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Perpendicular and Angle Bisectors

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1 Perpendicular and Angle Bisectors
Geometry Perpendicular and Angle Bisectors CONFIDENTIAL

2 Write the equation of each line in slope-intercept from.
Warm up Write the equation of each line in slope-intercept from. 1) The line through the points (1,-1) and (2, -9) 2) The line with slope -0.5 through (10, -15) 3) The line with x-intercept -4 and y-intercept 5 CONFIDENTIAL

3 Perpendicular and Angle Bisectors
When a point is the same distance from two or more objects, the point is said to be equidistant from the objects. Triangle congruence theorems can be used to prove theorems about equidistant points. CONFIDENTIAL

4 HYPOTHESIS CONCLUSION
Theorems Distance and Perpendicular Bisectors THEOREM HYPOTHESIS CONCLUSION L X 1.1) Perpendicular Bisector Theorem If a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoint of the segment. A Y B Next page -> CONFIDENTIAL

5 HYPOTHESIS CONCLUSION
THEOREM HYPOTHESIS CONCLUSION L 1.2) Converse of the Perpendicular Bisector Theorem If a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment. X A Y B CONFIDENTIAL

6 Perpendicular Bisector Theorem
X A Y B CONFIDENTIAL

7 A locus is a set of point that satisfies a given condition
A locus is a set of point that satisfies a given condition. The perpendicular bisector of a segment can be defined as the locus of points in a plane that are equidistant from the endpoints of the segment. CONFIDENTIAL

8 Applying the Perpendicular Bisector Theorem and Its Converse
Find each measure. L A) YW W 7.3 YW = XW YW = 7.3 X Z Y Next page -> CONFIDENTIAL

9 B) BC B 36 D L A 16 36 Next page -> C CONFIDENTIAL

10 C) PR PR = RQ 2n + 9 = 7n – 18 9 = 5n – 18 27 = 5n 5.4 = n
So PR = 2(5.4) + 9 = 19.8 L S Q P 2n + 9 7n - 18 R CONFIDENTIAL

11 Now you try! 1) Find each measure. L G
Given that line l is the perpendicular bisector of DE and EG = 14.6, find DG. b) Given that DE = 20.8, DG = 36.4, and EG = 36.4, find EF. D F E CONFIDENTIAL

12 Remember that the distance between a point and a line is the length of the perpendicular segment from the point to the line. CONFIDENTIAL

13 HYPOTHESIS CONCLUSION
Theorems Distance and Angle Bisectors THEOREM HYPOTHESIS CONCLUSION 1.3) Angle Bisector Theorem If a point is on the bisector of an angle, then it is equidistant from the sides of the angle. A C AC = BC P B /APC ≅ /BPC Next page -> CONFIDENTIAL

14 HYPOTHESIS CONCLUSION
THEOREM HYPOTHESIS CONCLUSION 1.4) Converse of the Angle Bisector Theorem If a point in the interior of an angle is equidistant from the sides of the angle, then it is on the bisector of the angle. A C /APC ≅ /BPC P B AC = BC CONFIDENTIAL

15 Based on those theorems, an angle bisector can be defined as the locus of all points in the interior of the angle that are equidistant from the sides of the angle. CONFIDENTIAL

16 Applying the Angle Bisector Theorems
Find each measure. J A) LM 12.8 M K LM = JM / Bisector Thm. LM = Substitute 12.8 for JM. L Next page -> CONFIDENTIAL

17 B) m/ABD, given that m/ABC = 112˚
74 A 74 B C Def. of / bisector Substitute 112˚ for m/ABC. Next page -> CONFIDENTIAL

18 U C) m/TSU R (6z + 14˚) S T (5z + 23˚) CONFIDENTIAL

19 Now you try! 2) Find each measure. W Z Y X CONFIDENTIAL

20 Parachute Application
Each pair of suspension lines on a parachute are the same length and are equally spaced from the center of the chute. How do these lines keep the sky diver centered under the parachute? P S R Q CONFIDENTIAL

21 S is equidistant from each pair of suspension
Now you try! S is equidistant from each pair of suspension lines. What can you conclude about P S R Q CONFIDENTIAL

22 Writing Equations of Bisectors in Coordinate Plane
Write an equation in point – slope form for the perpendicular bisector of the segment with endpoints A(-1,6) and B(3,4). y A (1,5) B 4 x 2 4 Next page -> CONFIDENTIAL

23 y A (1,5) B 4 x 2 4 Next page -> CONFIDENTIAL

24 y A (1,5) B 4 x 2 4 Next page -> CONFIDENTIAL

25 y A (1,5) B 4 x 2 4 CONFIDENTIAL

26 Now you try! 4) Write an equation in point-slope from for the
perpendicular bisector of the segment with endpoints P(5,2) and Q(1,-4). CONFIDENTIAL

27 Now some problems for you to practice !
CONFIDENTIAL

28 Use the diagram for Exercise.
Assessment Use the diagram for Exercise. m S Q P T 1) 2) CONFIDENTIAL

29 Use the diagram for Exercise.
3) A D C B 4) CONFIDENTIAL

30 5) For a king post truss to be constructed
correctly, P must lie on the bisector of /JLK. How can braces PK and PM be used to ensure that P is in the proper location? L M K J N P CONFIDENTIAL

31 Write an equation in point-slope from for the
perpendicular bisector of the segment with the given endpoints. 6) M(-5,4), N(1,-2) ) U(2,-6), V(4,0) CONFIDENTIAL

32 Perpendicular and Angle Bisectors
Let’s review Perpendicular and Angle Bisectors When a point is the same distance from two or more objects, the point is said to be equidistant from the objects. Triangle congruence theorems can be used to prove theorems about equidistant points. CONFIDENTIAL

33 HYPOTHESIS CONCLUSION
Theorems Distance and Perpendicular Bisectors THEOREM HYPOTHESIS CONCLUSION L X 1.1) Perpendicular Bisector Theorem If a point is on the perpendicular bisector of a segment, then it is equidistant from the endpoint of the segment. A Y B Next page -> CONFIDENTIAL

34 HYPOTHESIS CONCLUSION
THEOREM HYPOTHESIS CONCLUSION L 1.2) Converse of the Perpendicular Bisector Theorem If a point is equidistant from the endpoints of a segment, then it is on the perpendicular bisector of the segment. X A Y B CONFIDENTIAL

35 Perpendicular Bisector Theorem
X A Y B CONFIDENTIAL

36 A locus is a set of point that satisfies a given condition
A locus is a set of point that satisfies a given condition. The perpendicular bisector of a segment can be defined as the locus of points in a plane that are equidistant from the endpoints of the segment. CONFIDENTIAL

37 Applying the Perpendicular Bisector Theorem and Its Converse
Find each measure. L A) YW W 7.3 YW = XW YW = 7.3 X Z Y Next page -> CONFIDENTIAL

38 B) BC B 36 D L A 16 36 Next page -> C CONFIDENTIAL

39 C) PR PR = RQ 2n + 9 = 7n – 18 9 = 5n – 18 27 = 5n 5.4 = n
So PR = 2(5.4) + 9 = 19.8 L S Q P 2n + 9 7n - 18 R CONFIDENTIAL

40 Remember that the distance between a point and a line is the length of the perpendicular segment from the point to the line. CONFIDENTIAL

41 HYPOTHESIS CONCLUSION
Theorems Distance and Angle Bisectors THEOREM HYPOTHESIS CONCLUSION 1.3) Angle Bisector Theorem If a point is on the bisector of an angle, then it is equidistant from the sides of the angle. A C AC = BC P B /APC ≅ /BPC Next page -> CONFIDENTIAL

42 HYPOTHESIS CONCLUSION
THEOREM HYPOTHESIS CONCLUSION 1.4) Converse of the Angle Bisector Theorem If a point in the interior of an angle is equidistant from the sides of the angle, then it is on the bisector of the angle. A C /APC ≅ /BPC P B AC = BC CONFIDENTIAL

43 Based on those theorems, an angle bisector can be defined as the locus of all points in the interior of the angle that are equidistant from the sides of the angle. CONFIDENTIAL

44 Applying the Angle Bisector Theorems
Find each measure. J A) LM 12.8 M K LM = JM / Bisector Thm. LM = Substitute 12.8 for JM. L Next page -> CONFIDENTIAL

45 B) m/ABD, given that m/ABC = 112˚
74 A 74 B C Def. of / bisector Substitute 112˚ for m/ABC. Next page -> CONFIDENTIAL

46 U C) m/TSU R (6z + 14˚) S T (5z + 23˚) CONFIDENTIAL

47 Parachute Application
Each pair of suspension lines on a parachute are the same length and are equally spaced from the center of the chute. How do these lines keep the sky diver centered under the parachute? P R S Q CONFIDENTIAL

48 Writing Equations of Bisectors in Coordinate Plane
Write an equation in point – slope form for the perpendicular bisector of the segment with endpoints A(-1,6) and B(3,4). y A (1,5) B 4 x 2 4 Next page -> CONFIDENTIAL

49 y A (1,5) B 4 x 2 4 Next page -> CONFIDENTIAL

50 y A (1,5) B 4 x 2 4 Next page -> CONFIDENTIAL

51 y A (1,5) B 4 x 2 4 CONFIDENTIAL

52 You did a great job today!
CONFIDENTIAL


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