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Chemical Equilibrium Labs p208.

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Presentation on theme: "Chemical Equilibrium Labs p208."— Presentation transcript:

1 Chemical Equilibrium Labs p208

2 Thymol Blue Equilibrium
Thymol Blue (Yellow Form)   Thymol Blue + H+ (Blue)

3 Thymol Blue Equilibrium Stresses and Results
Thymol Blue (Yellow Form)   Thymol Blue + H+ (Blue) Stress: Add HCl (H+). Result: Green Colour Stress: Add more HCl. Results: Yellow Colour Stress: Add NaOH (OH-) reacts with H+ to form H2O) Result: Green Colour Stress: Add more NaOH. Results: Blue Colour

4 Equilibrium Involving Thiocyanatoiron III Ion
Fe(H2O)63+ (Amber) + SCN1-   Fe(SCN)(H2O)52+ (D. Red)

5 Equilibrium Involving Thiocyanatoiron III Ion
Fe(H2O)63+ (Amber) + SCN1-   Fe(SCN)(H2O)52+ (D. Red) Add KCl (Fe3+ forms an insoluble ppt [FeCl3] with Cl1-) Result: Amber Colour Add Fe(NO3)3 Possible Stresses: Fe+3 and NO3 – Result: Darker Red Add KSCN Possible Stresses: K+ and SCN- Add NaOH (Fe3+ forms ins. ppt [Fe(OH)3] with OH1-) Result: First Orange and then Amber Colour

6 Equilibrium Involving Cobalt II Complexes
Co(H2O)62+ (aq) + 2 Cl1- (aq)   Co(H2O)4Cl2 (aq) + H2O (ℓ) a) Add HCl. Result: Purple Colour b) Add H2O. Result: Pink Colour c) Add Heat Result: Purple Colour d) Remove Heat (Cool) Result: Pink Colour

7 Equilibrium Involving Chromate and Dichromate Ions
Cr2O72- (aq) OH1- (aq)   2 CrO42- (aq) H2O (ℓ) (Orange) (Yellow)

8 Equilibrium Involving Chromate and Dichromate Ions
Cr2O72- (aq) OH1- (aq)   2 CrO42- (aq) H2O (ℓ) (Orange) (Yellow) Add NaOH. Result: Orange turns Yellow (yellow stays yellow) Add HCl Result: Yellow turns Orange (orange stays orange) Add K2CrO4 Result: Colour in both is Orange Add K2Cr2O7 Result: Colour in both is Yellow Add Ba(NO3)2 (BaCrO4 is insoluble while BaCr2O7 is soluble) Result: Chr. sol.  Yellow, Dichr. Sol.  Orange Ba(NO3)2 in beaker K2CrO4 in graduate

9 Equilibrium With Copper II Complexes
Cu(H2O)42+ (aq) NH OH-   Cu(NH3)42+ (aq) + 4 H2O (Light Blue) (Deep Blue)

10 Equilibrium With Copper II Complexes
Cu(H2O)42+ (aq) NH OH-   Cu(NH3)42+ (aq) + 4 H2O (Light Blue) (Deep Blue) Add NH3 (aq) (NH3 (aq) is NH OH-) Result: The light blue colour turns a deeper blue Add more NH+. Result: The colour  Yet Deeper Blue Add HCl (Yields H+ and Cl-). The deep Blue  Light Blue

11 End of Lab Results

12 A A


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