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Lecture 223/19/07. Displacement reactions Some metals react with acids to produce salts and H 2 gas Balance the following displacement reaction: Zn (s)

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Presentation on theme: "Lecture 223/19/07. Displacement reactions Some metals react with acids to produce salts and H 2 gas Balance the following displacement reaction: Zn (s)"— Presentation transcript:

1 Lecture 223/19/07

2 Displacement reactions Some metals react with acids to produce salts and H 2 gas Balance the following displacement reaction: Zn (s) + HBr (aq)  ZnBr 2 (aq) + H 2 (g)

3 voltaic or galvanic cell electrolytic cell Electrochemical cells

4 Requires Electrodes Salt bridge External circuit

5 Anode: Cathode: Net reaction: Electrochemical cell notation:

6 Electromotive force (emf) Cell potential Cell voltage

7 All other potentials determined from the SHE Zn (s)  Zn 2+ (aq, 1 M) + 2e - E° ox = ? 2 H 3 O + (aq, 1 M) + 2e -  H 2 (g, 1 atm) + 2 H 2 O E° red = 0 V__ Zn (s) + 2 H 3 O +  Zn 2+ + H 2 + 2 H 2 O E° cell = +0.76 V

8 For any reaction: E° ox = - E° red

9 Standard Reduction Potentials (25° C) E° F 2 (g) + 2e - ↔ 2F - +2.87 Au 3+ + 3e - ↔ Au (s)+1.50 Cl 2 (g) + 2e- ↔ 2 Cl - +1.36 O 2 (g) + 4 H + + 4e - ↔ 2 H 2 O+1.23 Hg 2+ + 2e - ↔ Hg (l)+0.85 Ag + + e - ↔ Ag (s)+0.80 Fe 3+ + e - ↔ Fe 2+ +0.77 Cu 2+ + 2 e - ↔ Cu (s)+0.34 Sn 4+ + 2e - ↔ Sn 2+ +0.15 2H + + 2 e - ↔ H 2 (g) 0.00 Pb 2+ + 2e - ↔ Pb (s)-0.13 Sn 2+ + 2e - ↔ Sn (s)-0.14 Ni 2+ + 2e - ↔ Ni (s)-0.26 Zn 2+ + 2 e - ↔ Zn (s)-0.76 Cr 2+ + 2 e - ↔ Cr (s)-0.91 Mg 2+ + 2 e - ↔ Mg (s)-2.37 Na + + e - ↔ Na (s)-2.71 Ca 2+ + 2 e - ↔ Ca (s)-2.87 Li + + e - ↔ Li (s)- 3.04

10

11 Examples: What are the reactions for: F 2 and Cl - F 2 and Cl 2 F - and Cl 2 F - and Cl - Need to consider 2 questions: 1)Are both reduction and oxidation reactions possible? 2)Does the reduction reaction have a higher reduction potential than the oxidation reaction?

12 E° F 2 (g) + 2e - ↔ 2F - +2.87 Au 3+ + 3e - ↔ Au (s)+1.50 O 2 (g) + 4 H + + 4e - ↔ 2 H 2 O+1.23 Br 2 (l) + 2e - ↔ 2Br - +1.07 Ag + + e - ↔ Ag (s)+0.80 Fe 3+ + e - ↔ Fe 2+ +0.77 I 2 + 2e - ↔ 2 I - +0.54 O 2 (g) + 2 H 2 O + 4e - ↔ 4 OH - +0.40 Cu 2+ + 2e - ↔ Cu (s)+0.34 2H + + 2e - ↔ H 2 (g) 0.00 Pb 2+ + 2e - ↔ Pb (s)-0.13 Ni 2+ + 2e - ↔ Ni (s)-0.26 Fe 2+ + 2e - ↔ Fe (s)-0.45 Ag 2 S + 2e - ↔ 2 Ag (s) + S -2 -0.69 Zn 2+ + 2e - ↔ Zn (s)-0.76 Al 3+ + 3e - ↔ Al (s)-1.66

13 Four metals A, B, C, and D exhibit the following properties Only A and C react with 1.0 M HCl to give H 2 (g) When C is added to solutions of the ions of the other metals, metallic B, D, and A are formed Metal D reduces B n+ to give metallic B and D n+. Based on the information above, arrange the 4 metals in order of increasing ability to act as reducing agents.


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