble.

24 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 24 Figure 4.13: When yellow aqueous potassium chromate is added to a colorless barium nitrate solution, yellow barium chromate precipitates.

25 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 25 Describing Reactions in Solution Precipitation 1.Molecular equation (reactants and products as compounds) AgNO 3 (aq) + NaCl(aq)  AgCl(s) + NaNO 3 (aq) 2.Complete ionic equation (all strong electrolytes shown as ions) Ag + (aq) + Cl  (aq)  AgCl(s)

26 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 26 Describing Reactions in Solution (continued) 3.Net ionic equation (show only components that actually react) Ag + (aq) + Cl  (aq)  AgCl(s) Na + and NO 3  are spectator ions.

27 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 27 Performing Calculations for Acid-Base Reactions 1.List initial species and predict reaction. 2.Write balanced net ionic reaction. 3.Calculate moles of reactants. 4.Determine limiting reactant. 5.Calculate moles of required reactant/product. 6.Convert to grams or volume, as required. Remember: n H+ = n OH- (MV) H+ = (MV) OH-

28 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 28 Neutralization Reaction acid + base salt + water HCl (aq) + NaOH (aq) NaCl (aq) + H 2 OH + + Cl - + Na + + OH - Na + + Cl - + H 2 O H + + OH - H 2 O 4.3

29 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 29 Key Titration Terms Titrant - solution of known concentration used in titration Analyte - substance being analyzed Equivalence point - enough titrant added to react exactly with the analyte Endpoint - the indicator changes color so you can tell the equivalence point has been reached. movie

30 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 30 Practice Example How many moles are in 18.2 g of CO 2 ?

31 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 31 Practice Example Consider the reaction N 2 + 3H 2 = 2NH 3 How many moles of H 2 are needed to completely react 56 g of N 2 ?

32 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 32 Practice Example How many grams are in 0.0150 mole of caffeine C 8 H 10 N 4 O 2

33 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 33 Practice Example A solution containing Ni 2+ is prepared by dissolving 1.485 g of pure nickel in nitric acid and diluting to 1.00 L. A 10.00 mL aliquot is then diluted to 500.0 mL. What is the molarity of the final solution? (Atomic weight: Ni = 58.70).

34 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 34 Practice Example Calculate the number of molecules of vitamin A, C 20 H 30 O in 1.5 mg of this compound.

35 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 35 Practice Example What is the mass percent of hydrogen in acetic acid HC 2 H 3 O 2

36 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 36 Oxidation-Reduction Reactions (electron transfer reactions) 2Mg (s) + O 2 (g) 2MgO (s) 2Mg 2Mg 2+ + 4e - O 2 + 4e - 2O 2- Oxidation half-reaction (lose e - ) Reduction half-reaction (gain e - ) 2Mg + O 2 + 4e - 2Mg 2+ + 2O 2- + 4e - 2Mg + O 2 2MgO

37 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 37

38 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 38 Redox Reactions Many practical or everyday examples of redox reactions: –Corrosion of iron (rust formation) –Forest fire –Charcoal grill –Natural gas burning –Batteries –Production of Al metal from Al2O3 (alumina) –Metabolic processes combustion

39 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 39 Rules for Assigning Oxidation States 1. Oxidation state of an atom in an element = 0 2. Oxidation state of monatomic element = charge 3. Oxygen =  2 in covalent compounds (except in peroxides where it =  1) 4. H = +1 in covalent compounds 5. Fluorine =  1 in compounds 6. Sum of oxidation states = 0 in compounds Sum of oxidation states = charge of the ion

40 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 40

41 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 41 Zn (s) + CuSO 4 (aq) ZnSO 4 (aq) + Cu (s) Zn is oxidizedZn Zn 2+ + 2e - Cu 2+ is reducedCu 2+ + 2e - Cu Zn is the reducing agent Cu 2+ is the oxidizing agent 4.4 Copper wire reacts with silver nitrate to form silver metal. What is the oxidizing agent in the reaction? Cu (s) + 2AgNO 3 (aq) Cu(NO 3 ) 2 (aq) + 2Ag (s) Cu Cu 2+ + 2e - Ag + + 1e - AgAg + is reducedAg + is the oxidizing agent

42 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 42 NaIO 3 Na = +1 O = -2 3x(-2) + 1 + ? = 0 I = +5 IF 7 F = -1 7x(-1) + ? = 0 I = +7 K 2 Cr 2 O 7 O = -2K = +1 7x(-2) + 2x(+1) + 2x(?) = 0 Cr = +6 Oxidation numbers of all the elements in the following ? 4.4

43 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 43 Balancing by Half-Reaction Method 1.Write separate reduction, oxidation reactions. 2.For each half-reaction:  Balance elements (except H, O)  Balance O using H 2 O  Balance H using H +  Balance charge using electrons

44 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 44 Balancing by Half-Reaction Method (continued) 3.If necessary, multiply by integer to equalize electron count. 4.Add half-reactions. 5.Check that elements and charges are balanced.

45 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 45 Half-Reaction Method - Balancing in Base 1.Balance as in acid. 2.Add OH  that equals H + ions (both sides!) 3.Form water by combining H +, OH . 4.Check elements and charges for balance.

46 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 46 Balancing Redox Equations Example: Balance the following redox reaction: Cr 2 O 7 2- + Fe 2+ Cr 3+ + Fe 3+ (acidic soln) 1) Break into half reactions: Cr 2 O 7 2- Cr 3+ Fe 2+ Fe 3+

47 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 47 Balancing Redox Equations 2) Balance each half reaction: Cr 2 O 7 2- Cr 3+ Cr 2 O 7 2- 2 Cr 3+ Cr 2 O 7 2- 2 Cr 3+ + 7 H 2 O Cr 2 O 7 2- + 14 H + 2 Cr 3+ + 7 H 2 O 6 e - + Cr 2 O 7 2- + 14 H + 2 Cr 3+ + 7 H 2 O

48 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 48 Balancing Redox Equations 2) Balance each half reaction (cont) Fe 2+ Fe 3+ Fe 2+ Fe 3+ + 1 e -

49 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 49 Balancing Redox Reactions 3) Multiply by integer so e - lost = e - gained 6 e - + Cr 2 O 7 2- + 14 H + 2 Cr 3+ + 7 H 2 O Fe 2+ Fe 3+ + 1 e - x 6

50 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 50 Balancing Redox Reactions 3) Multiply by integer so e - lost = e - gained 6 Fe 2+ 6 Fe 3+ + 6 e - 6 e - + Cr 2 O 7 2- + 14 H + 2 Cr 3+ + 7 H 2 O 4) Add both half reactions Cr 2 O 7 2- + 6 Fe 2+ + 14 H + 2 Cr 3+ + 6 Fe 3+ + 7 H 2 O

51 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 51 Balancing Redox Reactions Cr 2 O 7 2- + 6 Fe 2+ + 14 H + 2 Cr 3+ + 6 Fe 3+ + 7 H 2 O 5) Check the equation 2 Cr7 O6 Fe14 H +24 + 24

52 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 52 Balancing Redox Reactions Procedure for Basic Solutions: –Divide the equation into 2 incomplete half reactions one for oxidation one for reduction

53 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 53 Balancing Redox Reactions –Balance each half-reaction: balance elements except H and O balance O atoms by adding H 2 O balance H atoms by adding H + add 1 OH - to both sides for every H + added combine H + and OH - on same side to make H 2 O cancel the same # of H 2 O from each side balance charge by adding e - to side with greater overall + charge different

54 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 54 Balancing Redox Equations –Multiply each half reaction by an integer so that # e - lost = # e - gained –Add the half reactions together. Simply where possible by canceling species appearing on both sides of equation –Check the equation # of atoms total charge on each side

55 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 55 Balancing Redox Reactions Example: Balance the following redox reaction. NH 3 + ClO - Cl 2 + N 2 H 4 (basic soln) NH 3 N 2 H 4 ClO - Cl 2 1) Break into half reactions:

56 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 56 Balancing Redox Reactions NH 3 N 2 H 4 2) Balance each half reaction: 2 NH 3 N 2 H 4 2 NH 3 N 2 H 4 + 2 H + 2 NH 3 + 2 OH - N 2 H 4 + 2 H 2 O + 2 OH - + 2 OH - 2H2O2H2O 2 NH 3 + 2 OH - N 2 H 4 + 2 H 2 O + 2 e -

57 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 57 Balancing Redox Reactions 2 ClO - Cl 2 2) Balance each half reaction: 2 ClO - Cl 2 + 2 H 2 O 2 ClO - + 4 H + Cl 2 + 2 H 2 O + 4 OH - + 4 OH - 2 ClO - + 4 H 2 O Cl 2 + 2 H 2 O + 4 OH - 2 ClO - + 2 H 2 O Cl 2 + 4 OH - 2 e - + 2 ClO - + 2 H 2 O Cl 2 + 4 OH - ClO - Cl 2

58 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 58 Balancing Redox Reactions 3) Multiply by integer so # e - lost = # e - gained 2 NH 3 + 2 OH - N 2 H 4 + 2 H 2 O + 2 e - 2 e - + 2 ClO - + 2 H 2 O Cl 2 + 4 OH - 4) Add both half reactions 2 NH 3 + 2 OH - + 2ClO - + 2 H 2 O N 2 H 4 + 2 H 2 O + Cl 2 + 4 OH -

59 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 59 Balancing Redox Reactions 5) Cancel out common species 2 NH 3 + 2 OH - + 2 ClO - + 2 H 2 O N 2 H 4 + 2 H 2 O + Cl 2 + 4 OH - 2 2 NH 3 + 2 ClO - N 2 H 4 + Cl 2 + 2 OH - 6) Check final equation: 2 N6 H2 Cl2 O-2

60 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 60

61 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 61

62 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 62 Practice Example In the following the oxidizing agent is: 5H 2 O 2 + 2MnO 4 - + 6H +  2Mn 2+ + 8H 2 O + 5O 2 a. MnO 4 - b. H 2 O 2 c. H + d. Mn 2+ e. O 2

63 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 63 Practice Example Determine the coefficient of Sn in acidic solution Sn + HNO 3  SnO 2 + NO 2 + H 2 O 1

64 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 64 Practice Example The sum of the coefficients when they are whole numbers in basic solution: Bi(OH) 3 + SnO 2 2-  Bi + SnO 3 2- 13

65 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 65 http://www.chemistrycoach.com/balancing_redox_in_acid.htm#Bal ancingRedoxEquationsinAcidicorBasicMedium

66 Copyright©2000 by Houghton Mifflin Company. All rights reserved. 66 http://www.chemistrycoach.com/tutorials-5.htm#Oxidation-Reduction


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