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Example 10.5 1ECE 201 Circuit Theory 1. A load having an impedance of 39 + j26 Ω is fed from a voltage source through a line having an impedance of 1.

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Presentation on theme: "Example 10.5 1ECE 201 Circuit Theory 1. A load having an impedance of 39 + j26 Ω is fed from a voltage source through a line having an impedance of 1."— Presentation transcript:

1 Example 10.5 1ECE 201 Circuit Theory 1

2 A load having an impedance of 39 + j26 Ω is fed from a voltage source through a line having an impedance of 1 + j4 Ω. The effective, or rms, value of the source voltage is 250 V. Calculate the load current I L and the voltage V L. 2ECE 201 Circuit Theory 1

3 Calculate the load current I L and the voltage V L. The line and load impedances are in series across the voltage source, so the load current equals the voltage divided by the total impedance. The load voltage equals the load current multiplied by the load impedance. 3ECE 201 Circuit Theory 1

4 Calculate the active and reactive power delivered to the load. Average Power = 975 WReactive Power = 650 VARS 4ECE 201 Circuit Theory 1

5 Calculate the average and reactive power delivered to the line. Reactive Power is positive due to an inductive line reactance 5ECE 201 Circuit Theory 1

6 Calculate the average and reactive power supplied by the source Add complex powers delivered to the line and load 6ECE 201 Circuit Theory 1

7 Calculate the apparent power The – sign is used whenever the current reference is in the direction of a voltage rise 7ECE 201 Circuit Theory 1


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