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Can Bottom Snap-through

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Presentation on theme: "Can Bottom Snap-through"— Presentation transcript:

1 Can Bottom Snap-through
MSC.Patran 2005 r2 MSC.Marc 2005 r2 Estimated Time for Completion: ~35min Experience Level: Lower

2 Topics Covered Topics covered in Modeling Topic covered in Analysis
Importing Geometry file with FEA data. Neutral format (.out) Creating Material Properties using Fields option. Specify the input data that represent the stress-strain relationship. Verifying Element Normal Shell element layers are dependent on the element direction Topic covered in Analysis Applying Large Displacement/Large Strains Analysis. Applying Modified Rik’s/Ramm Method Topics covered in Review Creating XY plots Load vs. Displacement plot Strain Energy vs. Time plot Animations Increment based animation Time based animation

3 Problem Description This example demonstrates the nonlinear analysis of the bottom of a 3D aluminum container under given internal pressure. The configuration of the bottom and the critical pressure leads to a snap-through problem. Pressure

4 Simplifying the problem
Problem Description Given Parameters Aluminum can Dimensions Thickness of the shell=0.025 in Diameter of the can= 2.61 in Material properties Young’s Modulus=11E6 psi Poisson’s ratio=0.3 Simplifying the problem To apply the axisymmetric condition, the rotation at the center of the bottom is fixed

5 Goal Find the critical pressure leading the snap-through phenomenon.
Find the location and value of the maximum stress during the loading and unloading processes. Plot the Load vs. Displacement, and Strain Energy vs. time.

6 Expected Results Deformation Increasing Pressure Time 0.01.0
Decreasing Pressure Time 1.02.0 Snap-through

7 Create Database file and Import Geometry
Create a New Database file called ‘can_snapthrough.db’ Use Marc as the analysis Code Import the Neutral Geometry file called ‘canbottom.out’, and Node and element information will be imported. Imported elements and nodes

8 Elements Verify the Shell Element Normal
This is required to know the layer information. The top layer of the element is numbered as Layer 1. Layer 5 Layer 1

9 Boudary Condtions Displacement Constraints Pressure Fixed_x Fixed_sym
This will fixed the displacements of the cut surface, however in-plane motion of the surface should be allowed. Fixed_sym This will symplify the problem. Unexpected buckling shape will be eliminated. Pressure Pressure_in Loading condition Pressure_zero Unloading condition Fixed_sym Pressure_in Pressure_zero

10 Fields Stress-strain curve
Plastic material property is defined as a table.

11 Materials Elastic model Plastic model Aluminum
Elastic Modulus: 11e6 psi Possion’s ratio: 0.3 Plastic model Use the stress-strain curve defined in the previous slide.

12 Properties Element Properties 2D Thin Shell Material: Aluminum
Thickness 0.025in

13 Load Cases Loading Name: LoadPressure Apply following three BCs/Load
Fixed_sym Fixed_x Pressure_in Unloading Name: UnloadingPressure Pressure_zero LoadPressure UnloadPressure

14 Analysis Two Load Steps Solving Options Loading Name: PressureStep
Load Case selected: LoadPressure Unloading Name: UnloadingStep Load Case selected: UnloadPressure Solving Options Large Displacement/Large Strain Loads Follow Deformations Adaptive Arc Length method Use Modifed Riks/Ramm method Use default options for all others Required nodal results Displacement, Rotation, Reaction Force, and External Force

15 Review Results Select the reference information
Reference nodes to review the displacement and stress results Reference increment to compare the results based on time (load factor) and increment (solving step) Reference increments for Loading and unloading results: Select the increment results with the time increasing. Reference node for the displacement axis Reference nodes for the von-Mises stress

16 Load applied vs. displacement Curve
Results Load applied vs. displacement Curve Snap-through information can be found by plotting the results with the increasing time. The critical load leads the snap-through is about 370 psi at time=0.74 (=500psi x 0.74) loading unloading Snap-through At time=0.74 Based on the increasing time(load) Based on the increment(solving step)

17 Plastic Strain Energy vs. Time
Results Plastic Strain Energy vs. Time Plastic Strain Energy is dramatically increased at the critical load (or time) It does not changed during the unloading step. So there is only elastic deformation in the step. Snap-through loading unloading Based on the increasing time(load) Based on the increment(solving step)

18 Results Elastic Strain Energy vs. Time Elastic Deformation
Snap-through loading unloading Based on the increasing time(load) Based on the increment(solving step)

19 von Mises Stress vs. Time
Results von Mises Stress vs. Time Use the reference nodes for the von Mises Stress. Maximum von Mises occurs after the loading step and it is about 0.1 MPa Locate the maximum stress by plotting on the geometry (Next slide) Snap-through Maximum stress Plastic Deformation loading unloading

20 Results (Stress: von Mises)
Stress at layer 1 (inside) Stress at layer 5 (Outside) Max=0.101 psi Max=0.104 psi

21 Animation (based on the increments)

22 Animation (based on the Time: Actual motion)

23 Further Analysis (Optional)
Remove the axisymmetric condition (fixed rotation) from the node at the cetner. Find the difference from the current analysis. For further simplification, use line elements and the axisymmetric condition and compare the results to the one with shell elements.


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