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Pharmacokinetics Questions

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Presentation on theme: "Pharmacokinetics Questions"— Presentation transcript:

1 Pharmacokinetics Questions
1. A drug achieves a plasma concentration of 16 mg/L immediately after the administration of the first dose. If the half life and the dosing interval are both 6 hrs, what is the approximate plasma level shortly before the administration of the 5th dose? 15 mg/L 24 mg /L 28 mg /L 30 mg /L 31 mg/L

2 Pharmacokinetics Questions 1) Answer
After first dose ---- plasma conc is 16mg/L, it will reduce to half of it in 6 hrs --- 8mg/L After second dose --- plasma conc is 8+16 = 24 mg/L, it will reduce to half in 6 hrs –12 mg/L, After 3rd dose --- plasma conc is = 28mg/L, it will reduce to half in 6 hrs -14mg/L After 4th dose – plasma conc is = 30mg/L, it will reduce to half in 6hrs – 15 mg/L Therefore before administration of fifth dose, plasma conc is around 15 mg/L

3 Pharmacokinetics Questions 1) Answer
The drug concentration before the administration of 5th dose is same as the concentration after 4 half lives. The drug reaches 94% of the steady state after 4 half lives. The drug achieves 50% of the steady state after 1 half life ~ is 8 mg/L. The drug concentration after 4 half lives – 94% = = 94 * 8 / = mg/L

4 Pharmacokinetics Questions
2. A patient was given a 160 mg dose of the drug IV, and 80 mg was eliminated during the first 120 minutes. If the drug follows the first order kinetics, how much of the drug will remain 6 hrs after its administration? 5 mg 10 mg 20 mg 40 mg 60 mg

5 Pharmacokinetics Questions 2) Answer
After 2 hrs = 120 mins, drug has reduce to half from 160 mg to 80mg, After 4 hrs, the drug will reduce from 80 to 40mg. Finally after 6 hrs, the drug will reduce from 40 to 20 mg.

6 Pharmacokinetics Questions
3. An IV infusion of a drug is started at 400mg/hour. If the clearance = 50L / hour. What is the anticipated plasma level at steady state? 2 mg/L 4 mg/L 8 mg/L 16 mg/L 32 mg/L

7 Pharmacokinetics Questions 3) Answer
Infusion rate = CL X Css Css = Infusion rate / CL Css = 400 mg/hour / 50L/hr = 8 mg/L

8 Pharmacokinetics Questions
4. Piroxicam with a half life of 40 hr being dosed once daily (every 24 hrs), steady state will be reached shortly following which dose (not half life)? 1st dose 2nd dose 5th dose 8th dose 20th dose

9 Pharmacokinetics Questions 4) Answer
Half life = 40hrs Dose admin rate = 24 hrly Drug reaches steady state in 5 half lives = 5x 40 = 200 hrs. Therefore, 200 hrs are reached after = / 24 = ~ 8th dose

10 Pharmacokinetics Questions
5. At 12 hr after the IV administration of the bolus dose, the plasma level of the drug is 3 mg/L If the Vd= 10L and the elimination half life= 6 hrs What is the dose administered? 120mg 180mg 240mg 480mg 600mg

11 Pharmacokinetics Questions 5) Answer
Half life = 6 hrs Vd = 10L Loading dose = Vd x Plasma conc at zero hour – immediately after IV Plasma conc after 12 hrs = 3 mg/L, half life = 6hrs ; Plasma conc at 6 hrs = 6 mg/L Plasma conc at zero hour = 12 mg/L Loading dose = 10L x 12mg/L = 120mg.

12 Pharmacokinetics Questions
6. Mr. John is admitted to the general hospital with pneumonia due to gram negative bacteria. The antibiotic Tobramycin was ordered. The CL and Vd of Tobramycin in Mr John are 80mL/min and 40L respectively. i).What is the maintenance dose that must be administered I.V at every 6 hrs to eventually obtain average steady state of 4mg/L? 100 mg 115 mg 175 mg 200 mg 250 mg

13 Pharmacokinetics Questions
6 ii).If you wish to give Mr. John a loading dose to achieve the therapeutic plasma concentration of 6mg/L, How much should be given? 100 mg 115 mg 175 mg 200 mg 240 mg

14 PK Questions 6 i). Steady state required of 4mg/L Vd = 40L
Cl = 80ml/ min CL = Rate of elimination Plasma concentration

15 PK Questions 6 i) Answer At steady state, Rate of elimination = Rate of infusion Rate of infusion = CL x CSS Rate of infusion = 80ml/min x 4 mg/L = L/min X 4mg/L = 0.32 mg/min = 0.32 X 60 mg/hr = 19.2mg/hr

16 PK Questions 6 i) Answer Rate of infusion = 19.2 mg /hr
Maintenance dose every 6 hr = 19.2 x 6 = gm

17 PK Questions 6 ii) Answer
6 ii). Loading dose = Vd x Plasma concentration at zero time Vd = 40L Therapeutic concentration required = 6mg/L Loading dose = 40 L x 6mg/L Loading dose = 240 mg

18 PK Questions 7. Despite your careful adherence to basic pharmacokinetic principles, your patient on digoxin therapy has developed digoxin toxicity. The plasma digoxin level is 4ng/L. Renal function is normal and the plasma half life is 1.6 days. How long should you withhold digoxin to reach a safe therapeutic plasma conc of 1ng/L? 1.6 days 3.2 days 2.4 days 4.8 days 9.6 days

19 PK Question 7) Answer Since the blood level drops by 50% during each half life (1.6 days) the plasma level will be 2 ng/L after 1.6 days and 1 ng/L after 3.2 days.

20 PK Questions 8. A 47-yr-old patient with myocardial infarction had severe cardiac arrhythmia. You have decided to give lidocaine to correct arrhythmia. A continuous infusion of lidocaine 1.92 mg/min is started at 8.A.M. The PK parameters of lidocaine are Vd = 77L, CL = 640 ml/min, half life = 1.8 hours The expected steady state plasma concentration is approximately 40 mg/L 3.0 mg/L 7.2 mg/L 8.46 mg/L 10.20 mg/L

21 PK Question 8) Answer Infusion rate = 1.92 mg/min Vd = 77L
CL = 640ml/min Half life = 1.8 hrs CL = Elimination rate Plasma conc At steady state, Infusion rate = Elimination rate

22 PK Question 8) Answer Infusion rate = CL x CSS Css = Infusion rate
CL

23 PK Question 8) Answer Css = 1.92 mg/min ------------------ 640 ml/min
Plasma concentration at steady state = mg 640 ml

24 PK Question 8) Answer Plasma conc = 1.92 mg ---------------------
Css = 3mg/L

25 PK Questions 9. A 56-yr-old patient of CAD requires an infusion of procainamide. Its half life is 2hrs. The infusion is begun at 9.00 a.m. At 1.00 p.m the same day, a blood sample is taken; the drug concentration is found to be 3 mg/L. What is the probable steady state concentration? 3 mg/L 4 mg/L 6 mg/L 10 mg/L 15 mg/L

26 PK Q 9) Answer A patient requires an infusion of procainamide. Its half life is 2hrs. The infusion is begun at 9.00 a.m and at 1.00 p.m the same day, a blood sample is taken; the drug concentration is found to be 3 mg/L. The plasma concentration after 4 hrs (i.e., after 2 half lives) is mg/L. The drug reaches 75% of the steady concentration after 2 half lives. The steady state concentration is 100 X 3 mg/ L / 75 = 4 mg /L

27 PK Qs 10. A young man is brought to the emergency room in a deep coma. His friends state that he self administered a large dose of morphine 6 hrs earlier. The immediate blood analysis in the hospital shows a morphine plasma level of 0.25mg/L. Assuming that the PK of morphine in this patient are Vd 200L and half life is 3 hrs, how much morphine did the patient inject 6h earlier? A.25 mg B. 50 mg. C. 100 mg. D. 200 mg E. Incomplete data

28 PK Question 10) Answer Large dose of morphine injected 6 hrs before. The immediate blood analysis shows a morphine plasma level of 0.25 mg/L ( i.e after 6 hrs.) Kinetics of morphine, Vd = 200L and half life = 3 hrs. Plasma concentration after 3 hrs could be = 0.50 mg/ L Plasma concentration at zero hour or immediately after injection of morphine = 1.00mg/L. Loading dose = Vd X plasma conc at zero hour Loading dose = 1.00 mg/L X 200 L = 200 mg

29 PK Q 11. The following are pharmacokinetic data for Drug X: Clearance, L/hr in a 70 kg adult; Effective plasma concentration, 5 mg/L; Oral availability 50% or Calculate the oral maintenance dosing rate for Drug X in a 70 kg person. A. 10 ug/hr B. 200 mg/hr C. 1 mg/hr D. 4 mg/hr E. 50 mg/hr

30 PK Q 11) Answer Clearance = 20 L/hr CL = Elimination rate
Plasma concentration Effective plasma concentration, 5 mg/L Oral availability 50% or 0.5 Rate of infusion (intravenous) = CL x Css Maintenance dose (oral) = CL X Css / F Maintenance dose = 20L/hr X 5 mg/L /0.5 Maintenance dose = 100 mg / 0.5 hr Maintenance dose = 200 mg/hr

31 Practice questions Q12. A pharmacologist is determining the PK parameters of a novel antibiotic in order to determine the proper dosage. The drug is a weak acid with a pKa of 5.0. Assuming a pH of 8.0 in the urine, approximately what percent of the drug will be in a form that can be rapidly excreted? 0.1 1 90 99 99.9

32 PHARMACOKINETICS

33 Practice questions Drug is a weakly acid pKa of acidic drug is 5.0
pH of the surroundings 8.0 in the urine pH-pKa = 3 { ionized} 10 pH-pKa = for an Acidic drug { non-ionized } { ionized } = for an Acidic drug { non-ionized } 1000 is ionized and 1 is non-ionized; in % 99.9% is ionized and water soluble and excreted in urine.


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